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x(sin)3A+y(cos)3A=sinA×cosA and xsinA=ycosA , prove that x2+y2= 1

Posted by Vishu Gupta 6 years, 9 months ago

2 answers

Puja Sahoo 6 years, 9 months ago

x sinA×sin^2A + y cosA×cos^2A = sinA ×cosA.... x sinA × sin^2A + x sinA × cos^2A= sinA×cosA... as xsinA=ycosA..... ab common le jao xsinA ko yu will get x=cosA and y= sinA.... and we know that sin^2A+ cos^2A=1... so, x^2+y^2=1... proved

2Thank You

Anushka Jugran❣️ 6 years, 9 months ago

x sin^3A me se xsinA baahar lelo.. Then xsinA ki jagah ycosA put karo.. Then if u solve u will get y=sin A nd x=cosA... Phir ye value vahan daal do jahan aapko proof karna hai..

2Thank You

ANSWER

The sum of 4 consecutive numbers in an AP is 32 and the ratio of the product of the numbers of the first and the last term to the product of 2 middle terms is 7:15. Find the numbers.

Posted by Mansi Dwivedi 6 years, 9 months ago

CBSE > Class 10 > Mathematics

5 answers

Amit Kumar 6 years, 9 months ago

2,6,10,14

0Thank You

#Miss_Raagini ???? 6 years, 9 months ago

Vry cmn ques

0Thank You

Devanshu Kumawat 6 years, 9 months ago

2,6,10,14.......

0Thank You

Puja Sahoo 6 years, 9 months ago

2,6,10,14........

2Thank You

Anushka Jugran❣️ 6 years, 9 months ago

2,6,10,14

2Thank You

ANSWER

What is Co prime no

Posted by Akash Sharma 6 years, 9 months ago

CBSE > Class 10 > Mathematics

1 answers

Anushka Jugran❣️ 6 years, 9 months ago

Co prime numbers r the numbers which do not have factors other than 1 nd itself..

1Thank You

ANSWER

OPQR is a rhombus whose three vertices P,Qand R lie on a circle of radius 4cm find area of the shaded region

Posted by Rupak Gur 6 years, 9 months ago

CBSE > Class 10 > Mathematics

1 answers

Sahil Rajput 6 years, 9 months ago

Area of rhombus-area of cirlce

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A well of diameter 3m is dug 14m deep .the earth taken out of it has been spread evenly all around it in the shape of a circular ring of width 4m to form an embankment. Find the height of the embankment.

Posted by Sunny Roy 6 years, 9 months ago

CBSE > Class 10 > Mathematics

2 answers

Keerthi . 6 years, 9 months ago

This is most repeated question.....

1Thank You

Sunny Roy 6 years, 9 months ago

1Thank You

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If p(x,y) is any point on the line joining points A(a,0) and B(0,b) then show that x/a+y/b=1

Posted by Ketan Holkar 6 years, 9 months ago

CBSE > Class 10 > Mathematics

2 answers

Puja Sahoo 6 years, 9 months ago

Dusra, hai ki let tge ratio in which p divides ab be k:1 then....x or y coordinates nikalo, by section formula and put it in lhs..... yu will get the answer.......

2Thank You

Puja Sahoo 6 years, 9 months ago

Ho gya solve....ise ap 2 trike se solve kr skte ho, pehla using the slope formula i.e. y1-y2/x1-x2.... by putting slope of AP = slope of AB........

2Thank You

ANSWER

In the figure, find the length of the tangent CD if AP =3cm and PC=8cm.

Posted by Swathi Poojary 6 years, 9 months ago

CBSE > Class 10 > Mathematics

3 answers

Anushka Jugran❣️ 6 years, 9 months ago

Incomplete question... Where is the figure??

2Thank You

Aman Soni 6 years, 9 months ago

where is figure???????

1Thank You

Affu 😊 6 years, 9 months ago

Fig???

4Thank You

ANSWER

√cosecA - 1/√cosecA + 1 + √cosecA+1/√cosecA-1 = 2secA

Posted by __@___ Goel 6 years, 9 months ago

CBSE > Class 10 > Mathematics

2 answers

Ishit__ __? 6 years, 9 months ago

*LCM

3Thank You

Ishit__ __? 6 years, 9 months ago

First take the pcm and that will help you to remove the roots and then put the value of cosec A-1 as cotA then simpify it by taking cot A = CosA/Sin A that at last you will get 2/cosA that is equal to 2secA

2Thank You

ANSWER

Find the ratio in which P(4,m) divides the line segment joining the points A$(2,3) and B(6,-3) . Hence find m

Posted by Haris Ansari 6 years, 9 months ago

CBSE > Class 10 > Mathematics

3 answers

Manpreet Kaur 6 years, 9 months ago

Use section formula

1Thank You

Parul Sharma 6 years, 9 months ago

By using section formula m1x2+m2x1/m1+m2 and m1x2+m2x1/m1+m2 For.x axis 4=k(6)+1(4)/k+1 4=6k+4/k+1 4k+4=6k+4 4k-6k=4-4 -2k=0 K=0 For y axis K(-3)+1(3)/k+1=m -3k+3/k+1=m Put k =0 -3(0)+3/3+1 =m 3/4=m Hence'. m=3/4 and k=0.

0Thank You

@ __R Rajput? 6 years, 9 months ago

Use the formula of. Area of triangle

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ANSWER

Prove that root 5is a irrational no.

Posted by @ __R Rajput? 6 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 4 months ago

Let us prove {tex}\sqrt 5 {/tex} irrational by contradiction.
Let us suppose that {tex}\sqrt 5 {/tex} is rational. It means that we have co-prime integers a and b (b ≠ 0)
Such that {tex}\sqrt 5 = \frac{a}{b}{/tex}
{tex}\Rightarrow {/tex} b {tex}\sqrt 5 {/tex}=a
Squaring both sides, we get
{tex}\Rightarrow {/tex} 5b ² =a² ... (1)
It means that 5 is factor of a²
Hence, 5 is also factor of a by Theorem. ... (2)
If, 5 is factor of a , it means that we can write a = 5c for some integer c .
Substituting value of a in (1) ,
5b² = 25c²
⇒ b² =5c²
It means that 5 is factor of b² .
Hence, 5 is also factor of b by Theorem. ... (3)
From (2) and (3) , we can say that 5 is factor of both a and b .
But, a and b are co-prime .
Therefore, our assumption was wrong. {tex}\sqrt 5 {/tex} cannot be rational. Hence, it is irrational.

0Thank You

ANSWER

Theorem 1.4 that root 2is irrational proof of real number chapter 1 of class 10

Posted by Priyaska Biswas 6 years, 9 months ago

CBSE > Class 10 > Mathematics

1 answers

Ram Kushwah 6 years, 9 months ago

Let us assume that {tex}\sqrt 2{/tex} is rational

so let {tex}\sqrt 2{/tex} ={tex}\frac pq{/tex}

where p and q are integers and also let p and q are not having any common factor

{tex}\begin{array}{l}2=\frac{\mathrm p^2}{\mathrm q^2}\\\mathrm p^2=2\mathrm q^2---(1)\\\mathrm{Hence}\;\mathrm p^{\;2}\;\mathrm{is}\;\mathrm{divisble}\;\mathrm{by}\;2\\\mathrm{so}\;\mathrm p^\;\;\mathrm{is}\;\mathrm{divisble}\;\mathrm{by}\;2---(2)\\\mathrm{let}\;\mathrm p=2\mathrm t\;(\;\mathrm t\;\;\mathrm{is}\;\mathrm a\;\mathrm{positive}\;\mathrm{integer})\\\mathrm{So}\;\mathrm{from}(1)\\2\mathrm q^2=4\mathrm t^2\\\mathrm q^2=2\mathrm t^2\\\mathrm{Hence}\;\mathrm q^{\;2}\;\mathrm{is}\;\mathrm{divisble}\;\mathrm{by}\;2\\\mathrm{so}\;\mathrm q^\;\;\mathrm{is}\;\mathrm{divisble}\;\mathrm{by}\;2---(3)\end{array}{/tex}

From (2) and (3) it follows that

p and q both having 2 as the common factor

But this makes wrong our assumption that p and q are not having any common factor

This has come as we assumed that {tex}\sqrt 2{/tex} is rational.

Hence {tex}\sqrt 2{/tex} is a irrational number

2Thank You

ANSWER

If the radius of the circle is 6cm and length of an arc is 12 cm find area of sector

Posted by Harshita Swami 6 years, 9 months ago

CBSE > Class 10 > Mathematics

1 answers

Ram Kushwah 6 years, 9 months ago

Let angle of arc ={tex}\theta{/tex}

{tex}\begin{array}{l}\mathrm{Length}\;\mathrm{of}\;\mathrm{arc}=\frac{\mathrm\theta}{360}\times2\mathrm{πr}\\\mathrm{so}\;\frac{\mathrm\theta}{360}\times2\mathrm\pi\times6=12\\\frac{\mathrm{θπ}}{360}=1.....(1)\\\mathrm{now}\;\mathrm{area}\;\mathrm{of}\;\mathrm{sector}\\=\frac{\mathrm\theta}{360}\times\mathrm{πr}^2=1\times\mathrm r^2=\mathrm r^2\;(\;\mathrm{from}\;(1))\\=6^2=36\;\mathrm{cm}^2\end{array}{/tex}

1Thank You

ANSWER

If in triangle ABC, AD is median and AE is perpendicular on BC, then prove that AB^2 +AC^2 = 2AD^2 + 1/2 BC^2.

Posted by Yashashva Kesheri 6 years, 9 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

An Ap consist of 37th term the sum of 3 middle most term is 225 and sum of the last 3 term is 429 , find the Ap

Posted by Ashish Singh 6 years, 9 months ago

CBSE > Class 10 > Mathematics

1 answers

#@Prince Arya 6 years, 9 months ago

Let the 1st term be 'a' and common difference be 'd'. No.of terms,n=37 N+1/2=19 Three middle term are 18th,19th and 20th According to questions (a+17d)+(a+18d)+(a+19d)=225 3a+54d=225 a+18d=75 i.e.a=75-18d NOW, sum of last three term i.e. (a+34d)+(a+35d)+(a+36d)=429 a+35d =143 75-18d+35d=143 16d=64 d=4 a=75-18×4=3 AP=3,7,11.....

1Thank You

ANSWER

Prove that opposite sides of a quadrilateral circumscribing a circle subtend supplementary angle at centre of circle

Posted by Neeraj Raj 6 years, 4 months ago

CBSE > Class 10 > Mathematics

1 answers

Sia ? 6 years, 4 months ago

Given: ABCD is a quadrilateral circumscribing a circle whose centre is O.
To prove:

{tex}\angle{/tex}AOB + {tex}\angle{/tex}COD = 180^o
{tex}\angle{/tex}BOC + {tex}\angle{/tex}AOD = 180^o

Construction: Join OP, OQ, OR and OS.

Proof: Since tangents from an external point to a circle are equal.
{tex}\therefore{/tex} AP = AS,
BP = BQ ........ (i)
CQ = CR
DR = DS
In {tex}\triangle{/tex}OBP and {tex}\triangle{/tex}OBQ,
OP = OQ [Radii of the same circle]
OB = OB [Common]
BP = BQ [From eq. (i)]
{tex}\therefore{/tex} {tex}\triangle{/tex}OPB {tex}\cong{/tex} {tex}\triangle{/tex}OBQ [By SSS congruence criterion]
{tex}\therefore{/tex} {tex}\angle{/tex}1 = {tex}\angle{/tex}2 [By C.P.C.T.]
Similarly, {tex}\angle{/tex}3 = {tex}\angle{/tex}4, {tex}\angle{/tex}5 = {tex}\angle{/tex}6, {tex}\angle{/tex}7 = {tex}\angle{/tex}8
Since, the sum of all the angles round a point is equal to 360^o.
{tex}\therefore{/tex} {tex}\angle{/tex}1 + {tex}\angle{/tex}2 + {tex}\angle{/tex}3 + {tex}\angle{/tex}4+ {tex}\angle{/tex}5 + {tex}\angle{/tex}6 + {tex}\angle{/tex}7 + {tex}\angle{/tex}8 = 360^o
{tex}\Rightarrow{/tex} {tex}\angle{/tex}1 + {tex}\angle{/tex}1 + {tex}\angle{/tex}4 + {tex}\angle{/tex}4+ {tex}\angle{/tex}5 + {tex}\angle{/tex}5 + {tex}\angle{/tex}8 + {tex}\angle{/tex}8 = 360^o
{tex}\Rightarrow{/tex} 2 ({tex}\angle{/tex}1 + {tex}\angle{/tex}4 + {tex}\angle{/tex}5 + {tex}\angle{/tex}8) = 360^o
{tex}\Rightarrow{/tex} {tex}\angle{/tex}1 + {tex}\angle{/tex}4 + {tex}\angle{/tex}5 + {tex}\angle{/tex}8 = 180^o
{tex}\Rightarrow{/tex} ({tex}\angle{/tex}1 + {tex}\angle{/tex}5) + ({tex}\angle{/tex}4 + {tex}\angle{/tex}8) = 180^o
{tex}\Rightarrow{/tex} {tex}\angle{/tex}AOB + {tex}\angle{/tex}COD = 180^o
Similarly we can prove that
{tex}\angle{/tex}BOC + {tex}\angle{/tex}AOD = 180^o

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ANSWER

6 & 13 chapter ki optional krni zaroori hai kya? ?

Posted by Mona Sharma ? 6 years, 9 months ago

CBSE > Class 10 > Mathematics

2 answers

Mona Sharma ? 6 years, 9 months ago

Thanks to answer. ?

1Thank You

Yash Malviya 6 years, 9 months ago

No it depends upon you that you want to solve miscellaneous questions. Its not compulsory

1Thank You

ANSWER

In ∆ABC,the line segment XY is parallel to side AC and it divides the triangle into tw equal parts of equal areas.find the ratio AX/AB.

Posted by Khushi Agrawal 5 years, 8 months ago

CBSE > Class 10 > Mathematics

3 answers

Khushi Agrawal 6 years, 9 months ago

Solve plz

0Thank You

Khushi Agrawal 6 years, 9 months ago

How

0Thank You

Ishit__ __? 6 years, 9 months ago

1/2=AX/AB

0Thank You

ANSWER

Find the ratio in which the line segment p(x1,y1) and (x2,y2) is divided by x-axis.

Posted by Sai Ram 6 years, 9 months ago

CBSE > Class 10 > Mathematics

0 answers

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Cosec theta + cot theta= p Then find the value of= P2+1 ---------- = cos theta P2-1

Posted by Sahil Rajput 6 years, 9 months ago

CBSE > Class 10 > Mathematics

2 answers

Sahil Rajput 6 years, 9 months ago

2016 ke paper me hai ja ke phle dekh

2Thank You

Khushi Agrawal 6 years, 9 months ago

Ye question pichle 10 saalon m na puccha gya aur n hi puccha jaega

1Thank You

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If X square + bx + c is equal to zero , a is not equal to zero has equal roots, what is the value of c

Posted by Ayushi Jain 6 years, 9 months ago

CBSE > Class 10 > Mathematics

1 answers

Aditi Kumari 6 years, 9 months ago

bsquare/4

0Thank You

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A hemispherical bowl of internal radius 9 cm is full of water its contents are emptied in a cylindrical vessel of internal radius 6 cm find the height of the water in the cylindrical vessel

Posted by Ayushi Jain 6 years, 9 months ago

CBSE > Class 10 > Mathematics

1 answers

Sahil Rajput 6 years, 9 months ago

Ayushi aah , height is 6 cm

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ANSWER

Express 32760 into product of prime factors

Posted by Ayushi Jain 6 years, 9 months ago

CBSE > Class 10 > Mathematics

1 answers

Ram Kushwah 6 years, 9 months ago

32760 = 2³ X 3²X 5 X 7 X 13

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If triangle ABC and triangle d e f are similar triangles such that angle A is 57degree and Angle E is 83 degree find angle C

Posted by Ayushi Jain 6 years, 9 months ago

CBSE > Class 10 > Mathematics

1 answers

Ram Kushwah 6 years, 9 months ago

{tex}\begin{array}{l}\text{∠A=57°,∠B=∠E=83°}\\\text{So ∠C=180-(∠A+∠B)}\\\text{=180-(57+83)=180-140=40°}\end{array}{/tex}

1Thank You

ANSWER

Find the product of the zeroes of -2x^2+kx+6

Posted by Ayushi Jain 6 years, 9 months ago

CBSE > Class 10 > Mathematics

2 answers

Ranganath Gowda 6 years, 9 months ago

Product of zeros=c÷a 6÷-2 -3

1Thank You

Siddi Reddy Raghunatha Reddy 6 years, 9 months ago

By factorisation 2

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What is thita

Posted by Rajesh Patodia 6 years, 9 months ago

CBSE > Class 10 > Mathematics

3 answers

#@Prince Arya 6 years, 9 months ago

It's same as x,y,a,b ..that we use in algebraic expression

1Thank You

Harsha Asiwal 6 years, 9 months ago

General referral for any of the angles

1Thank You

Gungun ? 6 years, 9 months ago

Name of angle

1Thank You

ANSWER

Find the missing frequency f1and f2 in the following frequency distribution if n=100 and median is 12. Marks obtained 0-10 10-20 20-30. 30-40 40-50. 50-60 No of students 10 f1 25 30 f2 10

Posted by Jhanvi Mehendiratta 6 years, 9 months ago

CBSE > Class 10 > Mathematics

2 answers

Jhanvi Mehendiratta 6 years, 9 months ago

Sir iska pura Sol milega

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Sahil Rajput 6 years, 9 months ago

F1= 13 and f2= 12

1Thank You

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7 years ago,Huma's age was five times the square of Haya's age. After 3 years from now ,Haya's age will be 2/5 times of the age of Huma. Find the diffrence between the ages of Huma and Haya?

Posted by Zarfa Umer 6 years, 9 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

How to draw graph of chapter 2

Posted by Abhishek Kumar Shah 6 years, 9 months ago

CBSE > Class 10 > Mathematics

1 answers

Sahil Singh 6 years, 9 months ago

With pencil

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All the theories of triangle with solutions

Posted by Nayah Khan 6 years, 9 months ago

CBSE > Class 10 > Mathematics

2 answers

Sarthak Paliwal 6 years, 9 months ago

Is given in ncert book

0Thank You

Moyottil Shifu 6 years, 9 months ago

You not write this on your notebook

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ANSWER

mean formula based on step deviation and assumed mean

Posted by Vishnu Ap 6 years, 9 months ago

CBSE > Class 10 > Mathematics

1 answers

Zarfa Umer 6 years, 9 months ago

Step Deviation Method - Mean= a+(f×u/f)×h Where,a=arbitrary value chosen somewhre in middle of xi h=class size u=xi-a/h Assumed mean-Mean=a+f×d/f Where,a=refer to above d=xi-a

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