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Ask QuestionPosted by Haridev Sudhan 5 years, 3 months ago
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Yogita Ingle 5 years, 3 months ago
Nearly 99 per cent of the filtrate formed after glomerular filtration has to be reabsorbed by the renal tubules. This process is called reabsorption. Though, this reabsorption takes place selectively allowing substances useful to be reabsorbed excluding those not needed by the body. Hence, it is called selective reabsorption. The tubular epithelial cells in different segments of nephron perform this either by active or passive mechanisms.
For example, substances like glucose, amino acids, Na+, etc., in the filtrate are reabsorbed actively.
Posted by Shiva Yadav 5 years, 3 months ago
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Posted by Boybe Cool 5 years, 3 months ago
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Haridev Sudhan 5 years, 3 months ago
Posted by Anukul Mishra 5 years, 3 months ago
- 2 answers
Haridev Sudhan 5 years, 3 months ago
Posted by Account Deleted 5 years, 3 months ago
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Yogita Ingle 5 years, 3 months ago
Power sharing is desirable because of the following reasons. Power sharing helps to reduce the possibility of conflict between social groups. Power sharing is a good way to ensure the stability of political order as social conflict often leads to violence and political instability.
Anukul Mishra 5 years, 3 months ago
Boobala Guru 5 years, 3 months ago
Posted by Siddharth Jangid 5 years, 3 months ago
- 3 answers
Boobala Guru 5 years, 3 months ago
Posted by Siddharth Jangid 5 years, 3 months ago
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Posted by Siddharth Jangid 5 years, 3 months ago
- 3 answers
Yogita Ingle 5 years, 3 months ago
Let the three consecutive terms be (a-d) (a) & (a+d) resp.
(a - d) + (a) + (a + d) =42
3a = 42
a = 14
Posted by Indrajeet Kumar 5 years, 3 months ago
- 2 answers
Posted by Hethvkraj Raj 5 years, 3 months ago
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Posted by Siddharth Jangid 5 years, 3 months ago
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Posted by Siddharth Jangid 5 years, 3 months ago
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Boobala Guru 5 years, 3 months ago
Yogita Ingle 5 years, 3 months ago
6x² – x – 2 = 0
6x² – 4x+ 3x – 2 = 0
2x(3x - 2) + 1 (3x - 2) = 0
(3x -2) ( 2x + 1) = 0
3x - 2 = 0 and 2x + 1 = 0
3x = 2 and 2x = -1
x = 2/3 and x = -1/2
Posted by Siddharth Jangid 5 years, 3 months ago
- 1 answers
Posted by Siddharth Jangid 5 years, 3 months ago
- 2 answers
Yogita Ingle 5 years, 3 months ago
Sum of first 5 multiples of 3:
Sum of an AP is: n/2 ×(2a+(n−1)d)
a=3,d=3,n=5
Then,
Sum = 5/2 ×(2×3+(5−1)×(3))
= 5/2×(6+12)
= 45
Posted by Siddharth Jangid 5 years, 3 months ago
- 1 answers
Yogita Ingle 5 years, 3 months ago
(sin30+cos30) - (sin60+cos60)
sin30 = 1/2
sin60= √3/2
cos30= √3/2
cos60= 1/2
= (1/2+√3/2) - (√3/2+1/2)
=1+√3/2 - √3+1/2
= 1+1+√3-√3 /2
= 2/2
= 1
Posted by Siddharth Jangid 5 years, 3 months ago
- 2 answers
Yogita Ingle 5 years, 3 months ago
The value of cosec 30 is
cosec 30 = 1/sin 30
cosec 30 = 1/ 1/2= 2
Posted by Siddharth Jangid 5 years, 3 months ago
- 2 answers
Posted by Siddharth Jangid 5 years, 3 months ago
- 1 answers
Yogita Ingle 5 years, 3 months ago
Using the section formula, if a point (x,y) divides the line joining the
points (x1,y1) and (x2,y2) internally in the
ratio m:n, then (x,y)=(mx2+nx1)/m+n ,(my2+ny1)/m+n
Substituting (x1,y1)=(7,−6) and (x2,y2)=(3,4) and m=1,n=2 in the section formula, we get
After solving we get x = 17/3 and y = -8/3
Since, x− cordinate is positive and y− cordinate is negative, the point lies in the IV quadrant.
Posted by Siddharth Jangid 5 years, 3 months ago
- 3 answers
Yogita Ingle 5 years, 3 months ago
a=10 and d=10
a1 = 10
a2 = a1 + d = 10 + 10 = 20
a3 = a2 + d = 20 + 10 = 30
a4 = a3 + d = 30 + 10 = 40
If a=10 and d=10, then first four terms will be: 10, 20, 30, 40,.........
Posted by Siddharth Jangid 5 years, 3 months ago
- 1 answers
Yogita Ingle 5 years, 3 months ago
Let the points A(-4,0),B(4,0)and C(0,3)are the vertices
∴AB=√(4−(−4))2+(0−0)2=√(8)2=√64=8
∴BC=√(0−4)2+(0−3)2= √16+9 = √25 = 5
∴CA=√(−4−0)2+(0−3)2=√16+9=√25=5
As we know that two points are equal in the given vertices
∴This is the vertices of a isosceles triangle.
Posted by Siddharth Jangid 5 years, 3 months ago
- 1 answers
Posted by Siddharth Jangid 5 years, 3 months ago
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Boobala Guru 5 years, 3 months ago
Posted by Siddharth Jangid 5 years, 3 months ago
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Posted by Siddharth Jangid 5 years, 3 months ago
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Posted by Siddharth Jangid 5 years, 3 months ago
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Posted by Siddharth Jangid 5 years, 3 months ago
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Riya Sharma 5 years, 3 months ago
2Thank You