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NCERT Solutions for Class 7 Maths Exercise 2.2

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NCERT Solutions for Class 7 Maths Exercise 2.2 book solutions are available in PDF format for free download. These ncert book chapter wise questions and answers are very helpful for CBSE exam. CBSE recommends NCERT books and most of the questions in CBSE exam are asked from NCERT text books. Class 7 Maths chapter wise NCERT solution for Maths Book all the chapters can be downloaded from our website and myCBSEguide mobile app for free.

NCERT solutions for Maths Fractions and Decimals Download as PDF

NCERT Solutions for Class 7 Maths Exercise 2.2

NCERT Solutions for Class 7 Maths Fractions and Decimals

Class –VII Mathematics (Ex. 2.2)
Question 1.Which of the drawings {tex}\left( a \right){/tex} to {tex}\left( d \right){/tex} show:

(i){tex}2 \times \frac{1}{5}{/tex}

(ii){tex}2 \times \frac{1}{2}{/tex}

(iii){tex}3 \times \frac{2}{3}{/tex}

(iv){tex}3 \times \frac{1}{4}{/tex}

Answer:

(i) – (d) Since {tex}2 \times \frac{1}{5} = \frac{1}{5} + \frac{1}{5}{/tex}

(ii) – (b) Since {tex}2 \times \frac{1}{2} = \frac{1}{2} + \frac{1}{2}{/tex}

(iii) – (a) Since {tex}3 \times \frac{2}{3} = \frac{2}{3} + \frac{2}{3} + \frac{2}{3}{/tex}

(iv) – (c) Since {tex}3 \times \frac{1}{4} = \frac{1}{4} + \frac{1}{4} + \frac{1}{4}{/tex}


NCERT Solutions for Class 7 Maths Exercise 2.2

Question 2.Some pictures {tex}\left( a \right){/tex} to {tex}\left( c \right){/tex} are given below. Tell which of them show:

(i){tex}3 \times \frac{1}{5} = \frac{3}{5}{/tex}

(ii){tex}2 \times \frac{1}{3} = \frac{2}{3}{/tex}

(iii){tex}3 \times \frac{3}{4} = 2\frac{1}{4}{/tex}

Answer:

(i) – (c) Since {tex}3 \times \frac{1}{5} = \frac{1}{5} + \frac{1}{5} + \frac{1}{5}{/tex}

(ii) – (a) Since {tex}2 \times \frac{1}{3} = \frac{1}{3} + \frac{1}{3}{/tex}

(iii) – (b) Since {tex}3 \times \frac{3}{4} = \frac{3}{4} + \frac{3}{4} + \frac{3}{4}{/tex}


NCERT Solutions for Class 7 Maths Exercise 2.2

Question 3.Multiply and reduce to lowest form and convert into a mixed fraction:

(i) {tex}7 \times \frac{3}{5}{/tex}

(ii) {tex}4 \times \frac{1}{3}{/tex}

(iii) {tex}2 \times \frac{6}{7}{/tex}

(iv) {tex}5 \times \frac{2}{9}{/tex}

(v) {tex}\frac{2}{3} \times 4{/tex}

(vi) {tex}\frac{5}{2} \times 6{/tex}

(vii) {tex}11 \times \frac{4}{7}{/tex}

(viii) {tex}20 \times \frac{4}{5}{/tex}

(ix) {tex}13 \times \frac{1}{3}{/tex}

(x) {tex}15 \times \frac{3}{5}{/tex}

Answer:

(i) {tex}7 \times \frac{3}{5}{/tex} = {tex}\frac{{7 \times 3}}{5}{/tex} = {tex}\frac{{21}}{5} = 4\frac{1}{5}{/tex}

(ii) {tex}4 \times \frac{1}{3}{/tex} = {tex}\frac{{4 \times 1}}{3}{/tex} = {tex}\frac{4}{3} = 1\frac{1}{3}{/tex}

(iii){tex}2 \times \frac{6}{7}{/tex} = {tex}\frac{{2 \times 6}}{7}{/tex} = {tex}\frac{{12}}{7} = 1\frac{5}{7}{/tex}

(iv) {tex}5 \times \frac{2}{9}{/tex} = {tex}\frac{{5 \times 2}}{9}{/tex} = {tex}\frac{{10}}{9} = 1\frac{1}{9}{/tex}

(v) {tex}\frac{2}{3} \times 4{/tex} = {tex}\frac{{2 \times 4}}{3}{/tex} = {tex}\frac{8}{3}{/tex} = {tex}2\frac{2}{3}{/tex}

(vi) {tex}\frac{5}{2} \times 6{/tex} = {tex}5 \times 3{/tex} = 15

(vii){tex}11 \times \frac{4}{7}{/tex} = {tex}\frac{{11 \times 4}}{7}{/tex} = {tex}\frac{{44}}{7}{/tex} = {tex}6\frac{2}{7}{/tex}

(viii){tex}20 \times \frac{4}{5}{/tex} = 4 x 4 = 16

(ix){tex}13 \times \frac{1}{3}{/tex} = {tex}\frac{{13 \times 1}}{3}{/tex} = {tex}\frac{{13}}{3} = 4\frac{1}{3}{/tex}

(x){tex}15 \times \frac{3}{5}{/tex} = 3 x 3 = 9


NCERT Solutions for Class 7 Maths Exercise 2.2

Question 4.Shade:

(i) {tex}\frac{1}{2}{/tex} of the circles in box

(ii) {tex}\frac{2}{3}{/tex} of the triangles in box

(iii){tex}\frac{3}{5}{/tex} of the squares inbox

Answer:

(i) {tex}\frac{1}{2}{/tex} of 12 circles = {tex}\frac{1}{2} \times 12{/tex} = 6 circles

(ii) {tex}\frac{2}{3}{/tex} of 9 triangles = {tex}\frac{2}{3} \times 9{/tex} = 2 x 3 = 6 triangles

(iii) {tex}\frac{3}{5}{/tex} of 15 squares = {tex}\frac{3}{5} \times 15{/tex} 3 x 3 = 9 squares


NCERT Solutions for Class 7 Maths Exercise 2.2

Question 5.Find:

(a) {tex}\frac{1}{2}{/tex} of (i) 24 (ii) 46

(b) {tex}\frac{2}{3}{/tex} of (i) 18 (ii) 27

(c) {tex}\frac{3}{4}{/tex} of (i) 16 (ii) 36

(d) {tex}\frac{4}{5}{/tex} of (i) 20 (ii) 35

Answer:

(a)

(i) {tex}\frac{1}{2}{/tex} of 24 = 12

(ii) {tex}\frac{1}{2}{/tex} of 46 = = 23

(b)

(i) {tex}\frac{2}{3}{/tex} of 18 = {tex}\frac{2}{3} \times 18{/tex} = 2 x 6 = 12

(ii) {tex}\frac{2}{3}{/tex} of 27 = {tex}\frac{2}{3} \times 27{/tex} = 2 x 9 = 18

(c)

(i) {tex}\frac{3}{4}{/tex} of 16 = {tex}\frac{3}{4} \times 16{/tex} = 3 x 4 = 12

(ii) {tex}\frac{3}{4}{/tex} of 36 = {tex}\frac{3}{4} \times 36{/tex} = 3 x 9 = 27

(d)

(i) {tex}\frac{4}{5}{/tex} of 20 = {tex}\frac{4}{5} \times 20{/tex} = 4 x 4 = 16

(ii) {tex}\frac{4}{5}{/tex} of 35 = {tex}\frac{4}{5} \times 35{/tex} = 4 x 7 = 28


NCERT Solutions for Class 7 Maths Exercise 2.2

Question 6.Multiply and express as a mixed fraction:

(a) {tex}3 \times 5\frac{1}{5}{/tex}

(b) {tex}5 \times 6\frac{3}{4}{/tex}

(c) {tex}7 \times 2\frac{1}{4}{/tex}

(d) {tex}4 \times 6\frac{1}{3}{/tex}

(e) {tex}3\frac{1}{4} \times 6{/tex}

(f) {tex}3\frac{2}{5} \times 8{/tex}

Answer:

(a) {tex}3 \times 5\frac{1}{5} = 3 \times \frac{{26}}{5} = \frac{{3 \times 26}}{5} = \frac{{78}}{5} = 15\frac{3}{5}{/tex}

(b) {tex}5 \times 6\frac{3}{4} = 5 \times \frac{{27}}{4} = \frac{{5 \times 27}}{4} = \frac{{135}}{4} = 33\frac{3}{4}{/tex}

(c) {tex}7 \times 2\frac{1}{4} = 7 \times \frac{9}{4} = \frac{{7 \times 9}}{4} = \frac{{63}}{4} = 15\frac{3}{4}{/tex}

(d) {tex}4 \times 6\frac{1}{3} = 4 \times \frac{{19}}{3} = \frac{{4 \times 19}}{3} = \frac{{76}}{3} = 25\frac{1}{3}{/tex}

(e) {tex}3\frac{1}{4} \times 6 = \frac{{13}}{4} \times 6 = \frac{{13 \times 3}}{2} = \frac{{39}}{2} = 19\frac{1}{2}{/tex}

(f) {tex}3\frac{2}{5} \times 8 = \frac{{17}}{5} \times 8 = \frac{{17 \times 8}}{5} = \frac{{136}}{5} = 27\frac{1}{5}{/tex}


NCERT Solutions for Class 7 Maths Exercise 2.2

Question 7.Find:

(a) {tex}\frac{1}{2}{/tex} of (i) {tex}2\frac{3}{4}{/tex} (ii) {tex}4\frac{2}{9}{/tex}

(b) {tex}\frac{5}{8}{/tex} of (i) {tex}3\frac{5}{6}{/tex} (ii) {tex}9\frac{2}{3}{/tex}

Answer:

Given: Total quantity of water in bottle = 5 litres

(i) Vidya consumed = {tex}\frac{2}{5}{/tex} of 5 litres = {tex}\frac{2}{5} \times 5{/tex} = 2 litres

Thus, Vidya drank 2 litres water from the bottle.

(ii) Pratap consumed = {tex}\left( {1 – \frac{2}{5}} \right){/tex} part of bottle

= {tex}\frac{{5 – 2}}{5} = \frac{3}{5}{/tex} part of bottle

Pratap consumed {tex}\frac{3}{5}{/tex} of 5 litres water = {tex}\frac{3}{5} \times 5{/tex} = 3 litres

Thus, Pratap drank {tex}\frac{3}{5}{/tex} part of the total quantity of water.


NCERT Solutions for Class 7 Maths Exercise 2.2

Question 8. Vidya and Pratap went for a picnic. Their mother gave them a water bottle that contained 5 litres of water. Vidya consumed {tex}\frac{2}{5}{/tex} of the water. Pratap consumed the remaining water.

(i)How much water did Vidya drink?

(ii)What fraction of the total quantity of water did Pratap drink?

Answer:

Given: Total quantity of water in bottle = 5 litres

(i) Vidya consumed = {tex}\frac{2}{5}{/tex} of 5 litres = {tex}\frac{2}{5} \times 5{/tex} = 2 litres

Thus, Vidya drank 2 litres water from the bottle.

(ii) Pratap consumed = {tex}\left( {1 – \frac{2}{5}} \right){/tex} part of bottle

= {tex}\frac{{5 – 2}}{5} = \frac{3}{5}{/tex} part of bottle

Pratap consumed {tex}\frac{3}{5}{/tex} of 5 litres water = {tex}\frac{3}{5} \times 5{/tex} = 3 litres

Thus, Pratap drank {tex}\frac{3}{5}{/tex} part of the total quantity of water.

NCERT Solutions for Class 7 Maths Exercise 2.2

NCERT Solutions Class 7 Maths PDF (Download) Free from myCBSEguide app and myCBSEguide website. Ncert solution class 7 Maths includes text book solutions from Class 7 Maths Book . NCERT Solutions for CBSE Class 7 Maths have total 15 chapters. 7 Maths NCERT Solutions in PDF for free Download on our website. Ncert Maths class 7 solutions PDF and Maths ncert class 7 PDF solutions with latest modifications and as per the latest CBSE syllabus are only available in myCBSEguide.

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3 thoughts on “NCERT Solutions for Class 7 Maths Exercise 2.2”

  1. In 7th question you gave 8th answer. please rewrite it then we (students) can write without mistakes.
    Thank you.

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