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Ask QuestionPosted by Rajesh Kumar 6 years, 7 months ago
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Yogita Ingle 6 years, 7 months ago
| Minerals | Ores |
| 1. The natural materials in which the metals or their compounds are found in earth are called minerals. | 1. Those minerals from which the metals can be extracted conveniently and profitably are called ore. |
| 2. All the ores are minerals. | 2. All the minerals are not ores. |
Posted by Siya Jain 6 years, 7 months ago
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Yogita Ingle 6 years, 7 months ago
Phenoxide ion is more stable than phenol. This is because the phenoxide ion has more stabilised resonating structures as compared to the phenol.
Posted by Santy Baralu 6 years, 7 months ago
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Posted by Gracy Kipgen 6 years, 7 months ago
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Posted by Tanusha Sahu 6 years, 7 months ago
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Posted by Kimaya Kale 6 years, 7 months ago
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Sourav Kr Singh Parmar 6 years, 7 months ago
Sia ? 6 years, 7 months ago
Mass of solution = Mass of benzene (C6H6) + Mass of CCl4
= 22 g + 122 g = 144 g
Mass percentage of {tex}{C_6}{H_6} = \frac{{{\text{Mass of benzene}}}}{{{\text{Mass of solution}}}} \times 100{/tex}
{tex} = \frac{{22g}}{{144g}} \times 100{/tex} = 15.28%
Mass percentage of {tex}CC{l_4} = \frac{{122g}}{{144g}} \times 100{/tex} = 84.72% or 100-15.28 = 84.72%
Posted by Hemant Saini 6 years, 7 months ago
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Deepanshi Garg 6 years, 7 months ago
Satyam Krishna 6 years, 7 months ago
A Raj 6 years, 7 months ago
Deepak Jindal 6 years, 7 months ago
Sia ? 6 years, 7 months ago
Posted by Lipi Dey 6 years, 7 months ago
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Sia ? 6 years, 7 months ago
Posted by Gentle Farzan 6 years, 7 months ago
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Yogita Ingle 6 years, 7 months ago
The main allotropes of phosphorus include the white phosphorus, red phosphorus and black phosphorus. In addition to these, there also exists a violet phosphorus. However, that is not a significant allotrope.
Sia ? 6 years, 7 months ago
Posted by Ayushi Dave 6 years, 7 months ago
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Posted by Santy Baralu 6 years, 7 months ago
- 1 answers
Sia ? 6 years, 7 months ago
It is because hydration energy of Cu2+ ion is high compared to Cu+ ion. The high hydration energy of Cu2+ can overcome second ionization energy of Cu2+ .That is why Cu2+ is more stable than Cu+ ion in aqueous solution.
Posted by Prashant Tomar 6 years, 7 months ago
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Santy Baralu 6 years, 7 months ago
Posted by Chirag Malik 6 years, 7 months ago
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Posted by Ankit Raj 6 years, 7 months ago
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Sourav Kr Singh Parmar 6 years, 7 months ago
Praveen Singh 6 years, 7 months ago
Posted by Rajveer Kaur 6 years, 7 months ago
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Prashant Tomar 6 years, 7 months ago
Posted by Himanshu Tiwary 6 years, 7 months ago
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Yogita Ingle 6 years, 7 months ago
Lamp Black is fabricated when tar and vegetable oils (rich in carbon) are singed in a deficient supply of air and the subsequent residue is deposited on wet blankets in a room.
Lamp Black is a velvety black powder. It is utilized as a part of the preparation of Indian ink, carbon papers, printer's ink, varnishes, and black paint.
Posted by Nitesh Kumar 6 years, 7 months ago
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Sia ? 6 years, 7 months ago
Absorbing Ammonia
Effect of Acid Rain on Limestone Rock
Amount of Casein in Milk
Finding EMF of Electrochemical Cell
That’s Some Smart Metal
Posted by Priya Dhawan 6 years, 7 months ago
- 1 answers
Sia ? 6 years, 7 months ago
We have, mass(m) deposited is
{tex}m = Z \times I \times t{/tex}
{tex}m = \frac{{108}}{{96500}} \times 0.5 \times 2 \times 60 \times 60{/tex}
{tex} = \frac{{108 \times 5}}{{965 \times 10}} \times 2 \times 6 \times 6{/tex}= 4.03 g
{tex}4.03g = V \times d{/tex}
{tex}4.03g = V \times 10.5gc{m^{ - 3}}{/tex}
V = Area {tex} \times {/tex} Thickness
{tex}V = \frac{{4.03}}{{10.5}}{/tex}
{tex}\frac{{4.03}}{{10.5}} = 900c{m^2} \times {/tex} thickness
Thickness {tex} = \frac{{0.338c{m^3}}}{{900c{m^2}}}{/tex}
{tex} = 4.26 \times {10^{ - 4}}cm{/tex}
Posted by Boby Patel 6 years, 7 months ago
- 1 answers
Sia ? 6 years, 7 months ago
{tex}\Phi _ { B } = B \cdot A{/tex}
{tex}\Phi _ { B } = B A \operatorname { Cos } \theta{/tex}
Where, B = magnetic field
A = surface area and
{tex}\theta{/tex} = angle between the normal to the surface and magnetic field.
Posted by Mahavir Jaat 6 years, 7 months ago
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Posted by Sumit Kumar 6 years, 7 months ago
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Prince Yadav 6 years, 7 months ago
K@Lp@N@ Singh 6 years, 7 months ago
Posted by Utkarsh Chauhan 6 years, 7 months ago
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Sia ? 6 years, 7 months ago
{tex}M g \left( N O _ { 3 } \right) _ { 2 } \rightarrow M g ^ { 2 + } + 2 N O _ { 3 }
{/tex}
{tex}\alpha = \frac { i - 1 } { n - 1 }{/tex}
{tex}= \frac { 2.74 - 1 } { 3 - 1 }{/tex}
{tex}= \frac { 1.74 } { 2 }{/tex}
= 0.87
Degree of Dissociation = 0.87 {tex}\times{/tex}100 = 87%
Posted by Aman Thakur 6 years, 7 months ago
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Bhavya Tiwari 6 years, 7 months ago
Bhavya Tiwari 6 years, 7 months ago
Posted by Abhishek Shinde 6 years, 7 months ago
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Posted by Macherla Indupriya 6 years, 7 months ago
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Posted by Satyam Krishna 6 years, 7 months ago
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Mayank Aggarwal 6 years, 7 months ago
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