NCERT Solutions for Class 7 Maths Exercise 8.1

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NCERT Solutions for Class 7 Maths Exercise 8.1 book solutions are available in PDF format for free download. These ncert book chapter wise questions and answers are very helpful for CBSE exam. CBSE recommends NCERT books and most of the questions in CBSE exam are asked from NCERT text books. Class 7 Maths chapter wise NCERT solution for Maths Book all the chapters can be downloaded from our website and myCBSEguide mobile app for free.

NCERT solutions for Maths Comparing Quantities Download as PDF

NCERT Solutions for Class 7 Maths Exercise 8.1

NCERT Solutions for Class 7 Maths Comparing Quantities

Class –VII Mathematics (Ex. 8.1)
Question 1. Find the ratio of:

(a) Rs. 5 to 50 paise

(b) 15 kg to 210 g

(c) 9 m to 27 cm

(d) 30 days to 36 hours

Answer:

To find ratios, both quantities should be in same unit.

(a) Rs. 5 to 50 paise

{tex} \Rightarrow {/tex} 5 x 100 paise to 50 paise

[{tex}\because {/tex}Rs. 1 = 100 paise]

{tex} \Rightarrow {/tex} 500 paise to 50 paise

Thus, the ratio is = {tex}\frac{{500}}{{50}} = \frac{{10}}{1}{/tex} = 10 : 1

(b) 15 kg to 210 g

{tex} \Rightarrow {/tex} 15 x 1000 g to 210 g [ {tex}\because {/tex} 1 kg = 1000 g]

{tex} \Rightarrow {/tex} 15000 g to 210 g

Thus, the ratio is = {tex}\frac{{15000}}{{210}} = \frac{{500}}{7}{/tex} = 500 : 7

(c) 9 m to 27 cm

{tex} \Rightarrow {/tex} 9 x 100 cm to 27 cm [ {tex}\because {/tex} 1 m = 100 cm]

{tex} \Rightarrow {/tex} 900 cm to 27 cm

Thus, the ratio is = {tex}\frac{{900}}{{27}} = \frac{{100}}{3}{/tex} = 100 :3

(d) 30 days to 36 hours

{tex} \Rightarrow {/tex} 30 x 24 hours to 36 hours [ {tex}\because {/tex} 1 day = 24 hours]

{tex} \Rightarrow {/tex} 720 hours to 36 hours

Thus, the ratio is = {tex}\frac{{720}}{{36}} = \frac{{20}}{1}{/tex} = 20 : 1


NCERT Solutions for Class 7 Maths Exercise 8.1

Question 2.In a computer lab, there are 3 computers for every 6 students. How many computers will be needed for 24 students?

Answer:

(a) 0.65 = {tex}\frac{{65}}{{100}} \times 100\% {/tex} = 65%

(b) 0.02 = {tex}\frac{2}{{100}} \times 100\% {/tex} = 2%


NCERT Solutions for Class 7 Maths Exercise 8.1

Question 3.Population of Rajasthan = 570 lakhs and population of U.P. = 1660 lakhs. Area of Rajasthan = 3 lakh {tex}k{m^2}{/tex}and area of U.P. = 2 lakh{tex}k{m^2}{/tex}.

(i) How many people are there per km2 in both states?

(ii) Which state is less populated?

Answer:

(i) People present per {tex}k{m^2}{/tex}= {tex}\frac{{{\text{Population}}}}{{{\text{Area}}}}{/tex}

In Rajasthan = {tex}\frac{{570{\text{ lakhs}}}}{{{\text{3 lakhs per k}}{{\text{m}}^2}}}{/tex} = 190 people {tex}k{m^2}{/tex}

In U.P. = {tex}\frac{{{\text{1660 lakhs}}}}{{{\text{2 lakh per k}}{{\text{m}}^2}}}{/tex} = 830 people per {tex}k{m^2}{/tex}

(ii) Rajasthan is less populated.

NCERT Solutions for Class 7 Maths Exercise 8.1

NCERT Solutions Class 7 Maths PDF (Download) Free from myCBSEguide app and myCBSEguide website. Ncert solution class 7 Maths includes text book solutions from Class 7 Maths Book . NCERT Solutions for CBSE Class 7 Maths have total 15 chapters. 7 Maths NCERT Solutions in PDF for free Download on our website. Ncert Maths class 7 solutions PDF and Maths ncert class 7 PDF solutions with latest modifications and as per the latest CBSE syllabus are only available in myCBSEguide.

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