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Gaurav Seth 5 years, 8 months ago
QUESTION: Solve; 1/a+b+x=1/a+1/b+1/x
Answer:
1/(a+b+x)=1/a + 1/b + 1/x
1/(a+b+x) -1/x = 1/a + 1/b
x-(a+b+x)/x(a+b+x) = a+b/ ab
-1(a+b) /x(a+b+x) = a+b/ ab
-1(a+b)/(a+b) = x(a+b+x)/ab
-1=x(a+b+x) / ab
-ab= (a+b)x + x2
so, x2 + (a+b)x +ab = 0
now, A = 1, B=(a+b) C= ab..
so, D = B2 - 4AC
=(a+b)2 - 4ab
= (a-b)2
so, x = (-B + root D)/2A and (-B-root D)/2A
= -a-b+a-b /2*1 and -a-b-a+b /2*1
= -2b/1 and -2a /1
so,x = -2b or -2a .
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Gaurav Seth 5 years, 8 months ago
Reaction of acids with metal carbonate:
Acids give carbon dioxide gas and respective salts along with water when they react with metal carbonates.
Metal carbonate + Acid ⇨ Salt + Carbon dioxide + Water
Examples: Hydrochloric acid gives carbon dioxide gas, sodium chloride along with water when it reacts with sodium carbonate.
<i>Na2CO3 + 2HCl ⇨ 2NaCl + CO2 + H2O</i>
Hydrochloric acid gives carbon dioxide, magnesium chloride and water when it reacts with magnesium carbonate.
<i>MgCO3 + 2HCl ⇨ MgCl2 + CO2 + H2O</i>
Hydrochloric acid gives carbon dioxide gas, calcium chloride and water when it reacts with calcium carbonate.
<i>CaCO3 + 2HCl ⇨ CaCl2 + CO2 + H2O</i>
Sulphuric acid gives calcium sulphate, carbon dioxide gas, calcium sulphate and water when it reacts with calcium carbonate.
<i>CaCO3 + H2SO4 ⇨ CaSO4 + CO2 + H2O</i>
Posted by Tanishka Dhonge 5 years, 8 months ago
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Gaurav Seth 5 years, 8 months ago
a. Organised sector
The enterprises or places of work where the terms of employment are regular and therefore, people have assured work.
They are registered by the government and have to follow its various laws such as the Factories Act, Minimum Wages Act, Payment of Gratuity Act, Shop and Establishment Act, etc. Workers enjoy the security of employment, they work only fixed a number of hours and given benefits like paid leave, Provident Fund, and medical facilities.
Posted by Namitha Namitha 5 years, 8 months ago
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Gaurav Seth 5 years, 8 months ago
Given that (a-b) x + (a + b)y = a2 - 2ab - b2 -------------(1)
(a+b) x+ (a+b)y = a2 + b2 -------------(2)
Substracting (2) from (1) we get
-2bx = -2ab
=2b2 x = a + b
Subsitute x in equation (2) we get y = - 2ab / ( a + b).
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