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Calculate Molality of 2.5 g of …

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Calculate Molality of 2.5 g of ethanoic acid (CH3COOH) in 75 g of benzene .

Posted by Ankit Raj 4 years, 10 months ago

CBSE > Class 12 > Chemistry

2 answers

Sourav Kr Singh Parmar 4 years, 10 months ago

Molality of ethanoic acid =2.5/60*1000/75=0.5556

1Thank You

Praveen Singh 4 years, 10 months ago

Mass of solute=2.5g Mass of solvent=75g Molar mass of solute=2C+4H+2O =12*2+4*1+2*16 =24+4+32 =60g Moles of solute=2.5/60 =0.042mol Molality=number of moles of solute/mass of solvent in kg m=0.042*1000/75 =0.56mol/Kg

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