NCERT Solutions for Class 7 Maths Exercise 10.3

NCERT Solutions for Class 7 Maths Exercise 10.3 book solutions are available in PDF format for free download. These ncert book chapter wise questions and answers are very helpful for CBSE exam. CBSE recommends NCERT books and most of the questions in CBSE exam are asked from NCERT text books. Class 7 Maths chapter wise NCERT solution for Maths Book all the chapters can be downloaded from our website and myCBSEguide mobile app for free.

NCERT solutions for Maths Practical Geometry Download as PDF

NCERT Solutions for Class 7 Maths Practical Geometry

Class –VII Mathematics (Ex. 10.3)

Question 1.Construct {tex}\Delta {/tex}DEF such that DE = 5 cm, DF = 3 cm and {tex}m\angle {/tex}EDF = {tex}{90^ \circ }.{/tex}

Answer:

To construct: {tex}\Delta {/tex}DEF where DE = 5 cm, DF = 3 cm and {tex}m\angle {/tex}EDF = {tex}{90^ \circ }.{/tex}

Steps of construction:

(a) Draw a line segment DF = 3 cm.

(b) At point D, draw an angle of {tex}{90^ \circ }{/tex} with the help of compass i.e., {tex}\angle {/tex}XDF = {tex}{90^ \circ }{/tex}.

(c) Taking D as centre, draw an arc of radius 5 cm, which cuts DX at the point E.

(d) Join EF.

It is the required right angled triangle DEF.

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NCERT Solutions for Class 7 Maths Exercise 10.3

Question 2.Construct an isosceles triangle in which the lengths of each of its equal sides is 6.5 cm and the angle between them is {tex}110^\circ .{/tex}

Answer:

To construct: An isosceles triangle PQR where PQ = RQ = 6.5 cm and {tex}\angle {/tex}Q = {tex}110^\circ .{/tex}

Steps of construction:

(a) Draw a line segment QR = 6.5 cm.

(b) At point Q, draw an angle of {tex}110^\circ {/tex} with the

help of protractor, i.e., {tex}\angle {/tex}YQR = {tex}110^\circ .{/tex}

(d) Taking Q as centre, draw an arc with radius

1. cm, which cuts QY at point P. 110{tex}^\circ {/tex}

(e) Join PR

It is the required isosceles triangle PQR.

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NCERT Solutions for Class 7 Maths Exercise 10.3

Question 3.Construct {tex}\Delta {/tex}ABC with BC = 7.5 cm, AC = 5 cm and {tex}m\angle {/tex}C = {tex}{60^ \circ }.{/tex}

Answer:

To construct: {tex}\Delta {/tex}ABC where BC = 7.5 cm, AC = 5 cm and {tex}m\angle {/tex}C = {tex}{60^ \circ }.{/tex}

Steps of construction:

(a) Draw a line segment BC = 7.5 cm.

(b) At point C, draw an angle of {tex}{60^ \circ }{/tex} with the help of protractor, i.e., {tex}\angle {/tex}XCB = {tex}{60^ \circ }.{/tex}

(c) Taking C as centre and radius 5 cm, draw an arc, which cuts XC at the point A.

(d) Join AB

It is the required triangle ABC.

NCERT Solutions for Class 7 Maths Exercise 10.3

NCERT Solutions Class 7 Maths PDF (Download) Free from myCBSEguide app and myCBSEguide website. Ncert solution class 7 Maths includes text book solutions from Class 7 Maths Book . NCERT Solutions for CBSE Class 7 Maths have total 15 chapters. 7 Maths NCERT Solutions in PDF for free Download on our website. Ncert Maths class 7 solutions PDF and Maths ncert class 7 PDF solutions with latest modifications and as per the latest CBSE syllabus are only available in myCBSEguide.

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