NCERT Solutions for Class 7 Maths Exercise 10.5

NCERT Solutions for Class 7 Maths Exercise 10.5 book solutions are available in PDF format for free download. These ncert book chapter wise questions and answers are very helpful for CBSE exam. CBSE recommends NCERT books and most of the questions in CBSE exam are asked from NCERT text books. Class 7 Maths chapter wise NCERT solution for Maths Book all the chapters can be downloaded from our website and myCBSEguide mobile app for free.

NCERT solutions for Maths Practical Geometry Download as PDF

NCERT Solutions for Class 7 Maths Practical Geometry

Class –VII Mathematics (Ex. 10.5)

Question 1.Construct the right angled {tex}\Delta {/tex}PQR, where {tex}m\angle {/tex}Q = {tex}{90^ \circ },{/tex} QR = 8 cm and PR = 10 cm.

Answer:

To construct: A right angled triangle PQR where {tex}m\angle {/tex}Q = {tex}{90^ \circ },{/tex} QR = 8 cm and PQ = 10 cm.

Steps of construction:

(a) Draw a line segment QR = 8 cm.

(b) At point Q, draw QX {tex} \bot {/tex} QR.

(c) Taking R as centre, draw an arc of radius 10 cm.

(d) This arc cuts QX at point P.

(e) Join PQ.

It is the required right angled triangle PQR.

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NCERT Solutions for Class 7 Maths Exercise 10.5

Question 2.Construct a right angled triangle whose hypotenuse is 6 cm long and one the legs is 4 cm long.

Answer:

To construct: A right angled triangle DEF where DF = 6 cm and EF = 4 cm

Steps of construction:

(a) Draw a line segment EF = 4 cm.

(b) At point Q, draw EX {tex} \bot {/tex} EF.

(c) Taking F as centre and radius 6 cm, draw an arc. (Hypotenuse)

(d) This arc cuts the EX at point D.

(e) Join DF.

It is the required right angled triangle DEF.

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NCERT Solutions for Class 7 Maths Exercise 10.5

Question 3.Construct an isosceles right angled triangle ABC, where {tex}m\angle {/tex}ACB = {tex}{90^ \circ }{/tex} and AC = 6 cm.

Answer:

To construct: An isosceles right angled triangle ABC where {tex}m\angle {/tex}C = {tex}{90^ \circ },{/tex} AC = BC = 6 cm.

Steps of construction:

(a) Draw a line segment AC = 6 cm.

(b) At point C, draw XC {tex} \bot {/tex} CA.

(c) Taking C as centre and radius 6 cm, draw an arc.

(d) This arc cuts CX at point B.

(e) Join BA.

It is the required isosceles right angled triangle ABC.

NCERT Solutions for Class 7 Maths Exercise 10.5

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