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Pradum Kumar 8 years, 4 months ago
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Seema Sardana 8 years, 4 months ago
Kinetic energy (K.E) = 1/2 mv2
multiply and divide RHS by m, we get K.E.= m2v2 /2m ........(i)
Momentum =p =mv..............(ii)
Substitute value from eq (ii) in eq(i) , we get K.E. =p2 /2m
Imam Asad Siddiqui 8 years, 4 months ago
Posted by Rakhi Singh Tomar 8 years, 4 months ago
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Posted by Jugal Sharma 8 years, 4 months ago
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Ritesh Kumar 8 years, 4 months ago
Posted by Aryan Singh 8 years, 4 months ago
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Seema Sardana 8 years, 4 months ago
Acceleration is the rate of change of velocity with respect to time
a= (final velocity - initial velocity) / time
SI units are m/s2
Posted by Aditya Dubey 8 years, 4 months ago
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Posted by Adari Srinivasarao 8 years, 4 months ago
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Posted by Hemant Singh 8 years, 4 months ago
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Naveen Sharma 8 years, 4 months ago
Given {tex}T = k p^a d^b E^c{/tex}
where k is a proportionally constant.
Substituting the dimensions of T, p, d and E,
we have
{tex} [T] = [[ML^{-1}T^{-2}]^ a [ML^{-3}]^ b [ML^2T^{ -2}]^ c {/tex}
Equating power of M, L, and T on both sides, we have
a + b + c = 0
–a –3b + 2c = 0
–2a – 2c = 1
Solving these equations, we get {tex}a = {-5\over 6}, \ b = {1\over 2} \ and \ c ={ 1\over 3}{/tex}
Posted by Monu Yadav 8 years, 4 months ago
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Himanshu Singhal 8 years, 4 months ago
the nucleus formed by the fusion of two polar nuclei in the embryo sac of a seed plant prior to fertilization —called also secondary nucleus
Posted by Zahiruddin Babar Khan 8 years, 4 months ago
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