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# NCERT Solutions for Class 6 Maths Exercise 3.3

NCERT solutions for Maths Playing with numbers

## NCERT Solutions for Class 6 Maths Playing with numbers

###### Question 1.Using divisibility test, determine which of the following numbers are divisible by 2; by 3; by 4; by 5; by 6; by 8; by 9; by 10; by 11. (say yes or no)
 Number Divisible by 1289901586275668663921042971428563060406839 Yes No Yes No No Yes No No No

 Number Divisible by 2 3 4 5 6 8 9 10 11 1289901586275668663921042971428563060406839 YesYesYesNoYesYesYesYesYesNo NoYesNoNoNoYesYesYesYesYes YesNoNoNoNoNoNoYesYesNo NoYesNoYesNoYesNoNoYesNo NoYesNoNoNoYesYesYesYesNo YesNoNoNoNoNoNoYesNoNo NoYesNoNoNoNoYesNoYesNo NoYesNoNoNoYesNoNoYesNo NoYesNoYesNoYesNoNoNoNo

NCERT Solutions for Class 6 Maths Exercise 3.3

###### Question 2.Using divisibility test, determine which of the following numbers are divisibly by 4; by 8:

(a) 572, (b) 726352, (c) 5500, (d) 6000, (e) 12159, (f) 14560, (g) 21084, (h) 31795072, (i) 1700, (j) 2150

(a) 572 {tex} \to {/tex} Divisible by 4 as its last two digits are divisible by 4.

{tex} \to {/tex} Not divisible by 8 as its last three digits are not divisible by 8.

(b) 726352 {tex} \to {/tex} Divisible by 4 as its last two digits are divisible by 4.

{tex} \to {/tex} Divisible by 8 as its last three digits are divisible by 8.

(c) 5500 {tex} \to {/tex} Divisible by 4 as its last two digits are divisible by 4.

{tex} \to {/tex} Not divisible by 8 as its last three digits are not divisible by 8.

(d) 6000 {tex} \to {/tex} Divisible by 4 as its last two digits are 0.

{tex} \to {/tex} Divisible by 8 as its last three digits are 0.

(e) 12159 {tex} \to {/tex} Not divisible by 4 and 8 as it is an odd number.

(f) 14560 {tex} \to {/tex} Divisible by 4 as its last two digits are divisible by 4.

{tex} \to {/tex} Divisible by 8 as its last three digits are divisible by 8.

(g) 21084 {tex} \to {/tex} Divisible by 4 as its last two digits are divisible by 4.

{tex} \to {/tex} Not divisible by 8 as its last three digits are not divisible by 8.

(h) 31795072 {tex} \to {/tex} Divisible by 4 as its last two digits are divisible by 4.

{tex} \to {/tex} Divisible by 8 as its last three digits are divisible by 8.

(i) 1700 {tex} \to {/tex} Divisible by 4 as its last two digits are 0.

{tex} \to {/tex} Not divisible by 8 as its last three digits are not divisible by 8.

(j) 5500 {tex} \to {/tex} Not divisible by 4 as its last two digits are not divisible by 4.

{tex} \to {/tex} Not divisible by 8 as its last three digits are not divisible by 8.

###### Question 3.Using divisibility test, determine which of the following numbers are divisible by 6:

(a)297144, (b) 1258, (c) 4335, (d) 61233, (e) 901352, (f) 438750, (g) 1790184, (h) 12583, (i) 639210, (j) 17852

(a) 297144 {tex} \to {/tex} Divisible by 2 as its units place is an even number.

{tex} \to {/tex} Divisible by 3 as sum of its digits (= 27) is divisible by 3.

Since the number is divisible by both 2 and 3, therefore, it is also divisible by 6.

(b) 1258 {tex} \to {/tex} Divisible by 2 as its units place is an even number.

{tex} \to {/tex} Not divisible by 3 as sum of its digits (= 16) is not divisible by 3.

Since the number is not divisible by both 2 and 3, therefore, it is not divisible by 6.

(c) 4335 {tex} \to {/tex} Not divisible by 2 as its units place is not an even number.

{tex} \to {/tex} Divisible by 3 as sum of its digits (= 15) is divisible by 3.

Since the number is not divisible by both 2 and 3, therefore, it is not divisible by 6.

(d) 61233 {tex} \to {/tex} Not divisible by 2 as its units place is not an even number.

{tex} \to {/tex} Divisible by 3 as sum of its digits (= 15) is divisible by 3.

Since the number is not divisible by both 2 and 3, therefore, it is not divisible by 6.

(e) 901352 {tex} \to {/tex} Divisible by 2 as its units place is an even number.

{tex} \to {/tex} Not divisible by 3 as sum of its digits (= 20) is not divisible by 3.

Since the number is not divisible by both 2 and 3, therefore, it is not divisible by 6.

(f) 438750 {tex} \to {/tex} Divisible by 2 as its units place is an even number.

{tex} \to {/tex} Divisible by 3 as sum of its digits (= 27) is not divisible by 3.

Since the number is divisible by both 2 and 3, therefore, it is divisible by 6.

(g) 1790184 {tex} \to {/tex} Divisible by 2 as its units place is an even number.

{tex} \to {/tex} Divisible by 3 as sum of its digits (= 30) is not divisible by 3.

Since the number is divisible by both 2 and 3, therefore, it is divisible by 6.

(h) 12583 {tex} \to {/tex} Not divisible by 2 as its units place is not an even number.

{tex} \to {/tex} Not divisible by 3 as sum of its digits (= 19) is not divisible by 3.

Since the number is not divisible by both 2 and 3, therefore, it is not divisible by 6.

(i) 639210 {tex} \to {/tex} Divisible by 2 as its units place is an even number.

{tex} \to {/tex} Divisible by 3 as sum of its digits (= 21) is not divisible by 3.

Since the number is divisible by both 2 and 3, therefore, it is divisible by 6.

(j) 17852 {tex} \to {/tex} Divisible by 2 as its units place is an even number.

{tex} \to {/tex} Not divisible by 3 as sum of its digits (= 23) is not divisible by 3.

Since the number is not divisible by both 2 and 3, therefore, it is not divisible by 6.

NCERT Solutions for Class 6 Maths Exercise 3.3

###### Question 4.Using divisibility test, determine which of the following numbers are divisible by 11:

(a) 5445, (b) 10824, (c) 7138965, (d) 70169308, (e) 10000001 , (f) 901153

Answer: (a) 5445 {tex} \to {/tex} Sum of the digits at odd places = 4 + 5 = 9

{tex} \to {/tex} Sum of the digits at even places = 4 + 5 = 9

{tex} \to {/tex} Difference of both sums = 9 – 9 = 0

Since the difference is 0, therefore, the number is divisible by 11.

(b) 10824 {tex} \to {/tex} Sum of the digits at odd places = 4 + 8 +1 = 13

{tex} \to {/tex} Sum of the digits at even places = 2 + 0 = 2

{tex} \to {/tex} Difference of both sums = 13 – 2 = 11

Since the difference is 11, therefore, the number is divisible by 11.

(c) 7138965 {tex} \to {/tex} Sum of the digits at odd places = 5 + 9 + 3 + 7 = 24

{tex} \to {/tex} Sum of the digits at even places = 6 + 8 + 1 = 15

{tex} \to {/tex} Difference of both sums = 24 – 15 = 9

Since the difference is neither 0 nor 11, therefore, the number is not divisible by 11.

(d) 70169308 {tex} \to {/tex} Sum of the digits at odd places = 8 + 3 + 6 + 0 = 17

{tex} \to {/tex} Sum of the digits at even places = 0 + 9 + 1 + 7 = 17

{tex} \to {/tex} Difference of both sums = 17 – 17 = 0

Since the difference is 0, therefore, the number is divisible by 11.

(e) 10000001 {tex} \to {/tex} Sum of the digits at odd places = 1 + 0 + 0 + 0 = 1

{tex} \to {/tex} Sum of the digits at even places = 0 + 0 + 0 + 1 = 1

{tex} \to {/tex} Difference of both sums = 1 – 1 = 0

Since the difference is 0, therefore, the number is divisible by 11.

(f) 901153 {tex} \to {/tex} Sum of the digits at odd places = 3 + 1 + 0 = 4

{tex} \to {/tex} Sum of the digits at even places = 5 + 1 + 9 = 15

{tex} \to {/tex} Difference of both sums = 15 – 4 = 11

Since the difference is 11, therefore, the number is divisible by 11.

###### Question 5.Write the smallest digit and the largest digit in the blanks space of each of the following numbers so that the number formed is divisibly by 3:

(a) __________ 6724

(b) 4765 __________ 2

(a) We know that a number is divisible by 3 if the sum of all digits is divisible by 3.

Therefore, Smallest digit : 2 {tex} \to {/tex} 26724 = 2 + 6 + 7 + 2 + 4 = 21

Largest digit : 8 {tex} \to {/tex} 86724 = 8 + 6 + 7 + 2 + 4 = 27

(b) We know that a number is divisible by 3 if the sum of all digits is divisible by 3.

Therefore, Smallest digit : 0 {tex} \to {/tex} 476502 = 4 + 7 + 6 + 5 + 0 + 2 = 24

Largest digit : 9 {tex} \to {/tex} 476592 = 4 + 7 + 6 + 5 + 0 + 2 = 33

NCERT Solutions for Class 6 Maths Exercise 3.3

###### Question 6.Write the smallest digit and the largest digit in the blanks space of each of the following numbers so that the number formed is divisibly by 11:

(a) 92 __________ 389

(b) 8 __________ 9484

Answer: (a) We know that a number is divisible by 11 if the difference of the sum of the digits at odd

places and that of even places should be either 0 or 11.

Therefore, 928389 {tex} \to {/tex} Odd places = 9 + 8 + 8 = 25

Even places = 2 + 3 + 9 = 14

Difference = 25 – 14 = 11

(b) We know that a number is divisible by 11 if the difference of the sum of the digits at odd

places and that of even places should be either 0 or 11.

Therefore, 869484 {tex} \to {/tex} Odd places = 8 + 9 + 8 = 25

Even places = 6 + 4 + 4 = 14

Difference = 25 – 14 = 11

## NCERT Solutions for Class 6 Maths Exercise 3.3

NCERT Solutions Class 6 Maths PDF (Download) Free from myCBSEguide app and myCBSEguide website. Ncert solution class 6 Maths includes text book solutions from Class 6 Maths Book . NCERT Solutions for CBSE Class 6 Maths have total 14 chapters. 6 Maths NCERT Solutions in PDF for free Download on our website. Ncert Maths class 6 solutions PDF and Maths ncert class 6 PDF solutions with latest modifications and as per the latest CBSE syllabus are only available in myCBSEguide.

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### 6 thoughts on “NCERT Solutions for Class 6 Maths Exercise 3.3”

1. Plz give answer of smallest digit and the largest digit which is divisible by 3

2. Plz give answer of smallest and largest digit which is divisible by 3

3. Plz give answer of largest and the smallest digit which is divisible by 3

4. Really helped for me vey nice clear concepts

5. chaman sah sarawsti vidya mandir ???maths and science ka halp Karna ka Lisa thankyou ??

6. This is very fantasty service.
Thanks for all