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Install Now17. If are in G.P., prove that are in G.P.
Ans. Given: are in G.P.
To prove: are in G.P.
Let
And
Also
Now,
Therefore, are in G.P.
18. If and are the roots and are roots of where form a G.P. Prove that
Ans. Let
And
Also
and are the roots
……….(i)
And
……….(ii)
Also are roots of
……….(iii)
And
……….(iv)
Dividing eq. (iii) by eq. (i),
Now
=
Therefore,
19. The ratio of the A.M. and G.M. of two positive numbers and is Show that =
Ans. Given:
By component and dividend,
Again by component and dividend,
Therefore, =
20. If are in A.P.; are in G.P. and are in A.P., prove that are in G.P.
Ans. Since, are in A.P.
Since, are in G.P.
……….(i)
Also are in A.P.
Putting values of and in eq. (i),
which shows that are in G.P.
21. Find the sum of the following series up to terms:
(i) 5 + 55 + 555 + ……….
(ii) .6 + .66 + .666 + ………….
Ans. (i) = 5 + 55 + 555 + ………. up to terms
= 5 [1 + 11 + 111 + ………. up to terms]
=
=
=
=
=
(ii) = .6 + .66 + .666 + …………. up to terms
= 6 [.1 + .11 + .111 + ………. up to terms]
=
=
=
=
=
=
=
22. Find the 20th term of the series terms.
Ans. Given: terms
=
23. Find the sum of the first terms of the series: 3 + 7 + 13 + 21 + 21 + ……….
Ans. Given: ……….(i)
Also ……….(ii)
Subtracting eq. (ii) from eq. (i),
=
=
=
=
=
=
=
24. If are the sum of first natural numbers, their squares and their cubes respectively, show that
Ans. Here , and
Now,
Proved.
25. Find the sum of the following series up to terms:
Ans. Given: up to terms
=
=
=
=
=
=
=
26. Show that
Ans. Given:
= =
=
=
=
= = =
27. A farmer buys a used tractor for Rs. 12000. He pays Rs. 6000 cash and agrees to pay the balance in annual installments of Rs. 500 plus 12% interest on the unpaid amount. How much will the tractor cost him?
Ans. Total cost of the tractor = Rs. 12000, Cash amount paid = Rs. 6000
Balance amount = 12000 – 6000 = Rs. 6000
Interest of 1st installment = = Rs. 720
Amount of 1st installment = 500 + 720 = Rs. 1220
Interest of 2nd installment = = Rs. 660
Amount of 2nd installment = 500 + 660 = Rs. 1160
Interest of 3rd installment = = Rs. 600
Amount of 3rd installment = 500 + 600 = Rs. 1100
Sequence of installments is 1220, 1160, 1100, ……….
Here, and
=
= 6 [2440 – 660] = Rs. 10680
Therefore, the total cost of tractor is (10680 + 6000) = Rs. 16680.
28. Shams had Ali buys a scooter for Rs. 22000. He pays Rs. 4000 cash and agrees to pay the balance in annual installment of Rs. 1000 plus 10% interest on the unpaid amount. How much will the scooter cost him?
Ans. Total cost of the scooter = Rs. 22000, Cash amount paid = Rs. 4000
Balance amount = 22000 – 4000 = Rs. 18000
Interest of 1st installment = = Rs. 1800
Amount of 1st installment = 1000 + 1800 = Rs. 2800
Interest of 2nd installment = = Rs. 1700
Amount of 2nd installment = 1000 + 1700 = Rs. 2700
Interest of 3rd installment = = Rs. 1600
Amount of 3rd installment = 1000 + 1600 = Rs. 2600
Sequence of installments is 2800, 2700, 2600, ……….
Here, and
=
= 9 [5600 – 1700] = Rs. 35100
Therefore, the total cost of tractor is (35100 + 4000) = Rs. 39100.
29. A person writes a letter to four of his friends. He asks each one of them to copy the letter and mail to four different persons with instruction that they move the chain similarly. Assuming that the chain is not broken and that it costs 50 paise to mail one letter. Find the amount spent on the postage when 8th set of letter is mailed.
Ans. Total letters in the first set = 4, Total letters in the second set = = 16
Total letters in the third set = = 64
Sequence of letters is 4, 16, 64, ………. In G.P.
Here and
=
=
= = 87380
Since, the amount of postage on each letter is 50 paise.
Therefore, amount spent on postage = = Rs. 43690.
30. A man deposited Rs. 10000 in a bank at the rate of 5% simple interest annually. Find the amount in 15th year since he deposited the amount and also calculate the total amount after 20 years.
Ans. Total amount deposited = Rs. 10000, Rate of interest = 5% per annum
Interest of first year = = Rs. 500
Here
Amount in 15th year = = 10000 + 7000 = Rs. 17000
Total amount after 20 years =
= 10 (20000 + 9500) = Rs. 295000
31. A manufacturer reckons that the value of a machine, which cost him Rs. 15625 will depreciate each year by 20%. Find the estimated value at the end of 5 years.
Ans. After 1 year value of machine = = 15625 – 3125 = Rs. 12500
After 2 year value of machine = = 12500 – 2500 = Rs. 10000
After 3 year value of machine = = 10000 – 2000 = Rs. 8000
Sequence of values of machine is 12500, 10000, 8000, ……. in G.P.
Here and
= = Rs. 5120
Therefore, the value of machine at the end of 5 years is Rs. 5120.
32. 150 workers were engaged to finish a job in a certain number of boys. 4 workers dropped out on second day, 4 more workers dropped out on third day and so on. It took 8 more days to finish the work find the number of days in which the work was completed.
Ans. Number of workers on the first day = 150
Number of workers on the second day = 150 – 4 = 146
Number of workers on the third day = 146 – 4 = 142
Sequence of values of workers is 150, 146, 142, ……… in A.P.
Here
Total number of workers required to finish the work in days
=
= ……….(i)
If no worker had dropped out, then
Total number of workers required to finish the work days = ……….(ii)
From eq. (i) and (ii),
and which is not possible
Therefore, the work is completed in 25 days.
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