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    • Posted by Govind 2009 1 year, 2 months ago

    CBSE > Class 10 > English Language and Literature
    • 2 answers

    I Am Helper 1 year, 2 months ago

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    0Thank You

    I Am Helper 1 year, 2 months ago

    This content has been hidden. One or more users have flagged this content as inappropriate. Once content is flagged, it is hidden from users and is reviewed by myCBSEguide team against our Community Guidelines. If content is found in violation, the user posting this content will be banned for 30 days from using Homework help section. Suspended users will receive error while adding question or answer. Question comments have also been disabled. Read community guidelines at https://mycbseguide.com/community-guidelines.html

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    • Posted by Abhi Bishnoi 1 year, 2 months ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    I Am Helper 1 year, 2 months ago

    Expand the left-hand side: [(x+2)^3 = x^3 + 3 \cdot x^2 \cdot 2 + 3 \cdot x \cdot 2^2 + 2^3] [= x^3 + 6x^2 + 12x + 8]Expand the right-hand side: [2x(x^2 - 1) = 2x \cdot x^2 - 2x \cdot 1] [= 2x^3 - 2x]Set the expanded forms equal: [x^3 + 6x^2 + 12x + 8 = 2x^3 - 2x]Move all terms to one side to form a polynomial equation: [x^3 + 6x^2 + 12x + 8 - 2x^3 + 2x = 0] [ - x^3 + 6x^2 + 14x + 8 = 0]Simplify the equation: [x^3 - 6x^2 - 14x - 8 = 0]Solve the cubic equation (x^3 - 6x^2 - 14x - 8 = 0):

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    • Posted by Sonali Sendhav 1 year, 2 months ago

    CBSE > Class 10 > हिंदी ए
    • 0 answers
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    • Posted by Sonali Sendhav 1 year, 2 months ago

    CBSE > Class 10 > हिंदी ए
    • 0 answers
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    • Posted by Sahasra Goud 1 year, 2 months ago

    CBSE > Class 10 > Social Science
    • 0 answers
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    • Posted by Anjali Sharma 1 year ago

    CBSE > Class 10 > English Language and Literature
    • 0 answers
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    • Posted by Chahek Makhija 1 year, 2 months ago

    CBSE > Class 10 > हिंदी ब
    • 0 answers
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    • Posted by Harman Kaur 1 year, 2 months ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Rakesh Kumar 1 year, 2 months ago

    3x is x and y is 5y and z is 17z

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    • Posted by Samriddhi Mishra 1 year, 2 months ago

    CBSE > Class 10 > हिंदी ए
    • 0 answers
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    • Posted by Abhinav Sharma 1 year, 2 months ago

    CBSE > Class 10 > English Language and Literature
    • 0 answers
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    • Posted by Priyansu Samal 1 year, 2 months ago

    CBSE > Class 10 > Other Subjects
    • 0 answers
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    • Posted by Mansi Ladna 1 year, 2 months ago

    CBSE > Class 10 > Social Science
    • 0 answers
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    • Posted by Biju Maniyan 1 year, 2 months ago

    CBSE > Class 10 > Social Science
    • 1 answers

    Biju Maniyan 1 year, 2 months ago

    This content has been hidden. One or more users have flagged this content as inappropriate. Once content is flagged, it is hidden from users and is reviewed by myCBSEguide team against our Community Guidelines. If content is found in violation, the user posting this content will be banned for 30 days from using Homework help section. Suspended users will receive error while adding question or answer. Question comments have also been disabled. Read community guidelines at https://mycbseguide.com/community-guidelines.html

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    • Posted by Sevi Sevi 1 year, 2 months ago

    CBSE > Class 10 > हिंदी ब
    • 0 answers
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    • Posted by Divya Rawat 1 year, 2 months ago

    CBSE > Class 10 > English Language and Literature
    • 0 answers
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    • Posted by Bikram Kumar Sarkar 1 year, 2 months ago

    CBSE > Class 10 > Mathematics
    • 2 answers

    Yuvraj Shinde 1 year, 2 months ago

    2x+y=7 4x-3y+1=0

    0Thank You

    I Am Helper 1 year, 2 months ago

    Given that \(2 \tan A = 3\), we want to find the value of \(\sin A\) and \(\cos A\). 1. **Express \(\tan A\) in terms of a simpler fraction**: \[ \tan A = \frac{3}{2} \] 2. **Use the Pythagorean identity to find \(\sin A\) and \(\cos A\)**: We know that: \[ \sin^2 A + \cos^2 A = 1 \] and \[ \tan A = \frac{\sin A}{\cos A} \] Since \(\tan A = \frac{3}{2}\), we can set: \[ \sin A = 3k \quad \text{and} \quad \cos A = 2k \] where \(k\) is a common factor. 3. **Use the Pythagorean identity** to find \(k\): \[ \sin^2 A + \cos^2 A = 1 \] Substitute \(\sin A\) and \(\cos A\): \[ (3k)^2 + (2k)^2 = 1 \] Simplify the equation: \[ 9k^2 + 4k^2 = 1 \] \[ 13k^2 = 1 \] Solve for \(k\): \[ k^2 = \frac{1}{13} \] \[ k = \frac{1}{\sqrt{13}} \] 4. **Find \(\sin A\) and \(\cos A\)** using \(k\): \[ \sin A = 3k = 3 \times \frac{1}{\sqrt{13}} = \frac{3}{\sqrt{13}} = \frac{3 \sqrt{13}}{13} \] \[ \cos A = 2k = 2 \times \frac{1}{\sqrt{13}} = \frac{2}{\sqrt{13}} = \frac{2 \sqrt{13}}{13} \] Thus, the values of \(\sin A\) and \(\cos A\) are: \[ \sin A = \frac{3 \sqrt{13}}{13} \] \[ \cos A = \frac{2 \sqrt{13}}{13} \]

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    • Posted by Trupti R 1 year, 2 months ago

    CBSE > Class 10 > Mathematics
    • 0 answers
    ANSWER

    • Posted by Rudraksh Singla 1 year, 2 months ago

    CBSE > Class 10 > English Communicative (101)
    • 0 answers
    ANSWER

    • Posted by Komal Kumari 1 year, 2 months ago

    CBSE > Class 10 > English Language and Literature
    • 1 answers

    M. Yugendiran M. Yugendiran 1 year, 2 months ago

    What is the dust of snow poet name

    1Thank You

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    • Posted by Harshit Singh 1 year, 2 months ago

    CBSE > Class 10 > English Language and Literature
    • 0 answers
    ANSWER

    • Posted by Butki Choti 1 year, 2 months ago

    CBSE > Class 10 > Science
    • 1 answers

    Prakash Choudhary Prakash Choudhary 1 year, 2 months ago

    How do we know wether a compound is an acid or base? solution

    2Thank You

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    • Posted by Harleen Kour 1 year, 2 months ago

    CBSE > Class 10 > हिंदी ए
    • 0 answers
    ANSWER

    • Posted by Kartikay Kaushik 1 year, 2 months ago

    CBSE > Class 10 > English Language and Literature
    • 0 answers
    ANSWER

    • Posted by Sakshi Samdhyan 1 year, 2 months ago

    CBSE > Class 10 > Social Science
    • 2 answers

    Biju Maniyan 1 year, 2 months ago

    This content has been hidden. One or more users have flagged this content as inappropriate. Once content is flagged, it is hidden from users and is reviewed by myCBSEguide team against our Community Guidelines. If content is found in violation, the user posting this content will be banned for 30 days from using Homework help section. Suspended users will receive error while adding question or answer. Question comments have also been disabled. Read community guidelines at https://mycbseguide.com/community-guidelines.html

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    1Thank You

    Biju Maniyan 1 year, 2 months ago

    This content has been hidden. One or more users have flagged this content as inappropriate. Once content is flagged, it is hidden from users and is reviewed by myCBSEguide team against our Community Guidelines. If content is found in violation, the user posting this content will be banned for 30 days from using Homework help section. Suspended users will receive error while adding question or answer. Question comments have also been disabled. Read community guidelines at https://mycbseguide.com/community-guidelines.html

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    • Posted by Khushi Yadav 1 year, 2 months ago

    CBSE > Class 10 > Mathematics
    • 1 answers

    Khushi Yadav 1 year, 2 months ago

    This content has been hidden. One or more users have flagged this content as inappropriate. Once content is flagged, it is hidden from users and is reviewed by myCBSEguide team against our Community Guidelines. If content is found in violation, the user posting this content will be banned for 30 days from using Homework help section. Suspended users will receive error while adding question or answer. Question comments have also been disabled. Read community guidelines at https://mycbseguide.com/community-guidelines.html

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    6Thank You

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    • Posted by Gurshaan Brar 1 year, 2 months ago

    CBSE > Class 10 > English Language and Literature
    • 1 answers

    Gurshaan Brar 1 year, 2 months ago

    This content has been hidden. One or more users have flagged this content as inappropriate. Once content is flagged, it is hidden from users and is reviewed by myCBSEguide team against our Community Guidelines. If content is found in violation, the user posting this content will be banned for 30 days from using Homework help section. Suspended users will receive error while adding question or answer. Question comments have also been disabled. Read community guidelines at https://mycbseguide.com/community-guidelines.html

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    2Thank You

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    • Posted by Shanaya Mishra 1 year, 2 months ago

    CBSE > Class 10 > English Language and Literature
    • 0 answers
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    • Posted by Srushti Biradar 1 year, 2 months ago

    CBSE > Class 10 > Mathematics
    • 0 answers
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    • Posted by Vikrant Pal 1 year, 2 months ago

    CBSE > Class 10 > Social Science
    • 1 answers

    Deep Thi.S 1 year, 2 months ago

    This content has been hidden. One or more users have flagged this content as inappropriate. Once content is flagged, it is hidden from users and is reviewed by myCBSEguide team against our Community Guidelines. If content is found in violation, the user posting this content will be banned for 30 days from using Homework help section. Suspended users will receive error while adding question or answer. Question comments have also been disabled. Read community guidelines at https://mycbseguide.com/community-guidelines.html

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    2Thank You

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    • Posted by Amruth N V 1 year, 2 months ago

    CBSE > Class 10 > Social Science
    • 0 answers
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