# NCERT Solutions for Class 7 Maths Exercise 2.7

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NCERT solutions for Maths Fractions and Decimals

## NCERT Solutions for Class 7 Maths Fractions and Decimals

###### Question 1.Find:

(i) 0.4 {tex} \div {/tex} 2

(ii) 0.35 {tex} \div {/tex} 5

(iii) 2.48 {tex} \div {/tex} 4

(iv) 65.4 {tex} \div {/tex} 6

(v) 651.2 {tex} \div {/tex} 4

(v) 14.49 {tex} \div {/tex} 7

(vii) 3.96 {tex} \div {/tex} 4

(viii) 0.80 {tex} \div {/tex} 5

(i) 0.4 {tex} \div {/tex} 2 = {tex}\frac{4}{{10}} \times \frac{1}{2} = \frac{2}{{10}}{/tex} = 0.2

(ii) 0.35 {tex} \div {/tex} 5 = {tex}\frac{{35}}{{100}} \times \frac{1}{5} = \frac{7}{{100}}{/tex} = 0.07

(iii)2.48 {tex} \div {/tex} 4 = {tex}\frac{{248}}{{100}} \times \frac{1}{4} = \frac{{62}}{{100}}{/tex} = 0.62 (iv) 65.4 {tex} \div {/tex} 6 = {tex}\frac{{654}}{{10}} \times \frac{1}{6} = \frac{{109}}{{10}}{/tex} = 10.9

(v)651.2 {tex} \div {/tex} 4 = {tex}\frac{{6512}}{{10}} \times \frac{1}{4} = \frac{{1628}}{{10}}{/tex} = 162.8

(vi)14.49 {tex} \div {/tex} 7 = {tex}\frac{{1449}}{{100}} \times \frac{1}{7} = \frac{{207}}{{100}}{/tex} = 2.07

(vii)3.96 {tex} \div {/tex} 4 = {tex}\frac{{396}}{{100}} \times \frac{1}{4} = \frac{{99}}{{100}}{/tex} = 0.99

(viii)0.80 {tex} \div {/tex} 5 = {tex}\frac{{80}}{{100}} \times \frac{1}{5} = \frac{{16}}{{100}}{/tex} = 0.16

NCERT Solutions for Class 7 Maths Exercise 2.7

###### Question 2.Find:

(i) 4.8 {tex} \div {/tex} 10

(ii) 52.5 {tex} \div {/tex} 10

(iii) 0.7 {tex} \div {/tex} 10

(iv) 33.1 {tex} \div {/tex} 10

(v) 272.23 {tex} \div {/tex} 10

(vi) 0.56 {tex} \div {/tex} 10

(vii) 3.97 {tex} \div {/tex} 10

(i) 4.8 {tex} \div {/tex} 10 = {tex}\frac{{4.8}}{{10}}{/tex} = 0.48

(ii) 52.5 {tex} \div {/tex} 10 = {tex}\frac{{52.5}}{{10}}{/tex} = 5.25

(iii) 0.7 {tex} \div {/tex} 10 = {tex}\frac{{0.7}}{{10}}{/tex} = 0.07

(iv) 33.1 {tex} \div {/tex} 10 = {tex}\frac{{33.1}}{{10}}{/tex} = 3.31

(v) 272.23 {tex} \div {/tex} 10 = {tex}\frac{{272.23}}{{10}}{/tex} = 27.223

(vi) 0.56 {tex} \div {/tex} 10 = {tex}\frac{{0.56}}{{10}}{/tex} = 0.056

(vii) 3.97 {tex} \div {/tex} 10 = {tex}\frac{{3.97}}{{10}}{/tex} = 0.397

NCERT Solutions for Class 7 Maths Exercise 2.7

###### Question 3. Find:

(i) 2.7 {tex} \div {/tex} 100

(ii) 0.3 {tex} \div {/tex} 100

(iii) 0.78 {tex} \div {/tex} 100

(iv) 432.6 {tex} \div {/tex} 100

(v) 23.6 {tex} \div {/tex} 100

(vi) 98.53 {tex} \div {/tex} 100

(i) 2.7 {tex} \div {/tex} 100 = {tex}\frac{{27}}{{10}} \times \frac{1}{{100}} = \frac{{27}}{{1000}}{/tex} = 0.027

(ii) 0.3 {tex} \div {/tex} 100 = {tex}\frac{3}{{10}} \times \frac{1}{{100}} = \frac{3}{{1000}}{/tex} = 0.003

(iii) 0.78 {tex} \div {/tex} 100 = {tex}\frac{{78}}{{100}} \times \frac{1}{{100}} = \frac{{78}}{{10000}}{/tex} = 0.0078

(iv) 432.6 {tex} \div {/tex} 100 = {tex}\frac{{4326}}{{10}} \times \frac{1}{{100}} = \frac{{4326}}{{1000}}{/tex} = 4.326

(v) 23.6 {tex} \div {/tex} 100 = {tex}\frac{{236}}{{10}} \times \frac{1}{{100}} = \frac{{236}}{{1000}}{/tex} = 0.236

(vi) 98.53 {tex} \div {/tex} 100 = {tex}\frac{{9853}}{{100}} \times \frac{1}{{100}} = \frac{{9853}}{{10000}}{/tex} 0.9853

NCERT Solutions for Class 7 Maths Exercise 2.7

###### Question 4.Find:

(i) 7.9 {tex} \div {/tex} 1000

(ii) 26.3 {tex} \div {/tex} 1000

(iii) 38.53 {tex} \div {/tex} 1000

(iv) 128.9 {tex} \div {/tex} 1000

(v) 0.5 {tex} \div {/tex} 1000

(i) 7.9 {tex} \div {/tex} 1000 = {tex}\frac{{79}}{{10}} \times \frac{1}{{1000}} = \frac{{79}}{{10000}}{/tex} = 0.0079

(ii) 26.3 {tex} \div {/tex} 1000 = {tex}\frac{{263}}{{10}} \times \frac{1}{{1000}} = \frac{{263}}{{10000}}{/tex} = 0.0263

(iii) 38.53 {tex} \div {/tex} 1000 = {tex}\frac{{3853}}{{100}} \times \frac{1}{{1000}} = \frac{{3853}}{{100000}}{/tex} = 0.03853

(iv) 128.9 {tex} \div {/tex} 1000 = {tex}\frac{{1289}}{{10}} \times \frac{1}{{1000}} = \frac{{1289}}{{10000}}{/tex} = 0.1289

(v) 0.5 {tex} \div {/tex} 1000 = {tex}\frac{5}{{10}} \times \frac{1}{{1000}} = \frac{5}{{10000}}{/tex} = 0.0005

NCERT Solutions for Class 7 Maths Exercise 2.7

###### Question 5.Find:

(i) 7 {tex} \div {/tex} 3.5

(ii) 36 {tex} \div {/tex} 0.2

(iii) 3.25 {tex} \div {/tex} 0.5

(iv) 30.94 {tex} \div {/tex} 0.7

(v) 0.5 {tex} \div {/tex} 0.25

(vi) 7.75 {tex} \div {/tex} 0.25

(vii) 76.5 {tex} \div {/tex} 0.15

(viii) 37.8 {tex} \div {/tex} 1.4

(ix) 2.73 {tex} \div {/tex} 1.3

(i) 7 {tex} \div {/tex} 3.5 = {tex}7 \div \frac{{35}}{{10}} = 7 \times \frac{{10}}{{35}} = \frac{{10}}{5}{/tex} = 2

(ii) 36 {tex} \div {/tex} 0.2 = {tex}36 \div \frac{2}{{10}} = 36 \times \frac{{10}}{2} = {/tex} 18 x 10 = 180

(iii) 3.25 {tex} \div {/tex} 0.5 = {tex}\frac{{325}}{{100}} \div \frac{5}{{10}} = \frac{{325}}{{100}} \times \frac{{10}}{5} = \frac{{65}}{{10}}{/tex} = 6.5

(iv) 30.94 {tex} \div {/tex} 0.7 = {tex}\frac{{3094}}{{100}} \div \frac{7}{{10}} = \frac{{3094}}{{100}} \times \frac{{10}}{7} = \frac{{442}}{{10}}{/tex} = 44.2

(v) 0.5 {tex} \div {/tex} 0.25 = {tex}\frac{5}{{10}} \div \frac{{25}}{{100}} = \frac{5}{{10}} \times \frac{{100}}{{25}} = \frac{{10}}{5}{/tex} = 2

(vi) 7.75 {tex} \div {/tex} 0.25 = {tex}\frac{{775}}{{100}} \div \frac{{25}}{{100}} = \frac{{775}}{{100}} \times \frac{{100}}{{25}}{/tex} = 31

(vii) 76.5 {tex} \div {/tex} 0.15 = {tex}\frac{{765}}{{10}} \div \frac{{15}}{{100}} = \frac{{765}}{{10}} \times \frac{{100}}{{15}}{/tex} = 51 x 10 = 510

(viii) 37.8 {tex} \div {/tex} 1.4 = {tex}\frac{{378}}{{10}} \div \frac{{14}}{{10}} = \frac{{378}}{{10}} \times \frac{{10}}{{14}}{/tex} = 27

(ix) 2.73 {tex} \div {/tex} 1.3 = {tex}\frac{{273}}{{100}} \div \frac{{13}}{{10}} = \frac{{273}}{{100}} \times \frac{{10}}{{13}} = \frac{{21}}{{10}}{/tex} = 2.1

NCERT Solutions for Class 7 Maths Exercise 2.7

###### Question 6.A vehicle covers a distance of 43.2 km in 2.4 litres of petrol. How% much distance will it cover in one litre petrol?

{tex}\because {/tex} In 2.4 litres of petrol, distance covered by the vehicle = 43.2 km

{tex}\therefore {/tex} In 1 litre of petrol, distance covered by the vehicle = 43.2 {tex} \div {/tex} 2.4

= {tex}\frac{{432}}{{10}} \div \frac{{24}}{{10}}{/tex} = {tex}\frac{{432}}{{10}} \times \frac{{24}}{{10}}{/tex}

= 18 km

Thus, it covered 18 km distance in one litre of petrol.

## NCERT Solutions for Class 7 Maths Exercise 2.7

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