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NCERT Solutions class 12 Maths Exercise 4.3

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NCERT Solutions class 12 Maths Exercise 4.3 Class 12 Maths book solutions are available in PDF format for free download. These ncert book chapter wise questions and answers are very helpful for CBSE board exam. CBSE recommends NCERT books and most of the questions in CBSE exam are asked from NCERT text books. Class 12 Maths chapter wise NCERT solution for Maths part 1 and Maths part 2 for all the chapters can be downloaded from our website and myCBSEguide mobile app for free.

Download NCERT solutions for Determinants  as PDF

NCERT Solutions class 12 Maths Exercise 4.3

NCERT Solutions class 12 Maths Determinants

1. Find the area of the triangle with vertices at the points given in each of the following:

(i) (1, 0), (6, 0), (4, 3)

(ii) (2, 7), (1, 1), (10, 8)

(iii)  

Ans. (i) Area of triangle = Modulus of  =

=  =  =  =  sq. units

(ii) Area of triangle = Modulus of  =

=  =

=  =

=  =  sq. units

(iii) Area of triangle = Modulus of  =

=

=

=

=

=  = 15 sq. units


NCERT Solutions class 12 Maths Exercise 4.3

2. Show that the points A B C are collinear.

Ans. Area of triangle ABC = Modulus of  =

=

=

=

=  = 0

Therefore, points A, B and C are collinear.


NCERT Solutions class 12 Maths Exercise 4.3

3. Find values of  if area of triangle is 4 sq. units and vertices are:

(i)  

(ii)  

Ans. (i) Given: Area of triangle = Modulus of  = 4

 Modulus of  = 4

 

 

 

 

Taking positive sign,

 

Taking negative sign,

 

(ii) Given: Area of triangle = Modulus of  = 4

  = 4

 

 

 

 

Taking positive sign,

 

Taking negative sign,

 


NCERT Solutions class 12 Maths Exercise 4.3

4. (i) Find the equation of the line joining (1, 2) and (3, 6) using determinants.

(ii) Find the equation of the line joining (3, 1) and (9, 3) using determinants.

Ans. (i) Let P be any point on the line joining the points (1, 2) and (3, 6).

Then, Area of triangle that could be formed by these points is zero.

 Area of triangle = Modulus of  = 0

 Modulus of  = 0

 

 

 

  which is required line.

(ii) Let P be any point on the line joining the points (3, 1) and (9, 3).

Then, Area of triangle that could be formed by these points is zero.

 Area of triangle = Modulus of  = 0

 Modulus of  = 0

 

 

 

   which is required line.


NCERT Solutions class 12 Maths Exercise 4.3

5. If area of triangle is 35 sq. units with vertices  and  Then  is:

(A) 12

(B)  

(C)  

(D)  

Ans. Given: Area of triangle = Modulus of  = 35

 Modulus of  = 35

 

 

 

 

 

Taking positive sign,

 

Taking negative sign,

 

Therefore, option (D) is correct.

NCERT Solutions class 12 Maths Exercise 4.3

NCERT Solutions Class 12 Maths PDF (Download) Free from myCBSEguide app and myCBSEguide website. Ncert solution class 12 Maths includes text book solutions from both part 1 and part 2. NCERT Solutions for CBSE Class 12 Maths have total 20 chapters. 12 Maths NCERT Solutions in PDF for free Download on our website. Ncert Maths class 12 solutions PDF and Maths ncert class 12 PDF solutions with latest modifications and as per the latest CBSE syllabus are only available in myCBSEguide

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