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Y=sin–¹ (2x√1-x²

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Y=sin–¹ (2x√1-x²
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Srishti Singla 6 days, 1 hour ago

Let x=cosA Y=sin–¹(2cosA ×√1-Sin²A) =Sin–¹(2cosA sinA) =Sin–¹(Sin2A) = 2A = 2 Cos –¹x
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