NCERT Solutions for Class 6 Maths Exercise 11.3

NCERT Solutions for Class 6 Maths Exercise 11.3 book solutions are available in PDF format for free download. These ncert book chapter wise questions and answers are very helpful for CBSE exam. CBSE recommends NCERT books and most of the questions in CBSE exam are asked from NCERT text books. Class 6 Maths chapter wise NCERT solution for Maths Book all the chapters can be downloaded from our website and myCBSEguide mobile app for free.

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NCERT Solutions for Class 6 Maths Algebra

Class –VI Mathematics

(Ex. 11.3)

Question 1.Make up as many expressions with numbers (no variables) as you can from three numbers 5, 7 and 8. Every number should be used not more than once. Use only addition, subtraction and multiplication.

(Hint: Three possible expressions are 5 + (8 – 7), 5 – (8 – 7), (5 x 8) + 7 make the other expressions)

Answer:

(a) (8 x 5) – 7

(b) (8 + 5) – 7

(c) (8 x 7) – 5

(d) (8 + 7) – 5

(e) 5 x (7 + 8)

(f) 5 + (7 x 8)

(g) 5 + (8 – 7)

(h) 5 – (7 + 8

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NCERT Solutions for Class 6 Maths Exercise 11.3

Question 2.Which out of the following are expressions with numbers only:

(a) {tex}y + 3{/tex}

(b) {tex}\left( {7 \times 20} \right) – 8z{/tex}

(c) {tex}5\left( {21 – 7} \right) + 7 \times 2{/tex}

(d) {tex}5{/tex}

(e) {tex}3x{/tex}

(f) {tex}5 – 5n{/tex}

(g) {tex}\left( {7 \times 20} \right) – \left( {5 \times 10} \right) – 45 + p{/tex}

Answer: (c) and (d)

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Question 3.Identify the operations (addition, subtraction, division, multiplication) in forming the following expressions and tell how the expressions have been formed:

(a) {tex}z + 1,z – 1,y + 17,y – 17{/tex}

(b) {tex}17y,\frac{y}{{17}},5z{/tex}

(c) {tex}2y + 17,2y – 17{/tex}

(d) {tex}7m, – 7m + 3, – 7m – 3{/tex}

Answer:

(a){tex}z + 1 \to {/tex} Addition

{tex}z – 1 \to {/tex} Subtraction

{tex}y + 17 \to {/tex} Addition

{tex}y – 17 \to {/tex} Subtraction

(b) {tex}17y \to {/tex} Multiplication

{tex}\frac{y}{{17}} \to {/tex} Division

{tex}5z \to {/tex} Multiplication

(c) {tex}2y + 17 \to {/tex} Multiplication and Addition

{tex}2y – 17 \to {/tex} Multiplication and Subtraction

(d) {tex}7m \to {/tex} Multiplication

{tex} – 7m + 3 \to {/tex} Multiplication and Addition

{tex} – 7m – 3 \to {/tex} Multiplication and Subtraction

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NCERT Solutions for Class 6 Maths Exercise 11.3

Question 4.Give expressions for the following cases:

(a) 7 added to {tex}p.{/tex}

(b) 7 subtracted from {tex}p.{/tex}

(c) {tex}p{/tex} multiplied by 7.

(d) {tex}p{/tex} divided by 7.

(e) 7 subtracted from {tex} – m.{/tex}

(f) {tex} – p{/tex} multiplied by 5.

(g) {tex} – p{/tex} divided by 5.

(h) {tex}p{/tex} multiplied by {tex} – 5.{/tex}

Answer:

(a) {tex}p + 7{/tex}

(b) {tex}p – 7{/tex}

(c) {tex}7p{/tex}

(d) {tex}\frac{p}{7}{/tex}

(e) {tex} – m – 7{/tex}

(f) {tex} – 5p{/tex}

(g) {tex}\frac{{ – p}}{5}{/tex}

(h) {tex} – 5p{/tex}

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Question 5.Give expression in the following cases:

(a)11 added to {tex}2m.{/tex}

(b)11 subtracted from {tex}2m.{/tex}

(c)5 times {tex}y{/tex} to which 3 is added.

(d)5 times {tex}y{/tex} from which 3 is subtracted.

(e){tex}y{/tex} is multiplied by {tex} – 8.{/tex}

(f){tex}y{/tex} is multiplied by {tex} – 8{/tex} and then 5 is added to the result.

(g){tex}y{/tex} is multiplied by 5 and result is subtracted from 16.

(h){tex}y{/tex} is multiplied by {tex} – 5{/tex} and the result is added to 16.

Answer:

(a) {tex}2m + 11{/tex}

(b) {tex}2m – 11{/tex}

(c) {tex}5y + 3{/tex}

(d) {tex}5y – 3{/tex}

(e) {tex} – 8y{/tex}

(f) {tex} – 8y + 5{/tex}

(g) {tex}16 – 5y{/tex}

(h) {tex} – 5y + 16{/tex}

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NCERT Solutions for Class 6 Maths Exercise 11.3

Question 7.

(a) From expressions using {tex}t{/tex} and 4. Use not more than one number operation. Every expression must have {tex}t{/tex} in it.

(b) Form expressions using {tex}y,{/tex} 2 and 7. Every expression must have {tex}y{/tex} in it. Use only two number operations. These should be different.

Answer:

(a) {tex}t + 4,t – 4,4 – t,4t,\frac{t}{4},\frac{4}{t}{/tex}

(b) {tex}2y + 7,2y – 7,7y + 2,7y – 2{/tex} and so on

NCERT Solutions for Class 6 Maths Exercise 11.3

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