Exercise 11.3
In each of the Exercises 1 to 9, find the coordinates of the foci, the vertices, the length of major axis, the minor axis, the eccentricity and the length of the latus rectum of the ellipse.
1. 
Ans. Given: Equation of ellipse: 
36 > 16




Now
= 
Coordinates of foci are 


Coordinates of vertices are 


Length of major axis =
= 
Length of minor axis =
= 
Eccentricity 
Length of latus rectum = 
2. 
Ans. Given: Equation of ellipse: 
25 > 4 



Now
= 
Coordinates of foci are 


Coordinates of vertices are 


Length of major axis =
= 
Length of minor axis =
= 
Eccentricity 
Length of latus rectum = 
3. 
Ans. Given: Equation of ellipse: 
16 > 9 



Now
= 
Coordinates of foci are 


Coordinates of vertices are 


Length of major axis =
= 
Length of minor axis =
= 
Eccentricity 
Length of latus rectum = 
4. 
Ans. Given: Equation of ellipse: 
100 > 25 



Now
= 
Coordinates of foci are 


Coordinates of vertices are 


Length of major axis =
= 
Length of minor axis =
= 
Eccentricity 
Length of latus rectum = 
5. 
Ans. Given: Equation of ellipse: 
49 > 36 



Now
= 
Coordinates of foci are 


Coordinates of vertices are 


Length of major axis =
= 
Length of minor axis =
= 
Eccentricity 
Length of latus rectum = 
6. 
Ans. Given: Equation of ellipse: 
400 > 100 



Now
= 
Coordinates of foci are 


Coordinates of vertices are 


Length of major axis =
=
Length of minor axis =
= 
Eccentricity 
Length of latus rectum = 
7. 
Ans. Given: Equation of ellipse: 




36 > 4 



Now
= 
Coordinates of foci are 


Coordinates of vertices are 


Length of major axis =
= 
Length of minor axis =
= 
Eccentricity 
Length of latus rectum = 
8. 
Ans. Given: Equation of ellipse: 




16 > 1 



Now
= 
Coordinates of foci are 


Coordinates of vertices are 


Length of major axis =
= 
Length of minor axis =
= 
Eccentricity 
Length of latus rectum = 
9. 
Ans. Given: Equation of ellipse: 




9 > 4 



Now
= 
Coordinates of foci are 


Coordinates of vertices are 


Length of major axis =
= 
Length of minor axis =
= 
Eccentricity 
Length of latus rectum = 
In each of the Exercises 10 to 20, find the equation of the ellipse that satisfies the given conditions:
10. Vertices
foci 
Ans. Since foci
lie on
axis, therefore equation of ellipse is 
Now Vertices 



And Foci 







Therefore, the required equation of ellipse is
.
11. Vertices
foci 
Ans. Since foci
lie on
axis, therefore equation of ellipse is 
Now Vertices 



And Foci 








Therefore, the required equation of ellipse is
.
12. Vertices
foci 
Ans. Since foci
lie on
axis, therefore equation of ellipse is 
Now Vertices 



And Foci 








Therefore, the required equation of ellipse is
.
13. Ends of major axis
ends of minor axis 
Ans. Ends of major axis
lie on
axis, therefore equation of ellipse is 
Now Ends of major axis 



And Ends of minor of axis 



Therefore, the required equation of ellipse is
.
14. Ends of major axis
ends of minor axis 
Ans. Ends of major axis
lie on
axis, therefore equation of ellipse is 
Now Ends of major axis 



And Ends of minor of axis 



Therefore, the required equation of ellipse is
.
15. Length of major axis 26, foci 
Ans. Since foci
lie on
axis, therefore equation of ellipse is 
Length of major axis = 


Foci
= 





Therefore, the required equation of ellipse is
.
16. Length of minor axis 16, foci 
Ans. Since foci
lie on
axis, therefore equation of ellipse is 
Length of major axis = 


Foci
= 





Therefore, the required equation of ellipse is
.
17. Foci

Ans. Since foci
lie on
axis, therefore equation of ellipse is 
Foci
= 





Therefore, the required equation of ellipse is
.
18.
centre at origin; foci on
axis
Ans. Since foci lie on
axis, therefore equation of ellipse is 




Therefore, the required equation of ellipse is
.
19. Centre at (0, 0), major axis on the
axis and passes through the points (3, 2) and (1, 6).
Ans. Since the major axis is along
axis, therefore equation of ellipse is 
And the ellipse passes through the point (3, 2) therefore
…..(i)
And the ellipse passes through the point (1, 6) therefore
…..(ii)
Solving eq. (i) and (ii), we have 
Therefore, the required equation of ellipse is
.
20. Major axis on the
axis and passes through the points (4, 3) and (6, 2).
Ans. Since the major axis is along
axis, therefore equation of ellipse is 
And the ellipse passes through the point (4, 3) therefore
…..(i)
And the ellipse passes through the point (6, 2) therefore
…..(ii)
Solving eq. (i) and (ii), we have 
Therefore, the required equation of ellipse is
.
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