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# NCERT Solutions for Class 7 Maths Exercise 6.2

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NCERT solutions for Maths Triangles and its Properties

## NCERT Solutions for Class 7 Maths Triangles and its Properties

###### Question 1.Find the value of the unknown exterior angle {tex}x{/tex} in the following diagrams:

Since, Exterior angle = Sum of interior opposite angles, therefore

1. {tex}x = 50^\circ + 70^\circ = 120^\circ {/tex}
2. {tex}x = 65^\circ + 45^\circ = 110^\circ {/tex}
3. {tex}x = 30^\circ + 40^\circ = 70^\circ {/tex}
4. {tex}x = 60^\circ + 60^\circ = 120^\circ {/tex}
5. {tex}x = 50^\circ + 50^\circ = 100^\circ {/tex}
6. {tex}x = {60^ \circ } + {30^ \circ } = {90^ \circ }{/tex}

NCERT Solutions for Class 7 Maths Exercise 6.2

###### Question 2.Find the value of the unknown interior angle {tex}x{/tex} in the following figures:

Since, Exterior angle = Sum of interior opposite angles, therefore

1. {tex}x + 50^\circ = 115^\circ {/tex} {tex} \Rightarrow {/tex} {tex}x = 115^\circ – 50^\circ = 65^\circ {/tex}
2. {tex}70^\circ + x = 100^\circ {/tex} {tex} \Rightarrow {/tex} {tex}x = 100^\circ – 70^\circ = 30^\circ {/tex}
3. {tex}x + 90^\circ = 125^\circ {/tex} {tex} \Rightarrow {/tex} {tex}x = 120^\circ – 90^\circ = 35^\circ {/tex}
4. {tex}60^\circ + x = 120^\circ {/tex} {tex} \Rightarrow {/tex} {tex}x = 120^\circ – 60^\circ = 60^\circ {/tex}
5. {tex}30^\circ + x = 80^\circ {/tex} {tex} \Rightarrow {/tex} {tex}x = 80^\circ – 30^\circ = 50^\circ {/tex}
6. {tex}x + 35^\circ = 75^\circ {/tex} {tex} \Rightarrow {/tex} {tex}x = 75^\circ – 35^\circ = 40^\circ {/tex}

## NCERT Solutions for Class 7 Maths Exercise 6.2

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### 4 thoughts on “NCERT Solutions for Class 7 Maths Exercise 6.2”

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