Cos-1 (cos (680)
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Posted by Deepanshu Saini 6 years, 9 months ago
- 2 answers
Payal Singh 6 years, 9 months ago
{tex}cos^{-1}[cos(680^°)]{/tex}
= {tex}cos^{-1}[cos(4\pi -40^°)]{/tex}
{tex}= cos^{-1}[cos(40^°)]{/tex}
= {tex}40^°{/tex}
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Sahdev Sharma 6 years, 9 months ago
{tex}cos^{-1}[cos(680^°)]{/tex}
{tex}= cos^{-1}[cos(4\pi -40^°)]{/tex}
{tex}= cos^{-1}[cos(40^°)]{/tex}
={tex}= 40^°{/tex}
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