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NCERT Solutions for Class 7 Maths Exercise 2.7

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NCERT Solutions for Class 7 Maths Exercise 2.7 book solutions are available in PDF format for free download. These ncert book chapter wise questions and answers are very helpful for CBSE exam. CBSE recommends NCERT books and most of the questions in CBSE exam are asked from NCERT text books. Class 7 Maths chapter wise NCERT solution for Maths Book all the chapters can be downloaded from our website and myCBSEguide mobile app for free.

NCERT solutions for Maths Fractions and Decimals Download as PDF

NCERT Solutions for Class 7 Maths Exercise 2.7

NCERT Solutions for Class 7 Maths Fractions and Decimals

Class –VII Mathematics (Ex. 2.7)
Question 1.Find:

(i) 0.4 {tex} \div {/tex} 2

(ii) 0.35 {tex} \div {/tex} 5

(iii) 2.48 {tex} \div {/tex} 4

(iv) 65.4 {tex} \div {/tex} 6

(v) 651.2 {tex} \div {/tex} 4

(v) 14.49 {tex} \div {/tex} 7

(vii) 3.96 {tex} \div {/tex} 4

(viii) 0.80 {tex} \div {/tex} 5

Answer:

(i) 0.4 {tex} \div {/tex} 2 = {tex}\frac{4}{{10}} \times \frac{1}{2} = \frac{2}{{10}}{/tex} = 0.2

(ii) 0.35 {tex} \div {/tex} 5 = {tex}\frac{{35}}{{100}} \times \frac{1}{5} = \frac{7}{{100}}{/tex} = 0.07

(iii)2.48 {tex} \div {/tex} 4 = {tex}\frac{{248}}{{100}} \times \frac{1}{4} = \frac{{62}}{{100}}{/tex} = 0.62 (iv) 65.4 {tex} \div {/tex} 6 = {tex}\frac{{654}}{{10}} \times \frac{1}{6} = \frac{{109}}{{10}}{/tex} = 10.9

(v)651.2 {tex} \div {/tex} 4 = {tex}\frac{{6512}}{{10}} \times \frac{1}{4} = \frac{{1628}}{{10}}{/tex} = 162.8

(vi)14.49 {tex} \div {/tex} 7 = {tex}\frac{{1449}}{{100}} \times \frac{1}{7} = \frac{{207}}{{100}}{/tex} = 2.07

(vii)3.96 {tex} \div {/tex} 4 = {tex}\frac{{396}}{{100}} \times \frac{1}{4} = \frac{{99}}{{100}}{/tex} = 0.99

(viii)0.80 {tex} \div {/tex} 5 = {tex}\frac{{80}}{{100}} \times \frac{1}{5} = \frac{{16}}{{100}}{/tex} = 0.16


NCERT Solutions for Class 7 Maths Exercise 2.7

Question 2.Find:

(i) 4.8 {tex} \div {/tex} 10

(ii) 52.5 {tex} \div {/tex} 10

(iii) 0.7 {tex} \div {/tex} 10

(iv) 33.1 {tex} \div {/tex} 10

(v) 272.23 {tex} \div {/tex} 10

(vi) 0.56 {tex} \div {/tex} 10

(vii) 3.97 {tex} \div {/tex} 10

Answer:

(i) 4.8 {tex} \div {/tex} 10 = {tex}\frac{{4.8}}{{10}}{/tex} = 0.48

(ii) 52.5 {tex} \div {/tex} 10 = {tex}\frac{{52.5}}{{10}}{/tex} = 5.25

(iii) 0.7 {tex} \div {/tex} 10 = {tex}\frac{{0.7}}{{10}}{/tex} = 0.07

(iv) 33.1 {tex} \div {/tex} 10 = {tex}\frac{{33.1}}{{10}}{/tex} = 3.31

(v) 272.23 {tex} \div {/tex} 10 = {tex}\frac{{272.23}}{{10}}{/tex} = 27.223

(vi) 0.56 {tex} \div {/tex} 10 = {tex}\frac{{0.56}}{{10}}{/tex} = 0.056

(vii) 3.97 {tex} \div {/tex} 10 = {tex}\frac{{3.97}}{{10}}{/tex} = 0.397


NCERT Solutions for Class 7 Maths Exercise 2.7

Question 3. Find:

(i) 2.7 {tex} \div {/tex} 100

(ii) 0.3 {tex} \div {/tex} 100

(iii) 0.78 {tex} \div {/tex} 100

(iv) 432.6 {tex} \div {/tex} 100

(v) 23.6 {tex} \div {/tex} 100

(vi) 98.53 {tex} \div {/tex} 100

Answer:

(i) 2.7 {tex} \div {/tex} 100 = {tex}\frac{{27}}{{10}} \times \frac{1}{{100}} = \frac{{27}}{{1000}}{/tex} = 0.027

(ii) 0.3 {tex} \div {/tex} 100 = {tex}\frac{3}{{10}} \times \frac{1}{{100}} = \frac{3}{{1000}}{/tex} = 0.003

(iii) 0.78 {tex} \div {/tex} 100 = {tex}\frac{{78}}{{100}} \times \frac{1}{{100}} = \frac{{78}}{{10000}}{/tex} = 0.0078

(iv) 432.6 {tex} \div {/tex} 100 = {tex}\frac{{4326}}{{10}} \times \frac{1}{{100}} = \frac{{4326}}{{1000}}{/tex} = 4.326

(v) 23.6 {tex} \div {/tex} 100 = {tex}\frac{{236}}{{10}} \times \frac{1}{{100}} = \frac{{236}}{{1000}}{/tex} = 0.236

(vi) 98.53 {tex} \div {/tex} 100 = {tex}\frac{{9853}}{{100}} \times \frac{1}{{100}} = \frac{{9853}}{{10000}}{/tex} 0.9853


NCERT Solutions for Class 7 Maths Exercise 2.7

Question 4.Find:

(i) 7.9 {tex} \div {/tex} 1000

(ii) 26.3 {tex} \div {/tex} 1000

(iii) 38.53 {tex} \div {/tex} 1000

(iv) 128.9 {tex} \div {/tex} 1000

(v) 0.5 {tex} \div {/tex} 1000

Answer:

(i) 7.9 {tex} \div {/tex} 1000 = {tex}\frac{{79}}{{10}} \times \frac{1}{{1000}} = \frac{{79}}{{10000}}{/tex} = 0.0079

(ii) 26.3 {tex} \div {/tex} 1000 = {tex}\frac{{263}}{{10}} \times \frac{1}{{1000}} = \frac{{263}}{{10000}}{/tex} = 0.0263

(iii) 38.53 {tex} \div {/tex} 1000 = {tex}\frac{{3853}}{{100}} \times \frac{1}{{1000}} = \frac{{3853}}{{100000}}{/tex} = 0.03853

(iv) 128.9 {tex} \div {/tex} 1000 = {tex}\frac{{1289}}{{10}} \times \frac{1}{{1000}} = \frac{{1289}}{{10000}}{/tex} = 0.1289

(v) 0.5 {tex} \div {/tex} 1000 = {tex}\frac{5}{{10}} \times \frac{1}{{1000}} = \frac{5}{{10000}}{/tex} = 0.0005


NCERT Solutions for Class 7 Maths Exercise 2.7

Question 5.Find:

(i) 7 {tex} \div {/tex} 3.5

(ii) 36 {tex} \div {/tex} 0.2

(iii) 3.25 {tex} \div {/tex} 0.5

(iv) 30.94 {tex} \div {/tex} 0.7

(v) 0.5 {tex} \div {/tex} 0.25

(vi) 7.75 {tex} \div {/tex} 0.25

(vii) 76.5 {tex} \div {/tex} 0.15

(viii) 37.8 {tex} \div {/tex} 1.4

(ix) 2.73 {tex} \div {/tex} 1.3

Answer:

(i) 7 {tex} \div {/tex} 3.5 = {tex}7 \div \frac{{35}}{{10}} = 7 \times \frac{{10}}{{35}} = \frac{{10}}{5}{/tex} = 2

(ii) 36 {tex} \div {/tex} 0.2 = {tex}36 \div \frac{2}{{10}} = 36 \times \frac{{10}}{2} = {/tex} 18 x 10 = 180

(iii) 3.25 {tex} \div {/tex} 0.5 = {tex}\frac{{325}}{{100}} \div \frac{5}{{10}} = \frac{{325}}{{100}} \times \frac{{10}}{5} = \frac{{65}}{{10}}{/tex} = 6.5

(iv) 30.94 {tex} \div {/tex} 0.7 = {tex}\frac{{3094}}{{100}} \div \frac{7}{{10}} = \frac{{3094}}{{100}} \times \frac{{10}}{7} = \frac{{442}}{{10}}{/tex} = 44.2

(v) 0.5 {tex} \div {/tex} 0.25 = {tex}\frac{5}{{10}} \div \frac{{25}}{{100}} = \frac{5}{{10}} \times \frac{{100}}{{25}} = \frac{{10}}{5}{/tex} = 2

(vi) 7.75 {tex} \div {/tex} 0.25 = {tex}\frac{{775}}{{100}} \div \frac{{25}}{{100}} = \frac{{775}}{{100}} \times \frac{{100}}{{25}}{/tex} = 31

(vii) 76.5 {tex} \div {/tex} 0.15 = {tex}\frac{{765}}{{10}} \div \frac{{15}}{{100}} = \frac{{765}}{{10}} \times \frac{{100}}{{15}}{/tex} = 51 x 10 = 510

(viii) 37.8 {tex} \div {/tex} 1.4 = {tex}\frac{{378}}{{10}} \div \frac{{14}}{{10}} = \frac{{378}}{{10}} \times \frac{{10}}{{14}}{/tex} = 27

(ix) 2.73 {tex} \div {/tex} 1.3 = {tex}\frac{{273}}{{100}} \div \frac{{13}}{{10}} = \frac{{273}}{{100}} \times \frac{{10}}{{13}} = \frac{{21}}{{10}}{/tex} = 2.1


NCERT Solutions for Class 7 Maths Exercise 2.7

Question 6.A vehicle covers a distance of 43.2 km in 2.4 litres of petrol. How% much distance will it cover in one litre petrol?

Answer:

{tex}\because {/tex} In 2.4 litres of petrol, distance covered by the vehicle = 43.2 km

{tex}\therefore {/tex} In 1 litre of petrol, distance covered by the vehicle = 43.2 {tex} \div {/tex} 2.4

= {tex}\frac{{432}}{{10}} \div \frac{{24}}{{10}}{/tex} = {tex}\frac{{432}}{{10}} \times \frac{{24}}{{10}}{/tex}

= 18 km

Thus, it covered 18 km distance in one litre of petrol.

NCERT Solutions for Class 7 Maths Exercise 2.7

NCERT Solutions Class 7 Maths PDF (Download) Free from myCBSEguide app and myCBSEguide website. Ncert solution class 7 Maths includes text book solutions from Class 7 Maths Book . NCERT Solutions for CBSE Class 7 Maths have total 15 chapters. 7 Maths NCERT Solutions in PDF for free Download on our website. Ncert Maths class 7 solutions PDF and Maths ncert class 7 PDF solutions with latest modifications and as per the latest CBSE syllabus are only available in myCBSEguide.

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