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NCERT Solutions for Class 6 Maths Exercise 7.3

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NCERT Solutions for Class 6 Maths Exercise 7.3 book solutions are available in PDF format for free download. These ncert book chapter wise questions and answers are very helpful for CBSE exam. CBSE recommends NCERT books and most of the questions in CBSE exam are asked from NCERT text books. Class 6 Maths chapter wise NCERT solution for Maths Book all the chapters can be downloaded from our website and myCBSEguide mobile app for free.

NCERT solutions for Maths Fractions Download as PDF

NCERT Solutions for Class 6 Maths Exercise 7.3

NCERT Solutions for Class 6 Maths Fractions

Class –VI Mathematics
(Ex. 7.3)
Question 1.Write the fractions. Are all these fractions equivalent:




(a) {tex}\frac{1}{2},\frac{2}{4},\frac{3}{6},\frac{4}{8}{/tex}

Yes, all of these fractions are equivalent.

(b) {tex}\frac{4}{12},\frac{3}{9},\frac{2}{6},\frac{1}{3},\frac{6}{15}{/tex}

No, these fractions are not equivalent.

Question 2.Write the fraction and pair up the equivalent fractions to each row:



(ii) {tex}\frac{4}{8}=\frac{1}{2}{/tex}

(b) {tex}\frac{4}{6}=\frac{2}{3}{/tex}

(iv) {tex}\frac{8}{12}=\frac{2}{3}{/tex}

(c) {tex}\frac{3}{9}=\frac{1}{3}{/tex}

(i) {tex}\frac{6}{18}=\frac{1}{3}{/tex}

(d) {tex}\frac{2}{8}=\frac{1}{4}{/tex}

(v) {tex}\frac{4}{16}=\frac{1}{4}{/tex}

(e) {tex}\frac{3}{4}{/tex}

(iii) {tex}\frac{12}{16}=\frac{3}{4}{/tex}

NCERT Solutions for Class 6 Maths Exercise 7.3

Question 3.Replace {tex}\boxed{\,\,\,\,\,}{/tex} in each of the following by the correct number:

(a) {tex}\frac{2}{7} = \frac{8}{{\boxed{{\text{ }}}}}{/tex}

(b) {tex}\frac{5}{8} = \frac{{10}}{{\boxed{{\text{ }}}}}{/tex}

(c) {tex}\frac{3}{5} = \frac{{\boxed{{\text{ }}}}}{{20}}{/tex}

(d) {tex}\frac{{45}}{{60}} = \frac{{15}}{{\boxed{{\text{ }}}}}{/tex}

(e) {tex}\frac{{18}}{{24}} = \frac{{\boxed{{\text{ }}}}}{4}{/tex}


(a) {tex}\frac{2}{7} = \frac{{2 \times 4}}{{7 \times 4}} = \frac{8}{{\boxed{28}}}{/tex}

(b) {tex}\frac{5}{8} = \frac{{5 \times 2}}{{8 \times 2}} = \frac{{10}}{{\boxed{16}}}{/tex}

(c) {tex}\frac{3}{5} = \frac{{3 \times 4}}{{5 \times 4}} = \frac{{\boxed{12}}}{{20}}{/tex}

(d) {tex}\frac{{45}}{{60}} = \frac{{45 \div 3}}{{60 \div 3}} = \frac{{15}}{{\boxed{20}}}{/tex}

(e) {tex}\frac{{18}}{{24}} = \frac{{18 \div 6}}{{24 \div 6}} = \frac{{\boxed3}}{4}{/tex}

Question 4.Find the equivalent fraction of {tex}\frac{3}{5}{/tex} having:

(a) denominator 20

(b) numerator 9

(c) denominator 30

(d) numerator 27


(a) {tex}\frac{3}{5} = \frac{{3 \times 4}}{{5 \times 4}} = \frac{{12}}{{20}}{/tex}

(b) {tex}\frac{3}{5} = \frac{{3 \times 3}}{{5 \times 3}} = \frac{9}{{15}}{/tex}

(c) {tex}\frac{3}{5} = \frac{{3 \times 6}}{{5 \times 6}} = \frac{{18}}{{30}}{/tex}

(d) {tex}\frac{3}{5} = \frac{{3 \times 9}}{{5 \times 9}} = \frac{{27}}{{45}}{/tex}

NCERT Solutions for Class 6 Maths Exercise 7.3

Question 5.Find the equivalent fraction of {tex}\frac{{36}}{{48}}{/tex} with:

(a) numerator 9

(b) denominator 4


(a) {tex}\frac{{36}}{{48}} = \frac{{36 \div 4}}{{48 \div 4}} = \frac{9}{{12}}{/tex}

(b) {tex}\frac{{36}}{{48}} = \frac{{36 \div 12}}{{48 \div 12}} = \frac{3}{4}{/tex}

Question 6.Check whether the given fraction are equivalent:

(a) {tex}\frac{5}{9},\frac{{30}}{{54}}{/tex}

(b) {tex}\frac{3}{{10}},\frac{{12}}{{50}}{/tex}



(a) {tex}\frac{5}{9},\frac{{30}}{{54}}{/tex} = {tex}\frac{{5 \times 6}}{{9 \times 6}},\frac{{30}}{{54}}{/tex} = {tex}\frac{{30}}{{54}},\frac{{30}}{{54}}{/tex}

Therefore, {tex}\frac{5}{9},\frac{{30}}{{54}}{/tex} are equivalent.

(b) {tex}\frac{3}{{10}},\frac{{12}}{{50}}{/tex} = {tex}\frac{{3 \times 5}}{{10 \times 5}},\frac{{12}}{{50}}{/tex} = {tex}\frac{{15}}{{50}},\frac{{12}}{{50}}{/tex}

Therefore, {tex}\frac{3}{{10}},\frac{{12}}{{50}}{/tex} are not equivalent.

(c) {tex}\frac{7}{{13}},\frac{5}{{11}}{/tex} = {tex}\frac{{7 \times 11}}{{13 \times 11}},\frac{{5 \times 13}}{{11 \times 13}}{/tex} = {tex}\frac{{77}}{{143}},\frac{{65}}{{143}}{/tex}

Therefore, {tex}\frac{7}{{13}},\frac{5}{{11}}{/tex} are not equivalent fraction.

NCERT Solutions for Class 6 Maths Exercise 7.3

Question 7.Reduce the following fractions to simplest form:

(a) {tex}\frac{{48}}{{60}}{/tex}

(b) {tex}\frac{{150}}{{60}}{/tex}

(c) {tex}\frac{{84}}{{98}}{/tex}

(d) {tex}\frac{{12}}{{52}}{/tex}

(e) {tex}\frac{7}{{28}}{/tex}


(a) {tex}\frac{48}{60}=\frac{2\times 2\times 2\times 2\times 3}{2\times 2\times 3\times 5}=\frac{4}{5}{/tex}

(b) {tex}\frac{150}{60}=\frac{3\times 5\times 10}{2\times 3\times 10}=\frac{5}{2}{/tex}

(c) {tex}\frac{84}{98}=\frac{2\times 3\times 14}{7\times 14}=\frac{6}{7}{/tex}

(d) {tex}\frac{12}{52}=\frac{2\times 2\times 3}{2\times 2\times 13}=\frac{3}{13}{/tex}

(e) {tex}\frac{7}{28}=\frac{7}{2\times 2\times 7}=\frac{1}{4}{/tex}

Question 8.Ramesh had 20 pencils, Sheelu had 50 pencils and Jamaal had 80 pencils. After 4 months, Ramesh used up 10 pencils, Sheelu used up 25 pencils and Jamaal used up 40 pencils. What fraction did each use up? Check is each has used up an equal fraction of her/his pencils?


Ramesh: Total pencils = 20

Pencils used = 10

Fraction = {tex}\frac{10}{20}=\frac{1}{2}{/tex}

Sheelu: Total pencils = 50

Pencils used = 25

Fraction = {tex}\frac{25}{50}=\frac{1}{2}{/tex}

Jamaal: Total pencils = 80

Pencils used = 40

Fraction = {tex}\frac{40}{80}=\frac{1}{2}{/tex}

Since, all of them used half of their pencils, therefore each one used up equal fraction of pencils.

NCERT Solutions for Class 6 Maths Exercise 7.3

Question 9. Match the equivalent fractions and write two more for each:
(i){tex}\frac{{250}}{{400}}{/tex}(a) {tex}\frac{2}{3}{/tex}
(ii){tex}\frac{{180}}{{200}}{/tex}(b) {tex}\frac{2}{5}{/tex}
(iii){tex}\frac{{660}}{{990}}{/tex}(c) {tex}\frac{1}{2}{/tex}
(iv){tex}\frac{{180}}{{360}}{/tex}(d) {tex}\frac{5}{8}{/tex}
(v){tex}\frac{{220}}{{550}}{/tex}(e) {tex}\frac{9}{{10}}{/tex}


(i) {tex}\frac{250}{400}=\frac{5}{8},\frac{10}{16},\frac{15}{24}{/tex}

(d) {tex}\frac{5}{8}{/tex}

(ii) {tex}\frac{180}{200}=\frac{9}{10},\frac{18}{20},\frac{27}{30}{/tex}

(e) {tex}\frac{9}{10}{/tex}

(iii) {tex}\frac{660}{990}=\frac{2}{3},\frac{4}{6},\frac{6}{9}{/tex}

(a) {tex}\frac{2}{3}{/tex}

(iv) {tex}\frac{180}{360}=\frac{1}{2},\frac{2}{4},\frac{3}{6}{/tex}


  1. {tex}\frac{220}{550}=\frac{2}{5},\frac{4}{10},\frac{6}{15}{/tex}

(b) {tex}\frac{2}{5}{/tex}

NCERT Solutions for Class 6 Maths Exercise 7.3

NCERT Solutions Class 6 Maths PDF (Download) Free from myCBSEguide app and myCBSEguide website. Ncert solution class 6 Maths includes text book solutions from Class 6 Maths Book . NCERT Solutions for CBSE Class 6 Maths have total 14 chapters. 6 Maths NCERT Solutions in PDF for free Download on our website. Ncert Maths class 6 solutions PDF and Maths ncert class 6 PDF solutions with latest modifications and as per the latest CBSE syllabus are only available in myCBSEguide.

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