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For example, to prepare 100 mL of a 10% by volume solution of acetic acid, dilute 10 mL acetic acid with distilled or deionized water to make 100 mL of solution. Note: Solutions of concentrated reagents, such as 37% hydrochloric and 85% phosphoric acids, are percent solutions by mass.
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The solubility of H2S gas = 0.195 m = 0.195 moles of H2S is dissolved in 1 kg of water (solvent).
1 kg of solvent contains = {tex}\frac { 1000 } { 18 }{/tex}= 55.55 moles
Moles fraction of H2S gas in solution =
{tex}x _ { \mathrm { H } _ { 2 } \mathrm { S } } = \frac { n _ { \mathrm { H } _ { 2 } \mathrm { S } } } { n _ { \mathrm { H } _ { 2 } \mathrm { S } } + n _ { \mathrm { H } _ { 2 } \mathrm { O } } }{/tex}{tex}= \frac { 0.195 } { 0.195 + 55.55 } = \frac { 0.195 } { 55.745 }{/tex}= 0.0035
Pressure at STP = 0.987 bar = 1 atm
{tex}p _ { \mathrm { H } _ { 2 } \mathrm { s } } = \mathrm { K } _ { \mathrm { H } } \times x _ { \mathrm { H } _ { 5 } ; \mathrm { K } _ { \mathrm { H } } } = \frac { 0.987 \mathrm { bar } } { 0.0035 }{/tex}= 282 bar
Thus, the Henry's constant = 282 bar
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Manika Gupta 6 years, 7 months ago
1Thank You