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Ask QuestionPosted by Dattatrey Mangavati 3 years ago
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Posted by Surya Sandeep 3 years ago
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Preeti Dabral 3 years ago
One Volt is defined as energy consumption of one joule per electric charge of one coulomb. 1V = 1J/C. One volt is equal to the current of 1 amp times the resistance of 1 ohm.
Abhishek Sahu 3 years ago
Aniket Dubey 3 years ago
Posted by Noufal Kasala 3 years ago
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Preeti Dabral 3 years ago
Value of {tex}\frac{x}{\sqrt{a^2+x^2}}{/tex}
{tex}\tan \theta=\frac{\mathrm{a}}{\mathrm{x}} Since, \begin{aligned} & \frac{x}{\sqrt{a^2+x^2}} \\ & \Rightarrow \frac{\frac{a}{\tan \theta}}{\sqrt{a^2+\left(\frac{a}{\tan \theta}\right)^2}} \\ & \Rightarrow \frac{\frac{a}{\tan \theta}}{\sqrt{a^2+\frac{a^2}{\tan ^2 \theta}}} \end{aligned} {/tex}
{tex}\begin{aligned} & \Rightarrow \frac{\frac{a}{\tan \theta}}{a \sqrt{\frac{1+\tan ^2 \theta}{\tan ^2 \theta}}} \\ & \Rightarrow \frac{\frac{1}{\tan \theta}}{\sqrt{\frac{1+\tan ^2 \theta}{\tan ^2 \theta}}} \\ & \Rightarrow \frac{1}{\sqrt{\sec ^2 \theta}} \\ & \Rightarrow \frac{1}{\sec \theta} \end{aligned}{/tex}
{tex}\Rightarrow \cos \theta {/tex}
Posted by Bijender Kumar 3 years ago
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Preeti Dabral 3 years ago
First story about flying is that there was the family of a bird.The child of a female bird cannot fly , he has the fear that I will die if I fly.His family increases his courage. At last, he succeed in his mission. The second story is that a pilot was driving his plane.Due to some fault , some error occurs in his plane . he thought that very soon I reach to my home so I can take the delicious food . An unknown aeroplane pilot was helped him to land safely.
Posted by Sima Kumaris 3 years ago
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Preeti Dabral 3 years ago
- Vegetative propagated plants are short lived, small compared to seed propagated plants.
- No new varieties can be produced.
- Skilled persons are required and often expensive compared to seed propagation.
- More susceptible to diseases as the entire plant may get affected as there is no genetic variation.
Posted by Tannu Singh 3 years ago
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Preeti Dabral 3 years ago
किसी पात्र में थोड़ा पानी ले कर उबलने के लिए ऑच पर रखने से, पात्र की तली में नन्हे बुदबुदे दिखाई देने लगते हैं। ये पानी में घुली हुई वायु के अलग हो कर भाप बनने के संकेत हैं। पानी उबलने की स्थिति में बड़े बड़े भाप के बबूले उपर तक आ जाते है और हवा में घुल जाते हैं । इस से पता लगता है कि जल में वायु घुली होती है ।
Posted by Tanya Garg 3 years ago
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Posted by Sachin Sachin 3 years ago
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Mohit Kumar 3 years ago
Reeta Rani 3 years ago
Posted by Mamatha Dumpa 3 years ago
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Preeti Dabral 3 years ago
The Opposition is the largest non-government party or coalition of parties in the Legislative Assembly. The Opposition's main role is to question the government of the day and hold them accountable.
Posted by P Raval 3 years ago
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Posted by Gandhan Pavar Gandhan Pavar 3 years ago
- 2 answers
Gandhan Pavar Gandhan Pavar 3 years ago
Posted by P Raval 3 years ago
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Gandhan Pavar Gandhan Pavar 3 years ago
Vanshika Jain 3 years ago
Posted by Daksh Vijay 3 years ago
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Preeti Dabral 3 years ago
{tex}\begin{aligned} & \text { To prove : } \frac{1+\sec \mathrm{A}}{\sec \mathrm{A}}=\frac{\sec ^{12} \mathrm{~A}}{1-\cos \mathrm{A}} \\ & \text { LHS } \frac{1+\sec \mathrm{A}}{\sec \mathrm{A}}=\frac{1+\frac{1}{\cos \mathrm{A}}}{\frac{1}{\cos \mathrm{A}}} \\ & =\frac{\frac{\cos \mathrm{A}+1}{\cos \mathrm{A}}}{\frac{1}{\cos \mathrm{A}}} \\ & =\frac{\cos \mathrm{A}+1}{\cos \mathrm{A}} \times \frac{\cos \mathrm{A}}{1} \\ & =1+\cos \mathrm{A} \\ & =1+\cos \mathrm{A} \times \frac{1-\cos \mathrm{A}}{1-\cos \mathrm{A}} \\ & =\frac{(1)^2-(\cos \mathrm{A})^2}{1-\cos \mathrm{A}} \\ & =\frac{1-\cos 2 \mathrm{~A}}{1-\cos \mathrm{A}} \end{aligned}{/tex}
{tex}\begin{aligned} & =\frac{\sin ^2 \mathrm{~A}}{1-\cos \mathrm{A}} \\ & =\mathrm{RHS} \end{aligned}{/tex}
Posted by Ishita Gupta 3 years ago
- 1 answers
Posted by Ashutosh Singh 3 years ago
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Preeti Dabral 3 years ago
Given quadratic equation is p(x-4)(x-2)+(x-1)² = 0
=> p(x²-4x-2x+8)+(x²-2x+1) = 0
=> p(x²-6x+8)+(x²-2x+1) = 0
=> px²-6px+8p+x²-2x+1 = 0
=> (px²+x²)+(-6px-2x)+8p+1 = 0
=> (p+1)x²-(6p+2)x+(8p+1) = 0
On comparing with the standard quadratic equation is ax²+bx+c = 0 then
a = p+1
b = -(6p+2)
c = 8p+1
Given that
Given equation has real and equal roots
=> The discriminant = 0
We know that
The discriminant of ax²+bx+c = 0 is b²-4ac
Therefore, b²-4ac = 0
=> [-(6p+2)]²-4(p+1)(8p+1) = 0
=> (6p+2)²-4(p+1)(8p+1) = 0
=> (36p²+24p+4)-4(8p²+p+8p+1) = 0
=> (36p²+24p+4)-4(8p²+9p+1) = 0
=> 36p²+24p+4-32p²-36p-4 = 0
=> (36p²-32p²)+(24p-36p)+(4-4) = 0
=> 4p² -12p+0 = 0
=> 4p² - 12 p = 0
=> 4p(p-3) = 0
=> 4p = 0 or p-3 = 0
=> p = 0/4 or p = 3
=> p = 0 or p = 3
If p = 0 the term containing p doesn't exist .
Therefore, p = 3
Posted by Kriahna Singh Mahant 3 years ago
- 2 answers
Posted by Kriahna Singh Mahant 3 years ago
- 0 answers
Posted by Kriahna Singh Mahant 3 years ago
- 1 answers
Posted by Kriahna Singh Mahant 3 years ago
- 1 answers
Posted by Kriahna Singh Mahant 3 years ago
- 0 answers
Posted by Kriahna Singh Mahant 3 years ago
- 0 answers
Posted by Kriahna Singh Mahant 3 years ago
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Posted by Kriahna Singh Mahant 3 years ago
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Posted by Kriahna Singh Mahant 3 years ago
- 1 answers
Preeti Dabral 3 years ago
हीराकुद बाँध ओड़िशा में महानदी पर निर्मित एक बाँध है। यह सम्बलपुर से 15 किमी दूर है। 1957 में महानदी पर निर्मित यह बाँध संसार का सबसे बड़ा एवं लंबा बांध है। इसकी कुल लम्बाई 25.8 किमी० है।
Posted by Kriahna Singh Mahant 3 years ago
- 2 answers
Posted by Kriahna Singh Mahant 3 years ago
- 2 answers
Preeti Dabral 3 years ago
हीराकुद बाँध ओड़िशा में महानदी पर निर्मित एक बाँध है। यह सम्बलपुर से 15 किमी दूर है। 1957 में महानदी पर निर्मित यह बाँध संसार का सबसे बड़ा एवं लंबा बांध है। इसकी कुल लम्बाई 25.8 किमी० है।
Posted by Riya Chaudhary 3 years ago
- 2 answers
Reeta Rani 3 years ago
Rovin Balu 3 years ago
Posted by P Raval 3 years ago
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Posted by Prasiddhi Chourdiya 3 years ago
- 0 answers
Posted by P Raval 3 years ago
- 3 answers
Anushka Sharma 2 years, 11 months ago
Ishita Gupta 3 years ago
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Abhishek Dubey 3 years ago
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