A solution of glycerol C3H8O3 in …
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Sia ? 4 years, 7 months ago
Given, Mass of solute (glycerol) (W2) =?
Molar mass of solute (M2) = 92 g mol-1
Mass of solvent (water) (W1) = 500g
{tex}\Delta{/tex}Tb = 100.42oC - 100oC
= 0.42oC = 0.42 k
Kb = 0.512 k kg mol-1
{tex}\therefore{/tex} {tex}\Delta{/tex}Tb = Kb {tex} \times \frac{{{W_2}}}{{{M_2}}}{/tex}{tex}\times{/tex} {tex}\frac{100}{W_1}{/tex} {tex}\therefore{/tex} W2 = {tex}\frac{{{\Delta T_b} \times {M_2}\, \times {W_1}\,}}{{{K_b} \times \,100}}{/tex}
W2 = {tex}\frac{{0.42 \times 92\, \times 500\,}}{{0.512 \times 1000}}{/tex}
W2 = 37.73 g
Hence, the mass of glycerol dissolved = 37.73 g.
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