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Nitin Dadhich 6 years, 9 months ago
Posted by Nitin Dadhich 6 years, 9 months ago
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Honey ??? 6 years, 9 months ago
Posted by Aditya Solanki 6 years, 4 months ago
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Sia ? 6 years, 4 months ago
Steps of construction:
- Draw a circle with the help of a bangle.
- Take two non-parallel chords AB and CD of this circle.
- Draw the perpendicular bisectors of AB and CD. Let these intersect at O.
Then O is the centre of this circle drawn. - Take a point P outside the circle.
- Join PO and bisect it. Let M be the mid-point of PO.
- Taking M as centre and MO as radius, draw a circle. Let it intersect the given circle at the points Q and R.
- Join PQ and PR.
Then, PQ and PR are the required two tangents.
Then {tex}\angle PQO{/tex} is an angle in the semicircle and therefore,
{tex}\angle PQO = 90^\circ {/tex}
{tex} \Rightarrow PQ \bot OQ{/tex}
Since OQ is a radius of the given circle, PQ has to be a tangent to the circle.
Similarly, PR is also a tangent to the circle.
Posted by Hasan Siddiqui 5 years, 8 months ago
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Posted by Raftaar Singh Thakur 6 years, 9 months ago
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Honey ??? 6 years, 9 months ago
Alka Shaw 6 years, 9 months ago
Posted by Lucky Sharma 6 years, 4 months ago
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Sia ? 6 years, 4 months ago
According to the question,
Diameter of the copper wire = 1 cm
Radius of the copper wire = 0.5 cm
Length of the copper rod = 8 cm
Volume of the cylinder = {tex}\pi r^2 h{/tex}
{tex}=\pi(0.5)^2 10{/tex}.....(i)
Length of the wire = 18 m = 1800 cm
Volume of the wire ={tex}\pi r^2 h{/tex}
{tex}=\pi(r)^2. 1800{/tex}
By equating both the equations. we get,
r2 = 200.00044
r= 0.033 cm
Therefore, The thickness of the wire is 0.033 cm.
Posted by Preeti Rahi 6 years, 9 months ago
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Jayesh Agrawal 6 years, 9 months ago
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Sia ? 6 years, 4 months ago
Radius of the cone = 52.5m
Height of the cylinder = 3m
Slant height of the cone = 53m
Area of the canvas = curved surface area of cone + curved surface area of cylinder = 2{tex}\pi{/tex} rh + {tex}\pi{/tex}rl
{tex}= \left( 2 \times \frac { 22 } { 7 } \times 52.5 \times 3 + \frac { 22 } { 7 } \times 52.5 \times 53 \right) \mathrm { m } ^ { 2 }{/tex} {tex}{/tex}
{tex}= \frac { 22 } { 7 } \times 52.5 ( 6 + 53 ) \mathrm { m } ^ { 2 } = 9735 \mathrm { m } ^ { 2 }{/tex}
Posted by Shanu Pathania 6 years, 9 months ago
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Honey ??? 6 years, 9 months ago
2Thank You