NCERT Solutions for Class 6 Maths Exercise 11.3

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NCERT Solutions for Class 6 Maths Exercise 11.3

NCERT Solutions for Class 6 Maths Algebra

Class –VI Mathematics
(Ex. 11.3)
Question 1.Make up as many expressions with numbers (no variables) as you can from three numbers 5, 7 and 8. Every number should be used not more than once. Use only addition, subtraction and multiplication.

(Hint: Three possible expressions are 5 + (8 – 7), 5 – (8 – 7), (5 x 8) + 7 make the other expressions)

Answer:

(a) (8 x 5) – 7

(b) (8 + 5) – 7

(c) (8 x 7) – 5

(d) (8 + 7) – 5

(e) 5 x (7 + 8)

(f) 5 + (7 x 8)

(g) 5 + (8 – 7)

(h) 5 – (7 + 8


NCERT Solutions for Class 6 Maths Exercise 11.3

Question 2.Which out of the following are expressions with numbers only:

(a) {tex}y + 3{/tex}

(b) {tex}\left( {7 \times 20} \right) – 8z{/tex}

(c) {tex}5\left( {21 – 7} \right) + 7 \times 2{/tex}

(d) {tex}5{/tex}

(e) {tex}3x{/tex}

(f) {tex}5 – 5n{/tex}

(g) {tex}\left( {7 \times 20} \right) – \left( {5 \times 10} \right) – 45 + p{/tex}

Answer: (c) and (d)


Question 3.Identify the operations (addition, subtraction, division, multiplication) in forming the following expressions and tell how the expressions have been formed:

(a) {tex}z + 1,z – 1,y + 17,y – 17{/tex}

(b) {tex}17y,\frac{y}{{17}},5z{/tex}

(c) {tex}2y + 17,2y – 17{/tex}

(d) {tex}7m, – 7m + 3, – 7m – 3{/tex}

Answer:

(a){tex}z + 1 \to {/tex} Addition

{tex}z – 1 \to {/tex} Subtraction

{tex}y + 17 \to {/tex} Addition

{tex}y – 17 \to {/tex} Subtraction

(b) {tex}17y \to {/tex} Multiplication

{tex}\frac{y}{{17}} \to {/tex} Division

{tex}5z \to {/tex} Multiplication

(c) {tex}2y + 17 \to {/tex} Multiplication and Addition

{tex}2y – 17 \to {/tex} Multiplication and Subtraction

(d) {tex}7m \to {/tex} Multiplication

{tex} – 7m + 3 \to {/tex} Multiplication and Addition

{tex} – 7m – 3 \to {/tex} Multiplication and Subtraction


NCERT Solutions for Class 6 Maths Exercise 11.3

Question 4.Give expressions for the following cases:

(a) 7 added to {tex}p.{/tex}

(b) 7 subtracted from {tex}p.{/tex}

(c) {tex}p{/tex} multiplied by 7.

(d) {tex}p{/tex} divided by 7.

(e) 7 subtracted from {tex} – m.{/tex}

(f) {tex} – p{/tex} multiplied by 5.

(g) {tex} – p{/tex} divided by 5.

(h) {tex}p{/tex} multiplied by {tex} – 5.{/tex}

Answer:

(a) {tex}p + 7{/tex}

(b) {tex}p – 7{/tex}

(c) {tex}7p{/tex}

(d) {tex}\frac{p}{7}{/tex}

(e) {tex} – m – 7{/tex}

(f) {tex} – 5p{/tex}

(g) {tex}\frac{{ – p}}{5}{/tex}

(h) {tex} – 5p{/tex}


Question 5.Give expression in the following cases:

(a)11 added to {tex}2m.{/tex}

(b)11 subtracted from {tex}2m.{/tex}

(c)5 times {tex}y{/tex} to which 3 is added.

(d)5 times {tex}y{/tex} from which 3 is subtracted.

(e){tex}y{/tex} is multiplied by {tex} – 8.{/tex}

(f){tex}y{/tex} is multiplied by {tex} – 8{/tex} and then 5 is added to the result.

(g){tex}y{/tex} is multiplied by 5 and result is subtracted from 16.

(h){tex}y{/tex} is multiplied by {tex} – 5{/tex} and the result is added to 16.

Answer:

(a) {tex}2m + 11{/tex}

(b) {tex}2m – 11{/tex}

(c) {tex}5y + 3{/tex}

(d) {tex}5y – 3{/tex}

(e) {tex} – 8y{/tex}

(f) {tex} – 8y + 5{/tex}

(g) {tex}16 – 5y{/tex}

(h) {tex} – 5y + 16{/tex}


NCERT Solutions for Class 6 Maths Exercise 11.3

Question 7.

(a) From expressions using {tex}t{/tex} and 4. Use not more than one number operation. Every expression must have {tex}t{/tex} in it.

(b) Form expressions using {tex}y,{/tex} 2 and 7. Every expression must have {tex}y{/tex} in it. Use only two number operations. These should be different.

Answer:

(a) {tex}t + 4,t – 4,4 – t,4t,\frac{t}{4},\frac{4}{t}{/tex}

(b) {tex}2y + 7,2y – 7,7y + 2,7y – 2{/tex} and so on

NCERT Solutions for Class 6 Maths Exercise 11.3

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