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# NCERT Solutions for Class 6 Maths Exercise 7.2

NCERT solutions for Maths Fractions ## NCERT Solutions for Class 6 Maths Fractions

###### Question 1.Draw number lines and locate the points on them:

(a){tex}\frac{1}{2},\frac{1}{4},\frac{3}{4},\frac{4}{4}{/tex}

(b){tex}\frac{1}{8},\frac{2}{8},\frac{3}{8},\frac{7}{8}{/tex}

(c){tex}\frac{2}{5},\frac{3}{5},\frac{8}{5},\frac{4}{5}{/tex} NCERT Solutions for Class 6 Maths Exercise 7.2

###### Question 2.Express the following fractions as mixed fractions:

(a){tex}\frac{{20}}{3}{/tex}

(b){tex}\frac{{11}}{5}{/tex}

(c){tex}\frac{{17}}{7}{/tex}

(d){tex}\frac{{28}}{5}{/tex}

(e){tex}\frac{{19}}{6}{/tex}

(f){tex}\frac{{35}}{9}{/tex}

(a)

3{tex}\mathop{\left){\vphantom{1\begin{gathered}

{\text{ }}20 \\\\\\

\underline { – 18} \\\\\\

\underline {{\text{ 2}}} \\\\\\

\end{gathered} }}\right.

\!\!\!\!\overline{\,\,\,\vphantom 1{\begin{gathered}

{\text{ }}20 \\\\\\

\underline { – 18} \\\\\\

\underline {{\text{ 2}}} \\\\\\

\end{gathered} }}}

\limits^{\displaystyle\,\,\, 6}{/tex}

(b)

5{tex}\mathop{\left){\vphantom{1\begin{gathered}

{\text{ 11}} \\\\\\

\underline { – 10} \\\\\\

\underline {{\text{ 1}}} \\\\\\

\end{gathered} }}\right.

\!\!\!\!\overline{\,\,\,\vphantom 1{\begin{gathered}

{\text{ 11}} \\\\\\

\underline { – 10} \\\\\\

\underline {{\text{ 1}}} \\\\\\

\end{gathered} }}}

\limits^{\displaystyle\,\,\, 2}{/tex}

{tex}\therefore {/tex}{tex}\frac{{20}}{3} = 6\frac{2}{3}{/tex}

{tex}\therefore {/tex}{tex}\frac{{11}}{5} = 2\frac{1}{5}{/tex}

(c)

7{tex}\mathop{\left){\vphantom{1\begin{gathered}

{\text{ 17}} \\\\\\

\underline { – 14} \\\\\\

\underline {{\text{ 3}}} \\\\\\

\end{gathered} }}\right.

\!\!\!\!\overline{\,\,\,\vphantom 1{\begin{gathered}

{\text{ 17}} \\\\\\

\underline { – 14} \\\\\\

\underline {{\text{ 3}}} \\\\\\

\end{gathered} }}}

\limits^{\displaystyle\,\,\, 2}{/tex}

(d)

5{tex}\mathop{\left){\vphantom{1\begin{gathered}

{\text{ 28}} \\\\\\

\underline { – 25} \\\\\\

\underline {{\text{ 3}}} \\\\\\

\end{gathered} }}\right.

\!\!\!\!\overline{\,\,\,\vphantom 1{\begin{gathered}

{\text{ 28}} \\\\\\

\underline { – 25} \\\\\\

\underline {{\text{ 3}}} \\\\\\

\end{gathered} }}}

\limits^{\displaystyle\,\,\, 5}{/tex}

{tex}\therefore {/tex}{tex}\frac{{17}}{7} = 2\frac{3}{7}{/tex}

{tex}\therefore {/tex}{tex}\frac{{28}}{5} = 5\frac{3}{5}{/tex}

(e)

6{tex}\mathop{\left){\vphantom{1\begin{gathered}

{\text{ 19}} \\\\\\

\underline { – 18} \\\\\\

\underline {{\text{ 1}}} \\\\\\

\end{gathered} }}\right.

\!\!\!\!\overline{\,\,\,\vphantom 1{\begin{gathered}

{\text{ 19}} \\\\\\

\underline { – 18} \\\\\\

\underline {{\text{ 1}}} \\\\\\

\end{gathered} }}}

\limits^{\displaystyle\,\,\, 3}{/tex}

(f)

9{tex}\mathop{\left){\vphantom{1\begin{gathered}

{\text{ 35}} \\\\\\

\underline { – 27} \\\\\\

\underline {{\text{ 8}}} \\\\\\

\end{gathered} }}\right.

\!\!\!\!\overline{\,\,\,\vphantom 1{\begin{gathered}

{\text{ 35}} \\\\\\

\underline { – 27} \\\\\\

\underline {{\text{ 8}}} \\\\\\

\end{gathered} }}}

\limits^{\displaystyle\,\,\, 3}{/tex}

{tex}\therefore {/tex}{tex}\frac{{19}}{6} = 3\frac{1}{6}{/tex}

{tex}\therefore {/tex}{tex}\frac{{35}}{9} = 3\frac{8}{9}{/tex}

NCERT Solutions for Class 6 Maths Exercise 7.2

###### Question 3.Express the following as improper fractions:

(a){tex}7\frac{3}{4}{/tex}

(b){tex}5\frac{6}{7}{/tex}

(c){tex}2\frac{5}{6}{/tex}

(d){tex}10\frac{3}{5}{/tex}

(e){tex}9\frac{3}{7}{/tex}

(f){tex}8\frac{4}{9}{/tex}

(a){tex}7\frac{3}{4} = \frac{{\left( {7 \times 4} \right) + 3}}{4} = \frac{{28 + 3}}{4} = \frac{{31}}{4}{/tex}

(b){tex}5\frac{6}{7} = \frac{{\left( {5 \times 7} \right) + 6}}{7} = \frac{{35 + 6}}{7} = \frac{{41}}{7}{/tex}

(c){tex}2\frac{5}{6} = \frac{{\left( {2 \times 6} \right) + 5}}{6} = \frac{{12 + 5}}{6} = \frac{{17}}{6}{/tex}

(d){tex}10\frac{3}{5} = \frac{{\left( {10 \times 5} \right) + 3}}{5} = \frac{{50 + 3}}{5} = \frac{{53}}{5}{/tex}

(e){tex}9\frac{3}{7} = \frac{{\left( {9 \times 7} \right) + 3}}{7} = \frac{{63 + 3}}{7} = \frac{{66}}{7}{/tex}

(f){tex}8\frac{4}{9} = \frac{{\left( {8 \times 9} \right) + 4}}{9} = \frac{{72 + 4}}{9} = \frac{{76}}{9}{/tex}

## NCERT Solutions for Class 6 Maths Exercise 7.2

NCERT Solutions Class 6 Maths PDF (Download) Free from myCBSEguide app and myCBSEguide website. Ncert solution class 6 Maths includes text book solutions from Class 6 Maths Book . NCERT Solutions for CBSE Class 6 Maths have total 14 chapters. 6 Maths NCERT Solutions in PDF for free Download on our website. Ncert Maths class 6 solutions PDF and Maths ncert class 6 PDF solutions with latest modifications and as per the latest CBSE syllabus are only available in myCBSEguide.

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