NCERT Solutions for Class 7 Maths Exercise 10.2

NCERT Solutions for Class 7 Maths Exercise 10.2 book solutions are available in PDF format for free download. These ncert book chapter wise questions and answers are very helpful for CBSE exam. CBSE recommends NCERT books and most of the questions in CBSE exam are asked from NCERT text books. Class 7 Maths chapter wise NCERT solution for Maths Book all the chapters can be downloaded from our website and myCBSEguide mobile app for free.

NCERT solutions for Maths Practical Geometry Download as PDF

NCERT Solutions for Class 7 Maths Practical Geometry

Class –VII Mathematics (Ex. 10.2)

Question 1.Construct {tex}\Delta {/tex}XYZ in which XY = 4.5 cm, YZ = 5 cm and ZX = 6 cm.

Answer:

To construct: {tex}\Delta {/tex}XYZ, where XY = 4.5 cm, YZ = 5 cm and ZX = 6 cm.

Steps of construction:

(a) Draw a line segment YZ = 5 cm.

(b) Taking Z as centre and radius 6 cm, draw an arc.

(c) Similarly, taking Y as centre and radius 4.5 cm, draw another arc which intersects first arc at point X.

(d) Join XY and XZ.

It is the required {tex}\Delta {/tex}XYZ.

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NCERT Solutions for Class 7 Maths Exercise 10.2

Question 2.Construct an equilateral triangle of side 5.5 cm.

Answer:

To construct: A {tex}\Delta {/tex}ABC where AB = BC = CA = 5.5 cm

Steps of construction:

(a) Draw a line segment BC = 5.5 cm

(b) Taking points B and C as centers and radius 5.5 cm, draw arcs which intersect at point A.

(c) Join AB and AC.

It is the required {tex}\Delta {/tex}ABC.

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NCERT Solutions for Class 7 Maths Exercise 10.2

Question 3.Draw {tex}\Delta {/tex}PQR with PQ = 4 cm, QR = 3.5 cm and PR = 4 cm. What type of triangle is this?

Answer:

To construction: {tex}\Delta {/tex}PQR, in which PQ = 4 cm, QR = 3.5 cm and PR = 4 cm.

Steps of construction:

(a) Draw a line segment QR = 3.5 cm.

(b) Taking Q as centre and radius 4 cm, draw an arc.

(c) Similarly, taking R as centre and radius 4 cm, draw an another arc which intersects first arc at P.

(d) Join PQ and PR.

It is the required isosceles {tex}\Delta {/tex}PQR.

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NCERT Solutions for Class 7 Maths Exercise 10.2

Question 4.Construct {tex}\Delta {/tex}ABC such that AB = 2.5 cm, BC = 6 cm and AC = 6.5 cm. Measure {tex}\angle {/tex}B.

Answer:

To construct :{tex}\Delta {/tex}ABC in which AB = 2.5 cm, BC = 6 cm and AC = 6.5 cm.

Steps of construction:

(a) Draw a line segment BC = 6 cm.

(b) Taking B as centre and radius 2.5 cm, draw an arc.

(c) Similarly, taking C as centre and radius 6.5 cm, draw another arc which intersects first arc at point A.

(d) Join AB and AC.

(e) Measure angle B with the help of protractor.

It is the required {tex}\Delta {/tex}ABC where {tex}\angle {/tex}B = {tex}80^\circ .{/tex}

NCERT Solutions for Class 7 Maths Exercise 10.2

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