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NCERT solutions for Class 8 Maths Comparing Quantities Download as PDF
NCERT Solutions for Class 8 Maths Comparing Quantities
Class –VIII Mathematics (Ex. 8.2)
NCERT SOLUTION
1. A man got 10% increase in his salary. If his new salary is Rs.1,54,000, find his original salary.
Ans. Let original salary be Rs.100.
Therefore New salary i.e., 10% increase
= 100 + 10 = Rs.110
New salary is Rs.110, when original salary = Rs.100
New salary is Rs.1, when original salary =
New salary is Rs.1,54,000, when original salary = = Rs.1,40,000
Hence original salary is Rs. 1,40,000.
NCERT Solutions for Class 8 Maths Exercise 8.2
2. On Sunday 845 people went to the Zoo. On Monday only 169 people went. What is the percent decrease in the people visiting the Zoo on Monday?
Ans. On Sunday, people went to the Zoo
= 845
On Monday, people went to the Zoo = 169
Number of decrease in the people
= 845 – 169 = 676
Decrease percent = = 80%
Hence decrease in the people visiting the Zoo is 80%.
3. A shopkeeper buys 80 articles for Rs.2,400 and sells them for a profit of 16%. Find the selling price of one article.
Ans. No. of articles = 80
Cost Price of articles = Rs. 2,400And Profit
= 16%
Cost price of articles is Rs.100, then selling price = 100 + 16 = Rs.116
Cost price of articles is Rs.1, then selling price =
Cost price of articles is Rs.2400, then selling price = = Rs.2784
Hence, Selling Price of 80 articles = Rs.2784
Therefore Selling Price of 1 article
= = Rs.34.80
4. The cost of an article was Rs.15,500, Rs.450 were spent on its repairs. If it sold for a profit of 15%, find the selling price of the article.
Ans. Here, C.P. = Rs.15,500 and Repair cost = Rs.450
Therefore Total Cost Price = 15500 + 450 = Rs.15,950
Let C.P be Rs.100, then S.P. = 100 + 15
= Rs.115
When C.P. is Rs.100, then S.P. = Rs.115
When C.P. is Rs.1, then S.P. =
When C.P. is Rs.15950, then S.P.
= = Rs.18,342.50
NCERT Solutions for Class 8 Maths Exercise 8.2
5. A VCR and TV were bought for Rs.8,000 each. The shopkeeper made a loss of 4% on the VCR and a profit of 8% on the TV. Find the gain or loss percent on the whole transaction.
Ans. Cost price of VCR = Rs.8000 and Cost price of TV = Rs.8000
Total Cost Price of both articles
= Rs.8000 + Rs.8000 = Rs. 16,000
Now VCR is sold at 4% loss.
Let C.P. of each article be Rs.100, then S.P. of VCR = 100 – 4 = Rs.96
When C.P. is Rs.100, then S.P. = Rs.96
When C.P. is Rs.1, then S.P. =
When C.P. is Rs.8000, then S.P.
= = Rs.7,680
And TV is sold at 8% profit, then S.P. of TV = 100 + 8 = Rs.108
When C.P. is Rs.100, then S.P. = Rs.108
When C.P. is Rs.1, then S.P. =
When C.P. is Rs.8000, then S.P.
= = Rs.8,640
Then, Total S.P.
= Rs.7,680 + Rs.8,640 = Rs. 16,320
Since S.P. >C.P.,
Therefore Profit = S.P. – C.P.
= 16320 – 16000 = Rs.320
And Profit% =
== 2%
NCERT Solutions for Class 8 Maths Exercise 8.2
6. During a sale, a shop offered a discount of 10% on the marked prices of all the items. What would a customer have to pay for a pair of jeans marked at Rs.1450and two shirts marked at Rs.850 each?
Ans. Rate of discount on all items = 10%
Marked Price of a pair of jeans = Rs.1450 and Marked Price of a shirt = Rs.850
Discount on a pair of jeans
= = Rs.145
S.P. of a pair of jeans = Rs.1450 – Rs.145
= Rs.1305
Marked Price of two shirts =
= Rs.1700
Discount on two shirts =
= Rs.170
S.P. of two shirts = Rs.1700 – Rs.170
= Rs.1530
Therefore the customer had to pay
= 1305 + 1530
= Discount on a pair of jeans
=
= Rs.145
S.P. of a pair of jeans
= Rs.1450 – Rs.145 = Rs.2,835
NCERT Solutions for Class 8 Maths Exercise 8.2
37. A milkman sold two of his buffaloes for Rs.20,000 each. On one he made a gain of 5% and on the other a loss of 10%. Find his overall gain or loss. (Hint: Find CP of each)
Ans. S.P. of each buffalo = Rs.20,000
S.P. of two buffaloes =
= Rs.40,000
One buffalo is sold at 5% gain.
Let C.P. be Rs.100, then S.P. = 100 + 5
= Rs.105
When S.P. is Rs.105, then C.P. = Rs.100
When S.P. is Rs.1, then C.P. =
When S.P. is Rs.20,000, then C.P.
= = Rs.19,047.62
Another buffalo is sold at 10% loss.
Let C.P. be Rs.100, then S.P. = 100 – 10
= Rs.90
When S.P. is Rs.90, then C.P. = Rs.100
When S.P. is Rs.1, then C.P. =
When S.P. is Rs.20,000, then C.P.
= = Rs.22,222.22
Total C.P. = Rs.19,047.62 + Rs.22,222.22
= Rs.41,269.84
Since C.P. >S.P.
Therefore here it is loss.
Loss = C.P. – S.P.
= Rs.41,269.84 – Rs. 40,000.00 = Rs.1,269.84
NCERT Solutions for Class 8 Maths Exercise 8.2
8. The price of a TV is Rs.13,000. The sales tax charged on it is at the rate of 12%. Find the amount that Vinod will have to pay if he buys it.
Ans. C.P. = Rs.13,000 and S.T. rate = 12%
Let C.P. be Rs.100, then S.P. for purchaser
= 100 + 12 = Rs.112
When C.P. is Rs.100, then S.P. = Rs.112
When C.P. is Rs.1, then S.P. =
When C.P. is Rs.13,000, then S.P.
= = Rs.14,560
NCERT Solutions for Class 8 Maths Exercise 8.2
9. Arun bought a pair of skates at a sale where the discount given was 20%. If the amount he pays is Rs.1,600, find the marked price.
Ans. S.P. = Rs.1,600 and Rate of discount
= 20%
Let M.P. be Rs.100, then S.P. for customer
= 100 – 20 = Rs.80
When S.P. is Rs.80, then M.P. = Rs.100
When S.P. is Rs.1, then M.P. =
When S.P. is Rs.1600, then M.P.
= = Rs.2,000
NCERT Solutions for Class 8 Maths Exercise 8.2
10. I purchased a hair-dryer for Rs.5,400 including 8% VAT. Find the price before VAT was added.
Ans. C.P. = Rs.5,400 and Rate of VAT = 8%
Let C.P. without VAT is Rs. 100, then price including VAT = 100 + 8 = Rs.108
When price including VAT is Rs.108, then original price = Rs.100
When price including VAT is Rs.1, then original price =
When price including VAT is Rs.5400, then original price = = Rs.5000
NCERT Solutions for Class 8 Maths Exercise 8.2
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