CBSE > Class 10 > Mathematics | CBSE Board | Homework Help

tanA + cosecB)² - (cotB - secA)² = tan²A + cosec²B + 2 tanA cosecB -(cot²B + sec²A - 2 cotB secA) ( using (a±b)² = a² + b² ± 2ab) = tan²A + cosec²B + 2tanA cosecB - cot²B - sec²A + 2cotB secA Rearranging above equation we get cosec²B - cot²B - sec²A + tan²A + 2tanA cosecB + 2cotB secA = (cosec²B - cot²B) - (sec²A - tan²A) + 2tanA cotB ( cosecB/cotB + secA/tanA ) = 1 - 1 + 2tanA cotB { (1/sinB)/(cosB/sinB) + (1/cosA)/(sinA/cosA) } ( As cosec²ø - cot²ø = 1 sec²ø - tan²ø = 1) = 0 + 2tanA cotB { (1/sinB) x (sinB/cosB) + (1/cos A) x ( cosA/sinA) } = 2tanA cotB ( 1/cosB + 1/sinA) = 2tanA cotB (secB + cosecA) = 2tanA cotB (cosecA + secB) Read more on Brainly.in - https://brainly.in/question/2314597#readmore

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Is it necessary to write steps of construction in board exam ? I saw last year topper answer sheet he/she had not written.?

Posted by Ashutosh Dubey 6 years, 9 months ago

CBSE > Class 10 > Mathematics

2 answers

Amayra Singhania 6 years, 9 months ago

Ya it is necessary. Agr tum steps miss krte ho to tumhare marks ct skte hain. And diksha a/q justification diya jata h step nhi.

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Diksha Kharwal 6 years, 9 months ago

Noo if it is write in question paper so you have to write

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What is the trick to solve the any trigonometry question

Posted by Abhishek Kumar Shah 6 years, 9 months ago

CBSE > Class 10 > Mathematics

2 answers

Charan Bhargav 6 years, 9 months ago

Try your level best.... If u still won't get, multiply both LHS and RHS by zero. Therefore, LHS=RHS..U WILL SURELY GET 2MARKS FOR 4????

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Anushka Jugran❣️ 6 years, 9 months ago

U just need to learn all the identities properly.. Learn the trigonometric ratios.. Practice as many questions of this chapter as possible.. Soon u will find it easy..

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Do compound interest and simple interest form AP????

Posted by Preeti Rahi 6 years, 9 months ago

CBSE > Class 10 > Mathematics

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Rashers got a playing top as his birthday present which surprisingly had no colour on it he wanted to colour it with his crayons the top is shaped like a cone surmounted by a hemisphere the entire top is 5cm in height and the diameter of the top is 3.5cm find the area has to colour

Posted by Harshit Chauban 6 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 4 months ago

Surface area to colour = surface area of hemisphere + curved surface area of cone

Diameter of hemisphere = 3.5 cm

So radius of hemispherical portion of the lattu = r = {tex}\frac { 3.5 } { 2 } \mathrm { cm }{/tex} = 1.75
r = Radius of the concial portion = {tex}\frac{3.5}2{/tex} = 1.75
Height of the conical portion = height of top - radius of hemisphere = {tex}{/tex} 5 - 1.75 = 3.25 cm
Let I be the slant height of the conical part. Then,
{tex}l^2=h^2+r^2{/tex}

{tex}\begin{array}{l}l^2=(3.25)^2+(1.75)^2\\\Rightarrow l^2\;=10.5625+3.0625\\\Rightarrow l^2=13.625\\\Rightarrow l=\sqrt{13.625}\\\Rightarrow l=3.69\end{array}{/tex}
Let S be the total surface area of the top. Then,
{tex}S = 2 \pi r ^ { 2 } + \pi r l{/tex}
{tex}\Rightarrow \quad S = \pi r ( 2 r + l ){/tex}
{tex}\begin{array}{l}\Rightarrow S=\frac{22}7\times1.75(2\times1.75+3.7)\\\;\;\;\;=\;5.5(3.5+3.7)\\=5.5(7.2)\\=39.6\;cm^2\end{array}{/tex}

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Why we are taking a-3d,a-d,a+d,a+3d in ap as consecutive no.?

Posted by Bhuvan Goyal 6 years, 9 months ago

CBSE > Class 10 > Mathematics

1 answers

Ashutosh Dubey 6 years, 9 months ago

Because their differences are equal

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Find two no.whose sum is 27and product is 182

Posted by Sukhdev Singh 6 years, 9 months ago

CBSE > Class 10 > Mathematics

2 answers

Prachi Varshney 6 years, 9 months ago

Let the two numbers be x &y x+y=27 .... (I) xy=182 (x+y) ²=x²+2xy+y² 27²=x²+y²+2×182 729=x²+y²+364 x²+y²=729-364 x²+y²=365 (x-y) ²=x²+y²-2xy (x-y) ²=365-364 (x-y) ²=1 x-y=1 .... (II) adding (I) &(II) 2x=28 x=14 y=13 Read more on Brainly.in - https://brainly.in/question/1858456#readmore

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Puja Sahoo 6 years, 9 months ago

Its ncert question

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Maths important questions

Posted by Borra Pushpalatha 6 years, 9 months ago

CBSE > Class 10 > Mathematics

1 answers

Puja Sahoo 6 years, 9 months ago

Check out in this app

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3x + y =1 (2k-1) x+(k-1)y = 2k + 1

Posted by Akankshya Nayak 6 years, 9 months ago

CBSE > Class 10 > Mathematics

1 answers

Sneha Singh?????? 6 years, 9 months ago

What's ur question

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How long does a train 110 meters running at the rate of 36km/hr take to cross a bridge 132 in length ?

Posted by Ketan Dhiman 6 years, 9 months ago

CBSE > Class 10 > Mathematics

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Prove:- (sinA+cosecA) square + (cosA+sec) square = 7+tan square A + cot square A

Posted by Gautam Nirmaan Gautam Nirmaan 6 years, 9 months ago

CBSE > Class 10 > Mathematics

1 answers

Sneha Singh?????? 6 years, 9 months ago

L.H.S =(sin²A + cosec²A + 2sinAcosecA) + (cos²A + sec²A + 2cosAsecA) = Sin²A + cos²A + 2sinAcosecA + 2cosAsecA + cosec²A + sec²A = 1 + 2 × 1 + 2×1 + cosec²A + sec²A = 5 + ( 1+ cot²A ) + ( 1+ tan²A) = 7 + tan²A + cot²A

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A tower AB is 20m high and BC its shadow on the ground is 20 3m long. Find sun's altitude

Posted by Shruti Priya 6 years, 9 months ago

CBSE > Class 10 > Mathematics

2 answers

Sneha Singh?????? 6 years, 9 months ago

Tan 30°

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Ajay King 6 years, 9 months ago

20√3 hoga question me .....

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What do you mean by conjecture and contradiction

Posted by Nikhil Dhouni 6 years, 9 months ago

CBSE > Class 10 > Mathematics

1 answers

Abhishek Yadav 6 years, 9 months ago

Conjecture means to predict something While contradiction means to oppose

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Two circular flower beds have been on the sides of a square lawn ABCD of side 56 m. if the center of each circular flower bed is the point of intersection O of the diagonals of the square lawn, find the sum of the areas of the lawn and the flower beds.

Posted by Shipu Kumar 6 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 4 months ago

Given side of the square = 56 m
From the fig in {tex}\Delta{/tex}BCD,
BD² = BC² + DC²
{tex}\Rightarrow{/tex} BD² = 2(56)²
{tex}\Rightarrow \mathrm{BD}=56 \sqrt{2} \;\mathrm{m}{/tex}
We know that diaganols of a square are equal and perpendicular bisector of each other,
{tex}\Rightarrow{/tex} AC = BD = {tex}56 \sqrt{2} m{/tex}
and AO = BO = CO = DO = {tex}\frac{56 \sqrt{2}}{2}=28 \sqrt{2} \;m{/tex}
Also area({tex}\Delta{/tex}AOD) = area({tex}\Delta{/tex}DOC) = area ({tex}\Delta{/tex}BOC) = area({tex}\Delta{/tex}AOB)
{tex}=\frac{1}{4} \operatorname{area}(\mathrm{ABCD})=\frac{1}{4} \times(56)^{2}=\frac{3136}{4}=784 \;\mathrm{m}^{2}{/tex}
and Area a sector OAB = Area sector OCD {tex}=\frac{1}{4} \pi \times(28 \sqrt{2})^{2}{/tex}
{tex}=\frac{1}{4} \times \frac{22}{7} \times 1568{/tex}
= 1232 m²
Thus required area = Area of {tex}\Delta{/tex}AOD + Area of sector ODC + Area of {tex}\Delta{/tex}BOC + Area of sector OAB
= 784 + 1232 + 784 + 1232
= 4032 m²

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In triangle ABC, angle B=135o how would you prove that AC2=AB2+BC2+4[ABC]

Posted by Manoj Kumar 6 years, 9 months ago

CBSE > Class 10 > Mathematics

1 answers

Mr. Raj 6 years, 9 months ago

Wrong question

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Solve the equation (a+b)(X+y)=a ki power 2+b ki power 2.........eq1 (a-b)X+(a+b)y=a ki power 2-2ab-b ki power 2........eq2 Solve for X &y ???????????????

Posted by Nikhil Dhouni 6 years, 9 months ago

CBSE > Class 10 > Mathematics

0 answers

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If the points A ,92034#3

Posted by Janiv Digga 6 years, 9 months ago

CBSE > Class 10 > Mathematics

0 answers

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If the points A (-1,2) B 2,3 Ca,2,

Posted by Janiv Digga 6 years, 9 months ago

CBSE > Class 10 > Mathematics

2 answers

Nikhil Dhouni 6 years, 9 months ago

a=-1???

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Affu 😊 6 years, 9 months ago

Complete your question

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If the HCF of 408 and 1032 is expressible in the 1032m - 408×5,find m.

Posted by Megha Kumari 6 years, 9 months ago

CBSE > Class 10 > Mathematics

2 answers

Megha Kumari 6 years, 9 months ago

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Viksita Bhardwaj 6 years, 9 months ago

8 is the HCF of both the nos. HCF is here expressible in the form 1032m- 408×5. Now, 8= 1032m - 408×5 8=1032m- 2040 8+2040= 1032m 2048= 1032m 2048÷1032= m 128/43=m (ans.) That's what my answer is coming .. If any mistake is done by me please rectify it.

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For what value of k the number -4 is a zero of the polynomial x square -x-(2k+2). Also find the the other Zeroes.

Posted by Thunder ?Yashwanth??? 6 years, 9 months ago

CBSE > Class 10 > Mathematics