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Posted by Chavdhari Anandiben 5 years, 4 months ago (9626051)
- 2 answers
Posted by Riya Tiwari 5 years, 4 months ago (9691889)
- 1 answers
Yogita Ingle 5 years, 4 months ago (2577571)
By using Euclids division algorithm
a = bq+r
where a is > b
so a = 867 and b=255
867=255 × 3+102
here r≠0 so a=255 and b=102
255=102×2+51
here r≠0 so a=102 and b=51
102=51×2+0
here r=0
so, Hcf of (867,255) is =51
Posted by Naveen Vijai 5 years, 4 months ago (9702479)
- 2 answers
Posted by Sukh Dhillon 5 years, 4 months ago (9711052)
- 0 answers
Posted by Niranjan Kumar 5 years, 4 months ago (9545174)
- 0 answers
Posted by Pranjal Jangid 5 years, 4 months ago (8682029)
- 1 answers
Yogita Ingle 5 years, 4 months ago (2577571)
kx2 + x -6 =0
put x =-2
k(-2)2 + (-2) - 6=0
4k -2 -6 = 0
4k - 8 = 0
4k = 8
Therefore,
k = 2
Posted by Pranjal Jangid 5 years, 4 months ago (8682029)
- 1 answers
Yogita Ingle 5 years, 4 months ago (2577571)
As given, points A( 1 , -2 ) ,B ( 3 , 6 ) and C ( 5 , 10 )
Let us assume that the vertex of point D is (x, y)
We know diagonal bisects each other,
So mid-point of AC = mid-point of BD……………. ( i )
Now, mid-point of
And mid-point of {tex}\mathrm{BD}=\frac{3+x}{2}, \frac{6+y}{2}{/tex}
Hence from equation (i) we can conclude that,
3+x=6
x=3
6+y=8
y=2
So vertex of D = (3, 2)
Posted by Pranjal Jangid 5 years, 4 months ago (8682029)
- 1 answers
Yogita Ingle 5 years, 4 months ago (2577571)
a = 1 d = 4-1 = 3
an = a + (n-1)d
a20 = 1 + (20-1)3
a20 = 1 + (19)3
a20= 1 + 57
a20= 58
Posted by Pranjal Jangid 5 years, 4 months ago (8682029)
- 0 answers
Posted by Pranjal Jangid 5 years, 4 months ago (8682029)
- 1 answers
Gaurav Seth 5 years, 3 months ago (2898529)
Given AP is 1,4,7,10,.....
In given AP first term a=1, common difference d=3
Since, Sn= n/2[2a+(n−1)d] ....... sum of n terms
Put n=20 for sum of first 20 terms
S20=20/2 [2(1)+(20−1)3]
S20=10[2+57]
S20=590
Posted by Pranjal Jangid 5 years, 4 months ago (8682029)
- 1 answers
Yogita Ingle 5 years, 4 months ago (2577571)
Sum of first 5 multiples of 3:
Sum of an AP is: n/2 × (2a+(n−1)d)
a=3,d=3,n=5
Then,
Sum = 5/2 ×(2×3+(5−1)×(3))
= 5/2 ×(6+12)
= 5/2 ×18
= 5 ×9
= 45
Posted by Pranjal Jangid 5 years, 4 months ago (8682029)
- 1 answers
Gaurav Seth 5 years, 3 months ago (2898529)
let a = first term and d=common difference.
According to question,
7a7 = 11 a11
=>7(a+6d) = 11(a+10d)
=> 7a-11a = 110d-42d
=> -4a = 68d
=>a = -17d ......(1)
Now , a18 = a +17d
but a = -17 d ..by (1)
so put this value , we get,
a18=-17d +17d =0
Hence proved
Posted by Ilsha Hareez 5 years, 4 months ago (7774327)
- 0 answers
Posted by Pranjal Jangid 5 years, 4 months ago (8682029)
- 1 answers
Yogita Ingle 5 years, 4 months ago (2577571)
a = 1 d = 4-1 = 3
an = a + (n-1)d
a10 = 1 + (10-1)3
a10 = 1 + (9)3
a10= 1 + 27
a10= 28
Posted by Pranjal Jangid 5 years, 4 months ago (8682029)
- 1 answers
Gaurav Seth 5 years, 3 months ago (2898529)
When a, b, and c are real numbers, a ≠ 0 and the discriminant is zero, then the roots α and β of the quadratic equation ax2+ bx + c = 0 are real and equal.
Posted by Pranjal Jangid 5 years, 4 months ago (8682029)
- 2 answers
Yogita Ingle 5 years, 4 months ago (2577571)
A quadratic polynomial has maximum three zeroes.
False, A quadratic polynomial has two zeroes.
Posted by Pranjal Jangid 5 years, 4 months ago (8682029)
- 0 answers
Posted by Keshav Maratha 5 years, 4 months ago (8824685)
- 4 answers
Posted by Pranjal Jangid 5 years, 4 months ago (8682029)
- 0 answers
Posted by Pranjal Jangid 5 years, 4 months ago (8682029)
- 2 answers
Yogita Ingle 5 years, 4 months ago (2577571)
If b2 - 4ac = 0 then the roots will be a real number because b and a are real.
Posted by Pema Chojiom 5 years, 4 months ago (9487558)
- 5 answers
09 Nitika Narayan Singh 6B 5 years, 4 months ago (9688846)
Posted by Mihir Nimgani 5 years, 4 months ago (9709507)
- 1 answers
Meghna Thapar 5 years, 4 months ago (6237)
The discount method refers to the sale of a bond at a discount to its face value, so that an investor can realize a greater effective interest rate. This approach yields a higher effective interest rate to the lender, since the interest payment is calculated based on a higher amount than was paid to the lender. Remember the formula for finding the discount price of an item. Where S = sale price, r = discount percentage rate and p = original price, the discount formula is: S = p - rp.
Posted by Pranjal Jangid 5 years, 4 months ago (8682029)
- 1 answers
Yogita Ingle 5 years, 4 months ago (2577571)
(cosecA-cotA) (cosecA+cotA)
= cosec2 A - Cot2A
= cot2A + 1 - Cot2A (cot2A + 1 = cosec2A)
= 1
Posted by Pranjal Jangid 5 years, 4 months ago (8682029)
- 0 answers
Posted by Pranjal Jangid 5 years, 4 months ago (8682029)
- 1 answers
Yogita Ingle 5 years, 4 months ago (2577571)
If sino = 3/5
Then, opposite side of the right angled triangle containing angle o = 3 and hypotenuse =5
Using pythagoras theorem, we get the adjacent side = 4
Now we have, coso =Adjacent/Hypotenuse=4/5
And cot o =Adjacent/Opposite= 3/4
3 cot o =3( 3/4) = 9/4
Posted by Pranjal Jangid 5 years, 4 months ago (8682029)
- 0 answers
Posted by Nikhil Bhaskar 5 years, 4 months ago (7536680)
- 1 answers
Yogita Ingle 5 years, 4 months ago (2577571)
Difference between Bar Diagram and Histogram:
(i) The spacing and the width or the area of bars are all arbitrary. It is the height and not the width or the area of the bar that really matters. But the width in a histogram is as important as its height.
(ii) Bar diagram can be drawn both for discrete and continous variables but histogram is drawn only for a continuous variables.
(iii) In bar diagram some space must be left between consecutive bars; but in histogram no space is, left between two rectangles.
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Yunus Khan 5 years, 4 months ago (4055530)
1 Thank You