Ask questions which are clear, concise and easy to understand.
Ask QuestionPosted by Kukatla Ajith Kumar Yadav Yadav 5 years, 4 months ago
- 2 answers
Neha Singh 5 years, 4 months ago
Anbhu Arasan 5 years, 4 months ago
Posted by Kukatla Ajith Kumar Yadav Yadav 5 years, 4 months ago
- 4 answers
Anupama ?? 5 years, 4 months ago
Yogita Ingle 5 years, 4 months ago
When some metals are exposed to moisture, acids etc., they tarnish due to the formations of respective metal oxide on their surface. This process is called “corrosion”.
1) 4 Ag + 2H2S + O2 → 2Ag2S + 2H2O
2) 2 Cu + O2 → 2 CuO
Khush Kaur 5 years, 4 months ago
Posted by Debasish Gogoi 5 years, 4 months ago
- 4 answers
Posted by Sulagna Mukherjee 5 years, 4 months ago
- 1 answers
Sanika Walimbe 5 years, 4 months ago
Posted by Dhruv Lamba 5 years, 4 months ago
- 3 answers
Posted by Pranali Solanke 5 years, 4 months ago
- 0 answers
Posted by Samruddhi Br 5 years, 4 months ago
- 1 answers
Madhav Emineni 5 years, 4 months ago
Posted by Mohamed Kalim 5 years, 4 months ago
- 3 answers
Anupama ?? 5 years, 4 months ago
Ranveer Yadav 5 years, 4 months ago
Posted by Jayant Bisht 5 years, 4 months ago
- 3 answers
Posted by Suganth Kamal 5 years, 4 months ago
- 0 answers
Posted by Ashish Das 5 years, 4 months ago
- 0 answers
Posted by Praveen Choudhary 5 years, 4 months ago
- 2 answers
Yogita Ingle 5 years, 4 months ago
The issue of sustainability is important for development because:
- It requires preservation of stock of resources including exhaustible natural resources and environmental resources.
- Recent studies show that groundwater in India is exhausted because of overuse. 1/3 of the country is overusing its groundwater reserves. Another area is exhaustion of natural resources. The resources of crude oil would last only for 43 years more.
Prajnasree Behera 5 years, 4 months ago
Posted by Rohit Singh 5 years, 4 months ago
- 0 answers
Posted by Ajay Ram Ajay 5 years, 4 months ago
- 3 answers
Posted by Sunidhi Singh 5 years, 4 months ago
- 0 answers
Posted by Sunidhi Singh 5 years, 4 months ago
- 0 answers
Posted by Sunidhi Singh 5 years, 4 months ago
- 1 answers
Sunil Sahu 5 years, 4 months ago
Posted by Vartika Pandey 5 years, 4 months ago
- 1 answers
Gaurav Seth 5 years, 4 months ago
Mr Keesing was an old maths teacher at Anne’s school.He was very strict by Nature. He would not tolerate anyone talking in his class. Naturally, he remained quiet annoyed with Anne who was no doubt the Chatterbox.He would punish her by giving her extra homework. Anne would stuff her assigned homework with such funny contents that not only the class but even Mr Keesing felt greatly delighted. But Mr Keesing still failed to stop Anne's habit of chattering in the class. With the intention of making a mockery of Anne he gave her an essay to write on the topic: ‘Quack, Quack, Quack,’ Mrs Chatterbox. Anne wrote her essay in the form of a story in verse. It told the story of a mother duck and a father swan. The father bites his three ducklings to death because they quacked too much. The father in the poem is clearly Mr Keesing and the ducklings are the children of his class. Luckily Mr Keesing took the joke the right way. He enjoyed this poem and read it to several classes. He stopped giving Anne any extra homework. He allowed her to talk in the class. He even started making jokes with the children. Thus we see how even Mr Keesing got infected by Anne's sense of humour.
Posted by Sunidhi Singh 5 years, 4 months ago
- 1 answers
Gaurav Seth 5 years, 4 months ago
1) S1: = 1 + 3 + 5 + 7 + ---- + (2n-1) [nth term; a + (n-1)d;
==> nth term = 1 + (n-1)2 = (2n-1)]
2) Sum to n terms of an AP: (n/2){1st term + Last term};
==> S1 = (n/2)*(1 + 2n -1) = (n^2)
3) S2 = 1 + 5 + 9 + 13 + ---- + (2n-3)
[Here a = 1; d = 4; no. of terms = n/2, assuming in S1, number of terms are even]
==> S2 = {(n/2)/2}*(1 + 2n -3) = (n/4)*(2n-2) = (n)(n-1)/2
So, S1/S2 = (n^2)/{(n)(n-1)/2} = 2n/(n-1)
Now let us consider, the number of terms in S1 are odd;
Then number of terms in S2 would be = (n+1)/2
==> Last term here = 1 + {(n+1)/2 - 1}4 = 1 + 2n + 2 - 4 = 2n - 1
==> S2 = {(n+1)/2)/2}*(1 + 2n -1) = (n)*(n+1)/2
So, in this case the ratio S1/S2 = 2n/(n+1)
Posted by Sunidhi Singh 5 years, 4 months ago
- 1 answers
Gaurav Seth 5 years, 4 months ago
Skx = kx/2 (2a + (kx-1)d)
Sx = x/2 (2a + (x-1)d)
Skx/Sx = [kx/2 (2a + (kx-1)d)] / [x/2 (2a + (x-1)d)]
= [k (2a + (kx-1)d)] / [(2a + (x-1)d)]
For Skx/Sx to be independent of x, 2a – d = 0.
2a – d = 0 ⇒ 2a = d ⇒ a = d/2.
Posted by Nahid Shakil 5 years, 4 months ago
- 1 answers
Gaurav Seth 5 years, 4 months ago
- A telebook is a book that can be displayed on a screen for educating or entertaining people.
- A telebook can be an online book which can be browsed using internet. Or it can be displayed through TV signals on TV screen.
- A telebook is a book that can be displayed on a screen for educating or entertaining people.
Posted by Bandookmaar Gaming 5 years, 4 months ago
- 2 answers
Neha Singh 5 years, 4 months ago
Posted by Sunidhi Singh 5 years, 4 months ago
- 2 answers
Gaurav Seth 5 years, 4 months ago
Given that Sum to n terms of an AP is
3n² + n
Given common difference is 6,
If suppose a is the first term of A.P and 'd' is the
common difference, the Sum to n terms of an A.P is
given by Sn = (n/2)*[2a + (n - 1)d]
Given Sn = 3n² + n
If we substitute n = 1 , in Sn we get Sum to 1 tems of an A.P
which is equivalent to first term of A.P itself,
So, 1st term of A,P = S₁ = 3.1² + 1
= 3 + 1
= 4.
Hence, first term of an A.P is 4.
Posted by Sunidhi Singh 5 years, 4 months ago
- 1 answers
Gaurav Seth 5 years, 4 months ago
is the sum of
terms.
Given:
Sum of first p terms of an AP = q
Sum of first q terms = p
To find:
Sum of (p + q) terms = ?
Solution:
The sum of first p term of AP is q, which means that the number of terms is p
Thereby, let us take the first term as A and the common difference d
The sum of first q term of AP is p, which means that the number of terms is q
Thereby, let us take the first term as A and the common difference d
Therefore, the sum
Subtracting the sum of the term , p and q
After solving the equation we get the value of d as
Now with , first value of the series is a and the number of terms is
Therefore, the sum is
3.6
Posted by Sunidhi Singh 5 years, 4 months ago
- 1 answers
Gaurav Seth 5 years, 4 months ago
a n s w e r
Given that :
Sn is sum of first n terms of an A.P.
Let a be the first term and d be the common difference of the given A.P.
Then,
myCBSEguide
Trusted by 1 Crore+ Students
Test Generator
Create papers online. It's FREE.
CUET Mock Tests
75,000+ questions to practice only on myCBSEguide app
Borigi Adhithya 5 years, 4 months ago
0Thank You