# NCERT Solutions for Class 6 Maths Exercise 10.3

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NCERT solutions for Maths Mensuration

## NCERT Solutions for Class 6 Maths Mensuration

###### Question 1.Find the areas of the rectangles whose sides are:

(a) 3 cm and 4 cm

(b) 12 m and 21 m

(c) 2 km and 3 km

(d) 2 m and 70 cm

(a) Area of rectangle = length x breadth

= 3 cm x 4 cm = 12 cm2

(b) Area of rectangle = length x breadth

= 12 m x 21 m = 252 m2

(c) Area of rectangle = length x breadth

= 2 km x 3 km = 6 km2

(d) Area of rectangle = length x breadth

= 2 m x 70 cm = 2 m x 0.7 m = 1.4 m2

###### Question 2.Find the areas of the squares whose sides are:

(a) 10 cm

(b) 14 cm

(c) 5 cm

(a) Area of square = side x side = 10 cm x 10 cm = 100 cm2

(b) Area of square = side x side = 14 cm x 14 cm = 196 cm2

(c) Area of square = side x side = 5 m x 5 m = 25 m2

###### Question 3.The length and the breadth of three rectangles are as given below:

(a) 9 m and 6 m

(b) 17 m and 3 m

(c) 4 m and 14 m

Which one has the largest area and which one has the smallest?

(a) Area of rectangle = length x breadth = 9 m x 6 m = 54 m2

(b) Area of rectangle = length x breadth= 3 m x 17 m = 51 m2

(c) Area of rectangle = length x breadth= 4 m x 14 m = 56 m2

Thus, the rectangle (c) has largest area, i.e. 56 m2 and rectangle (b) has smallest area, i.e., 56 m2.

NCERT Solutions for Class 6 Maths Exercise 10.3

###### Question 4.The area of a rectangle garden 50 m long is 300 m2, find the width of the garden.

Length of rectangle = 50 m and Area of rectangle = 300 m2

Since, Area of rectangle = length x breadth

Therefore, Breadth = {tex}\frac{{{\text{Area of rectangle}}}}{{{\text{Length}}}}{/tex} = = 6 m

Thus, the breadth of the garden is 6 m.

###### Question 5.What is the cost of tilling a rectangular plot of land 500 m long and 200 m wide at the rate of Rs. 8 per hundred sq. m?

Length of land = 500 m and Breadth of land = 200 m

Area of land = length x breadth = 500 m x 200 m = 1,00,000 m2

{tex}\because {/tex} Cost of tilling 100 sq. m of land = Rs. 8

{tex}\therefore {/tex} Cost of tilling 1,00,000 sq. m of land = = Rs. 8000

NCERT Solutions for Class 6 Maths Exercise 10.3

###### Question 6.A table-top measures 2 m by 1 m 50 cm. What is its area in square meters?

Answer: Length of table = 2 m and breadth of table = 1 m 50 cm = 1.50 m

Area of table = length x breadth

= 2 m x 1.50 m = 3 m2

###### Question 7.A room us 4 m long and 3 m 50 cm wide. How many square meters of carpet is needed to cover the floor of the room?

Answer: Length of room = 4 m and breadth of room = 3 m 50 cm = 3.50 m

Area of carpet = length x breadth

= 4 x 3.50 = 14m2

NCERT Solutions for Class 6 Maths Exercise 10.3

###### Question 8.A floor is 5 m long and 4 m wide. A square carpet of sides 3 m is laid on the floor. Find the area of the floor that is not carpeted.

Answer: Length of floor = 5 m and breadth of floor = 4 m

Area of floor = length x breadth

= 5 m x 4 m = 20 m2

Now, Side of square carpet = 3 m

Area of square carpet = side x side = 3 x 3 = 9 m2

Area of floor that is not carpeted = 20 m2 – 9 m2 = 11 m2

###### Question 9.Five square flower beds each of sides 1 m are dug on a piece of land 5 m long and 4 m wide. What is the area of the remaining part of the land?

Answer: Side of square bed = 1 m

Area of square bed = side x side = 1 m x 1 m = 1 m2

{tex}\therefore {/tex} Area of 5 square beds = 1 x 5 = 5 m2

Now, Length of land = 5 m and breadth of land = 4 m

{tex}\therefore {/tex} Area of land = length x breadth = 5 m x 4 m = 20 m2

Area of remaining part = Area of land – Area of 5 flower beds

= 20 m2 – 5 m2 = 15 m2

NCERT Solutions for Class 6 Maths Exercise 10.3

###### Question 10.By splitting the following figures into rectangles, find their areas. (The measures are given in centimeters)

(a) Area of HKLM = 3 x 3 = 9 cm2

Area of IJGH = 1 x 2 = 2 cm2

Area of FEDG = 3 x 3 = 9 cm2

Area of ABCD = 2 x 4 = 8 cm2

Total area of the figure = 9 + 2 + 9 + 8 = 28 cm2

(b) Area of ABCD = 3 x 1 = 3 cm2

Area of BDEF = 3 x 1 = 3 cm2

Area of FGHI = 3 x 1 = 3 cm2

Total area of the figure = 3 + 3 + 3 = 9 cm2

###### Question 11.Split the following shapes into rectangles and find their areas. (The measures are given in centimeters)

(a) Area of rectangle ABCD = 2 x 10 = 20 cm2

Area of rectangle DEFG = 10 x 2 = 20 cm2

Total area of the figure = 20 + 20 = 40 cm2

(b) There are 5 squares each of side 7 cm.

Area of one square = 7 x 7 = 49 cm2

Area of 5 squares = 49 x 5 = 245 cm2

(c) Area of rectangle ABCD = 5 x 1 = 5 cm2

Area of rectangle EFGH = 4 x 1 = 4 cm2

Total area of the figure = 5 + 4 cm2

NCERT Solutions for Class 6 Maths Exercise 10.3

###### Question 12.How many tiles whose length and breadth are 12 cm and 5 cm respectively will be needed to fit in a rectangular region whose length and breadth are respectively:

(a)100 cm and 144 cm

(b)70 cm and 36 cm

(a) Area of region = 100 cm x 144 cm = 14400 cm2

Area of one tile = 5 cm x 12 cm = 60 cm2

Number of tiles = {tex}\frac{{{\text{Area of region}}}}{{{\text{Area of one tile}}}}{/tex}

= 240

Thus, 240 tiles are required.

(b) Area of region = 70 cm x 36 cm = 2520 cm2

Area of one tile = 5 cm x 12 cm = 60 cm2

Number of tiles = {tex}\frac{{{\text{Area of region}}}}{{{\text{Area of one tile}}}}{/tex}

= 42

Thus, 42 tiles are required.

## NCERT Solutions for Class 6 Maths Exercise 10.3

NCERT Solutions Class 6 Maths PDF (Download) Free from myCBSEguide app and myCBSEguide website. Ncert solution class 6 Maths includes text book solutions from Class 6 Maths Book . NCERT Solutions for CBSE Class 6 Maths have total 14 chapters. 6 Maths NCERT Solutions in PDF for free Download on our website. Ncert Maths class 6 solutions PDF and Maths ncert class 6 PDF solutions with latest modifications and as per the latest CBSE syllabus are only available in myCBSEguide.

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