# NCERT Solutions for Class 9 Maths Exercise 4.1

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NCERT solutions for Class 9 Maths Linear Equations in Two Variables

## NCERT Solutions for Class 9 Mathematics Linear Equations in Two Variables

###### (Take the cost of a notebook to be Rs x and that of a pen to be Rs y).

Ans. Let the cost of a notebook be.

Let the cost of a pen be.

We need to write a linear equation in two variables to represent the statement, “Cost of a notebook is twice the cost of a pen”.

Therefore, we can conclude that the required statement will be.

NCERT Solutions for Class 9 Maths Exercise 4.1

###### 2. Express the following linear equations in the form ax + by + c = 0 and indicate the values of a, b and c in each case:

(i)

(ii)

(iii)

(iv)

(v)

(vi)

(vii)

(viii)

Ans. (i)

We need to express the linear equationin the form ax + by + c = 0 and indicate the values of a, b and c.

can also be written as

We need to compare the equationwith the general equation ax + by + c = 0, to get the values of a, b and c.

Therefore, we can conclude that.

###### (ii)

We need to express the linear equationin the form ax + by + c = 0 and indicate the values of a, b and c.

can also be written as

We need to compare the equationwith the general equation ax + by + c = 0, to get the values of a, b and c.

Therefore, we can conclude that.

###### (iii)

We need to express the linear equationin the form ax + by + c = 0 and indicate the values of a, b and c.

can also be written as

We need to compare the equationwith the general equation ax + by + c = 0, to get the values of a, b and c.

Therefore, we can conclude that.

###### (iv)

We need to express the linear equationin the form ax + by + c = 0 and indicate the values of a, b and c.

can also be written as

We need to compare the equationwith the general equation ax + by + c = 0, to get the values of a, b and c.

Therefore, we can conclude that.

###### (v)

We need to express the linear equationin the form ax + by + c = 0 and indicate the values of a, b and c.

can also be written as

We need to compare the equationwith the general equation ax + by + c = 0, to get the values of a, b and c.

Therefore, we can conclude that.

###### (vi)

We need to express the linear equationin the form ax + by + c = 0 and indicate the values of a, b and c.

can also be written as

We need to compare the equationwith the general equation ax + by + c = 0, to get the values of a, b and c.

Therefore, we can conclude that.

NCERT Solutions for Class 9 Maths Exercise 4.1

###### (vii)

We need to express the linear equationin the form ax + by + c = 0 and indicate the values of a, b and c.

can also be written as

We need to compare the equationwith the general equation ax + by + c = 0, to get the values of a, b and c.

Therefore, we can conclude that.

(viii)

We need to express the linear equationin the form ax + by + c = 0 and indicate the values of a, b and c.

can also be written as

We need to compare the equationwith the general equation ax + by + c = 0, to get the values of a, b and c.

Therefore, we can conclude that.

## NCERT Solutions for Class 9 Maths Exercise 4.1

NCERT Solutions for Class 9 Maths PDF (Download) Free from myCBSEguide app and myCBSEguide website. Ncert solution class 9 Maths includes text book solutions from Mathematics Book. NCERT Solutions for CBSE Class 9 Maths have total 15 chapters. 9 Maths NCERT Solutions in PDF for free Download on our website. Ncert Maths class 9 solutions PDF and Maths ncert class 9 PDF solutions with latest modifications and as per the latest CBSE syllabus are only available in myCBSEguide.

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