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? Royal Thakur ? 6 years ago
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? Royal Thakur ? 6 years ago
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Posted by ? Royal Thakur ? 6 years ago
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Yogita Ingle 6 years ago
| Basis | Acid | Base |
| Definition | An acid is any chemical compound once dissolved in water produces a solution with hydrogen ion activity more than purified water | A base is an aqueous substance that could absorb hydrogen ions. |
| Strength | Relies on the concentration of the hydronium ions | Relies on the concentration of the hydroxide ions |
| Examples | Acetic acid CH3COOH and sulphuric acid | Sodium Hydroxide (NaOH) and Ammonia |
| Characteristics (Physical) | Would depend upon the temperature acids would look solid, liquid or in the form of gas. It would also have a sour taste. | Bases would feel slippery and solid in nature except ammonia which is gaseous. It would have a bitter taste. |
| Disassociation | Acids would release hydrogen ions (h+) when mixed with water | Bases would release hydroxide ions(OH-) when mixed with water |
| Test with Litmus | Would turn litmus paper red | Would turn litmus paper blue |
Posted by Prisha Gupta 6 years ago
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Yogita Ingle 6 years ago
(a) Given:For electric bulb:
Voltage = 220 V
Resistance = 1200 Ω
Solution:
According to Ohm's law, the current is ratio of voltage and resistance, hence, can be written as:
{tex}I=\frac{V}{R}{/tex}
Plug the given values in the above formula:
{tex}I=\frac{220 \ V}{1200 \ \Omega}=0.183 \ Ampere{/tex}
(b) Given:
For electric heater coil:
Voltage = 220 V
Resistance = 100 Ω
Solution:
According to Ohm's law, the current is ratio of voltage and resistance hence can be written as:
{tex}I=\frac{V}{R}{/tex}
Plug the given values in the formula:
{tex}I=\frac{220 \ \mathrm{V}}{100 \ \Omega}=2.20 \ Ampere{/tex}
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Gaurav Seth 6 years ago
Jobber : ‘Jobbers’ were usually employed by the industrialists to recruit the right people for work from villages out of the various job seekers. A jobber often demanded money or gifts for his favour (that is for finding a job for someone).
The main functions of a Jobber were :
(i) Getting people from villages.
(ii) Ensuring them jobs.
(iii) Helping them to settle in the city and to provide them money in times of crisis.
Posted by Jeevith Arumugam 6 years ago
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Yogita Ingle 6 years ago
Since there are 2 zeroes, the polynomial is of degree 2.
Let a and b represents the zeroes of the polynomial.
Let {tex}a=2+\sqrt{3} and b=2-\sqrt{3}{/tex}
Since, the polynomial is of degree 2
Polynomial would be of the form {tex}{x^{2}-(a+b) x+a b} {/tex}
Therefore computing the values,
{tex}{a+b=(2+\sqrt{3})+(2-\sqrt{3})=4}{/tex}
{tex}{a b=(2+\sqrt{3}) \times(2-\sqrt{3})=4-3=1}{/tex}
Therefore, the polynomial is {tex}{x^{2}-4 x+1} {/tex}
Posted by Mohit Tilwani 6 years ago
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Posted by Bharani Ajith 6 years ago
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Gaurav Seth 6 years ago
Let a be any positive integer
by EDL a = bq +r
0 ≤ r < b
possible remainders are 0, 1, 2 , 3
this shows that a can be in the form of 4q, 4q+1, 4q+2, 4q+3 q is quotient
as a is odd a can't be the form of 4q or 4q+2 as they are even
so a ill be in the form of 4q + 1 or 4q+3
hence proved
Posted by Lipa Routray 6 years ago
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Riya Shree Gupta 6 years ago
1Thank You