Sin-1(tan5π/4)
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Lokendra Soni 7 years ago
{tex}\tan{5\pi\over4}{/tex} = {tex}\tan({\pi + {\pi\over4}}){/tex} = {tex}\tan{\pi\over4}{/tex}
{tex}\sin^{-1}({\tan{\pi\over4}}){/tex} = {tex}\sin^{-1}({1}){/tex} = {tex}\pi\over2{/tex}
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