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Sia ? 6 years, 3 months ago
According to the question, a solution containing 1.9 g per 100 mL of KCl (M = 74.5 g mol–1 ) is isotonic with a solution containing 3 g per 100 mL of urea (M = 60 g mol–1 ).
As solution is isotonic,
{tex}\pi_1{/tex} (urea) = {tex}\pi _2 {/tex} (KCI)
{tex}\Rightarrow {/tex}C1RT = iC2RT
{tex}\Rightarrow {/tex}{tex}\frac { n _ { 1 } } { V 1 } = \mathrm { i } \frac { n _ { 2 } } { V 2 }{/tex} ({tex}\because {/tex}V1 = V2)
{tex}\Rightarrow {/tex}{tex}\frac { 3 } { 60 } = \mathrm { i } \times \frac { 1.9 } { 74.5 }{/tex}
{tex}\Rightarrow {/tex}i = 1.96
We know that, {tex}\alpha = \frac { i - 1 } { n - 1 }{/tex}
{tex}= \frac { 1.96 - 1 } { 2 - 1 } \\= 0.96{/tex}
= 96%
Posted by Himanshu Upadhyay 6 years, 3 months ago
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Racemization occurs when one pure form of an enantiomer is converted into equal proportion of both enantiomers, forming a racemate.
Posted by Rutuja Murhe 4 years, 6 months ago
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Conductivity is the conductance per unit volume of the solution; it may also be considered as the concentration of ions per unit volume of solution. Molar Conductivity is the conductance of the entire solution having 1 mole of electrolyte dissolved in it.
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{tex}Mole\;fraction,\;x\;=\frac{\frac wm}{\frac wm+\frac WM}{/tex}
(where, w and m represent the mass and molar mass of solute and W and M represent the mass and molar mass of solvent.)
{tex}\frac1x\;=\frac{\frac wm+\frac WM}{\frac wm}{/tex}
{tex}\frac1x=1+\frac{W\times m}{M\times w}\times\frac{1000}{1000}{/tex}
{tex}\frac1x=1+\frac{1000}{M\times m}{/tex}({tex}\because{/tex}Molality, {tex}m=\frac{w\times1000}{m\times W}{/tex})
{tex}=1+\frac{1000}{18\times4.5}{/tex} ({tex}\because{/tex} Molor mass of H2O=18gmol-1)
{tex}=1+\frac{1000}{81}{/tex}
{tex}=\frac{1081}{81}=13.34{/tex}
{tex}x=\frac1{13.34}=0.075{/tex}
Posted by Divyansh Batra 6 years, 3 months ago
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Given, Mass of solute (glycerol) (W2) =?
Molar mass of solute (M2) = 92 g mol-1
Mass of solvent (water) (W1) = 500g
{tex}\Delta{/tex}Tb = 100.42oC - 100oC
= 0.42oC = 0.42 k
Kb = 0.512 k kg mol-1
{tex}\therefore{/tex} {tex}\Delta{/tex}Tb = Kb {tex} \times \frac{{{W_2}}}{{{M_2}}}{/tex}{tex}\times{/tex} {tex}\frac{100}{W_1}{/tex} {tex}\therefore{/tex} W2 = {tex}\frac{{{\Delta T_b} \times {M_2}\, \times {W_1}\,}}{{{K_b} \times \,100}}{/tex}
W2 = {tex}\frac{{0.42 \times 92\, \times 500\,}}{{0.512 \times 1000}}{/tex}
W2 = 37.73 g
Hence, the mass of glycerol dissolved = 37.73 g.
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The Sandmeyer reaction is a chemical reaction used to synthesize aryl halides from aryl diazonium salts using copper salts as reagents or catalysts. It is an example of a radical-nucleophilic aromatic substitution.

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H2SO4, 413 K
{tex}\underset{Ethanol}{2\;CH_3-CH_2-OH}\rightarrow\underset{Ethoxy\;ethane\;(or\;Diethyl\;ether)}{CH_3-CH_2-O-CH_2-CH_3\;+\;H_2O}{/tex}
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