the mole fraction of methanol in …
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Posted by Deepanshi Tripathi 4 years, 7 months ago
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Sia ? 4 years, 7 months ago
{tex}Mole\;fraction,\;x\;=\frac{\frac wm}{\frac wm+\frac WM}{/tex}
(where, w and m represent the mass and molar mass of solute and W and M represent the mass and molar mass of solvent.)
{tex}\frac1x\;=\frac{\frac wm+\frac WM}{\frac wm}{/tex}
{tex}\frac1x=1+\frac{W\times m}{M\times w}\times\frac{1000}{1000}{/tex}
{tex}\frac1x=1+\frac{1000}{M\times m}{/tex}({tex}\because{/tex}Molality, {tex}m=\frac{w\times1000}{m\times W}{/tex})
{tex}=1+\frac{1000}{18\times4.5}{/tex} ({tex}\because{/tex} Molor mass of H2O=18gmol-1)
{tex}=1+\frac{1000}{81}{/tex}
{tex}=\frac{1081}{81}=13.34{/tex}
{tex}x=\frac1{13.34}=0.075{/tex}
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