# NCERT Solutions for Class 10 Maths Exercise 2.2

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NCERT solutions for Class 10 Maths Polynomials

## NCERT Solutions for Class 10 Maths Polynomials

1. Find the zeroes of the following quadratic polynomials and verify the relationship between the zeros and the coefficients.

(i)

(ii)

(iii)

(iv)

(v)

(vi)

Ans. (i)

Comparing given polynomial with general form ,

We get a = 1, b = -2 and c = -8

We have,

= x(x−4)+2(x−4) = (x−4)(x+2)

Equating this equal to 0 will find values of 2 zeroes of this polynomial.

(x−4)(x+2) = 0

x = 4, −2 are two zeroes.

Sum of zeroes = 4 – 2 = 2 =

=

Product of zeroes = 4 × −2 = −8

=

(ii)

Here, a = 4, b = -4 and c = 1

We have,

=

=2s(2s−1)−1(2s−1)
= (2s−1)(2s−1)

Equating this equal to 0 will find values of 2 zeroes of this polynomial.

⇒ (2s−1)(2s−1) = 0

s =

Therefore, two zeroes of this polynomial are

Sum of zeroes = = 1 =

=

Product of Zeroes =

(iii)

Here, a = 6, b = -7 and c = -3

We have,

= 3x(2x−3)+1(2x−3) = (2x−3)(3x+1)

Equating this equal to 0 will find values of 2 zeroes of this polynomial.

⇒ (2x−3)(3x+1) = 0

x =

Therefore, two zeroes of this polynomial are

Sum of zeroes =

Product of Zeroes =

(iv)

Here, a = 4, b = 8 and c = 0

Equating this equal to 0 will find values of 2 zeroes of this polynomial.

⇒ 4u(u+2) = 0

u = 0,−2

NCERT Solutions for Class 10 Maths Exercise 2.2

Therefore, two zeroes of this polynomial are 0, −2

Sum of zeroes = 0−2 = −2 =

=

Product of Zeroes = 0

=

(v)

Here, a = 1, b = 0 and c = -15

We have, t =

Therefore, two zeroes of this polynomial are

Sum of zeroes =

Product of Zeroes =

(vi)

Here, a = 3, b = -1 and c = -4

We have, =

= x(3x−4)+1(3x−4) = (3x−4)(x+1)

Equating this equal to 0 will find values of 2 zeroes of this polynomial.

⇒ (3x−4)(x+1) = 0

x =

Therefore, two zeroes of this polynomial are

Sum of zeroes =

Product of Zeroes =

NCERT Solutions for Class 10 Maths Exercise 2.2

2. Find a quadratic polynomial each with the given numbers as the sum and product of its zeroes respectively.

(i) , −1

(ii) , 13

(iii) 0,

(iv) 1, 1

(v)

(vi) 4, 1

Ans. (i) , −1

Let α and β are two zeroes of above quadratic polynomial.

α+β = =

α × β = -1 =

Quadratic polynomial which satisfies above conditions =

(ii)

Let α and β be two zeros of above quadratic polynomial.

α+β = =

α × β = which is equal to

Quadratic polynomial which satisfies above conditions =

(iii) 0,

Let α and β be two zeros of above quadratic polynomial.

α+β = 0 =

α β = =

Quadratic polynomial which satisfies above conditions

(iv) 1, 1

Let α and β be two zeros of above quadratic polynomial.

α+β = 1 =

α β = 1 =

Quadratic polynomial which satisfies above conditions =

(v)

Let α and β be two zeros of above quadratic polynomial.

α+β = =

α β = =

Quadratic polynomial which satisfies above conditions =

(vi) 4, 1

Let α and β be two zeros of above quadratic polynomial.

α+β = 4 =

α × β = 1 =

Quadratic polynomial which satisfies above conditions

## NCERT Solutions for Class 10 Maths Exercise 2.2

NCERT Solutions for Class 10 Maths Exercise 2.2 PDF (Download) Free from myCBSEguide app and myCBSEguide website. Ncert solution class 10 Maths includes text book solutions from Mathematics Book. NCERT Solutions for CBSE Class 10 Maths have total 15 chapters. 10 Maths NCERT Solutions in PDF for free Download on our website. Ncert Maths class 10 solutions PDF and Maths ncert class 10 PDF solutions with latest modifications and as per the latest CBSE syllabus are only available in myCBSEguide.

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