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Ask QuestionPosted by Sukhwinder Singh 2 years, 11 months ago
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Posted by Afiya Afiya 2 years, 11 months ago
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Preeti Dabral 2 years, 11 months ago
Height of the cylinder (h) = 14 cm,
Base diameter = 7 cm
{tex}\Rightarrow{/tex} Radius of the base of the cylinder (r) = 3.5 cm
Volume of the cylinder = {tex}\pi r ^ { 2 } h{/tex}
= {tex}\frac { 22 } { 7 } \times 3.5 \times 3.5 \times 14{/tex}
= 22 {tex}\times{/tex}3.5 {tex}\times{/tex}3.5{tex}\times{/tex}14
= 539 cm3
Radius of the conical holes (r1) = 2.1 cm,
Height of the conical holes (h1) = 4 cm,
volume of the conical hole {tex}= \frac { 1 } { 3 } \pi r _ { 1 } ^ { 2 } h _ { 1 }{/tex}
{tex}= \frac { 1 } { 3 } \times \frac { 22 } { 7 } \times 2.1 \times 2.1 \times 4{/tex}
= 18.48 cm3
Volume of the two conical hole = 2 {tex}\times{/tex}18.48
= 36.96 cm3
Volume of the remaining solid = Volume of the cylinder - Volume of two conical hole
= 539 - 36.96
= 502.04 cm3
Posted by Tushar Saini 2 years, 11 months ago
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@Balram$₹* @ 2 years, 11 months ago
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Few rules to keep homework help section safe, clean and informative.
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Stanzin Chorgyal 2 years, 11 months ago
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Preeti Dabral 2 years, 11 months ago
he wrote a letter addressing God to send him 100 pesos so that they could survive in such a difficult situation.
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Valli loved to watch the bus passing through her street every hour. The sight of the bus filled with new passengers gave her an unending joy. She wished to ride on that bus. The wish became an overwhelming desire due to her growing fascination for the bus ride.
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Chinmayi P P 2 years, 11 months ago
0Thank You