CBSE > Class 10 > Mathematics | CBSE Board | Homework Help

Ask questions which are clear, concise and easy to understand.

Ask Question

For what value of p, the points (2,1),(p,-7) and (-1,3)are collinear

Posted by Brajmohan Yadav 2 years, 2 months ago

CBSE > Class 10 > Mathematics

1 answers

Naitik Nama 2 years, 2 months ago

(2,1), (p,−1) & (−1,3) are collinear ⇒p−2−1−1=−1−p3−(−1) ⇒p−2−2=−1−p4 ⇒2(1+p)=4(p−2)⇒2+2p=4p−8 ⇒10−2p ∴ p=5

0Thank You

ANSWER

Prove that the √5 is irrational

Posted by Chiluka Sriteja 2 years, 2 months ago

CBSE > Class 10 > Mathematics

3 answers

Priyanshu Singh 2 years, 2 months ago

assume that √5 is rational number √5=a/b (here 'a' and 'b' are co prime) b√5= a Square on both sides (b√5)^2 =(a)^2 5b^2 = a^2.............(i) If a^2 is divisible by 5 than it means that 5 is also divisible by a. Now, let there be another integer 'c' therefore, a=5c square on both side a^2 =25c^2 5b^2 =25c^2 {from equation (i)} then, b^2 =5 c^2 b^2/5 = c^2 If b^2 is divisible by 5 than it means b is also divisible by 5 . Therefore 'a' and 'b' has common factor 5 . But , we ensure that 'a' and 'b' are co prime. Therefore, our assumption is wrong that √5 is rational number. Contradiction occurs. Therefore √5 is irrational numbers.

1Thank You

Gunpreet Kaur 2 years, 2 months ago

lets assume that √5 is rational number √5=a/b (here 'a' and 'b' are co prime) b√5= a Square on both sides (b√5)^2 =(a)^2 5b^2 = a^2.............(i) If a^2 is divisible by 5 than it means that 5 is also divisible by a. Now, let there be another integer 'c' therefore, a=5c square on both side a^2 =25c^2 5b^2 =25c^2 {from equation (i)} then, b^2 =5 c^2 b^2/5 = c^2 If b^2 is divisible by 5 than it means b is also divisible by 5 . Therefore 'a' and 'b' has common factor 5 . But , we ensure that 'a' and 'b' are co prime. Therefore, our assumption is wrong that √5 is rational number. Contradiction occurs. Therefore √5 is irrational numbers.

0Thank You

Gunpreet Kaur 2 years, 2 months ago

0Thank You

ANSWER

CosA divided by 1+ sinA = secA-tanA

Posted by Shawn Jo 2 years, 2 months ago

CBSE > Class 10 > Mathematics

2 answers

Dhwani Panchal 2 years, 2 months ago

SecA+tanA = 1- sinA

0Thank You

Sriya Sharma 2 years, 2 months ago

Cos A/ 1+ sinA Now put cos A as (1- sinA) And put 1+ sinA as ( cos A ) Then it will be (1/ cosA - sinA /cos A) Since 1/cos A is (secA ) And SinA / cosA is( tan A ) Therefore (secA - Tan A ) hence proved ...

0Thank You

ANSWER

The nth term of an ap from the end 2,7,12,17,22.......227 is

Posted by Meet Jadhwani 2 years, 2 months ago

CBSE > Class 10 > Mathematics

2 answers

Gunpreet Kaur 2 years, 2 months ago

AP- 2,7,12,17,22.......227 an=227 a=2 d= 5 , n=? an= a+ (n-1) d 227= 2+ (n-1)(5) 227-2= (n-1)(5) 225/5 = (n-1) 45 +1 =n 46 = n

1Thank You

Ayushi Angra 2 years, 2 months ago

Reverse the series...so that a=227..and then solve using formula an=a+(n-1)d

3Thank You

ANSWER

What was the volume of 20 balls of radius 3.5 mm

Posted by Mohammad Aftab 2 years, 2 months ago

CBSE > Class 10 > Mathematics

1 answers

Raghav Jindal 2 years, 2 months ago

Volume=4πr³/3 4×22/7×35/10×35/10×35/30 179.67mm³

0Thank You

ANSWER

LCM and HCF of 15,20

Posted by Agaru Bhargavi 2 years, 2 months ago

CBSE > Class 10 > Mathematics

4 answers

Abirami N 2 years, 2 months ago

0Thank You

Meet Jadhwani 2 years, 2 months ago

HCF OF 15=3×5 HCF of 20=2×2×5 HCF OF 15,20=5 LCM OF 15,20=60

1Thank You

Pritam Panghal 2 years, 2 months ago

15= 3 × 5 20 = 2×2×5 5 is common in both then, HCF = 5 LCM is product of HCF and other numbers LCM = 5×2×2×3 LCM = 60

1Thank You

Shubham Pathak 2 years, 2 months ago

1Thank You

ANSWER

Hlo Ex 6.2 ques 10

Posted by Arsh Kaur 2 years, 2 months ago

CBSE > Class 10 > Mathematics

1 answers

Priyanshu Singh 2 years, 2 months ago

Ncert ya rs Aggarwal

2Thank You

ANSWER

In the circumference of a circle increase from 4π to 8π , then it's area is

Posted by Tarun Saket 2 years, 2 months ago

CBSE > Class 10 > Mathematics

2 answers

Raghav Jindal 2 years, 2 months ago

Circumference of circle=2πr 4π=2πr 2=r Similarly, 8π=2πr 4=r Area = πr² π×4×4 16π unit²

0Thank You

Gurleen Dhillon 2 years, 2 months ago

2πr=4π πr=4π2/2 πr=2π Put the values =r=2 Area of circle πr2 Put values Ans -88/7

0Thank You

ANSWER

A TV tower stands vertically on a bank of a canal from a point on the other bank of a canal from a point on the other bank directly opposite the tower the angle of elevation of the top of the tower is 60 degree from elevation of from a point 20 m away from this point on the same bank the angle of elevation of the top of the tower is 30 so a find the with of the canal b find the height of the tower c find the distance between top of the tower and point the third find the distance between stop of the tower c

Posted by Rudresh Yadav 2 years, 2 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

✓5

Posted by Vedant Bhosale 2 years, 2 months ago

CBSE > Class 10 > Mathematics

2 answers

Yatharth Yadav 2 years, 2 months ago

Bhosale🤣🤣🤣

0Thank You

Raghav Jindal 2 years, 2 months ago

2.23606798

0Thank You

ANSWER

√3sin = cos find value of 3cos² +2 cos / 3cos+2

Posted by Jigyasa Madaan 2 years, 2 months ago

CBSE > Class 10 > Mathematics

3 answers

Shubham Pathak 2 years, 2 months ago

√3 sinΦ = cosΦ => tanΦ = √3 Φ = 60° ,then 3cos²+ 2 cos/3cos +2 => 3 * 1/4 + 2* 1/2 // 3* 1/2 +2 => 3/4 + 1 // 3/2 +2 => 7/4 * 2/7 = 1/2

0Thank You

Vedant Bhosale 2 years, 2 months ago

Wrong spelling

1Thank You

Vedant Bhosale 2 years, 2 months ago

Byr

2Thank You

ANSWER

Blue print of mathematics

Posted by Sampat Rashmi Patro 2 years, 2 months ago

CBSE > Class 10 > Mathematics

2 answers

Pooja Naval 2 years, 2 months ago

Same search 🔍 on Google you definitely find it

1Thank You

Vipin Khola 2 years, 2 months ago

Ufnk

4Thank You

ANSWER

Solve for x: (x+1/x-1)+(x-2/x+2)=4-(2x+3/x-2)

Posted by D.Thrishanth Reddy 2 years, 2 months ago

CBSE > Class 10 > Mathematics

1 answers

Naitik Nama 2 years, 2 months ago

Let's solve your equation step-by-step. �+1�−1+�−2�+2=4−(2�+3�−2) 2�2+�−1�=−2�2+6�−3� Step 1: Multiply both sides by x. 2�2+�−1=−2�2+6�−3 Step 2: Multiply both sides by x. 2�3+�2−�=−2�3+6�2−3� 2�3+�2−�−(−2�3+6�2−3�)=−2�3+6�2−3�−(−2�3+6�2−3�)(Subtract -2x^3+6x^2-3x from both sides) 4�3−5�2+2�=0 �(4�2−5�+2)=0(Factor left side of equation) �=0or4�2−5�+2=0(Set factors equal to 0) �=0 Check answers. (Plug them in to make sure they work.) �=0(Doesn't work in original equation)

0Thank You

ANSWER

If the sum of the first 14 terms of an AP is 1050 and its first term is 10 find the 20th term

Posted by Atharv Mishra 2 years, 2 months ago

CBSE > Class 10 > Mathematics

3 answers

Rohan Baisoya 2 years, 2 months ago

20th term is200

0Thank You

जय श्री राम🚩🚩 .... 2 years, 2 months ago

Here, S14 = 1050, n = 14, a = 10. We know that Sn = (n2)[2a+(n−1)d] Substituting the values we have, 1050=(142)[20+13d] ⇒1050=140+91d ⇒910=91d ⇒d=10 Therefore, a20=10+(20–1)×10=200 i.e. 20th term is 200.

2Thank You

D.Thrishanth Reddy 2 years, 2 months ago

200 is the 20th term

3Thank You

ANSWER

A chord of circle is 20 cm in length and its distance from the center is 24cm. Find the radius of circle

Posted by Aayushi Singh 2 years, 2 months ago

CBSE > Class 10 > Mathematics

4 answers

Piyush Sahani 2 years, 2 months ago

24•24-20•20=√176=14

0Thank You

Aditya Bansal 2 years, 2 months ago

26 cm ( by using Pythagoras theorem )

0Thank You

जय श्री राम🚩🚩 .... 2 years, 2 months ago

Here, AB = 20cm and OC = 24cm Now, AC=CB=2AB=10cm (perpendicular drawn from centre of the circle to the chord,bisects the chord) Then using Pythagorean Theorem: OA=(AC2+OC2)=(102+242)=676=26

1Thank You

D.Thrishanth Reddy 2 years, 2 months ago

26cm is radius

0Thank You

ANSWER

A solid is in the form of a cylinder with hemispherical end . The total height of the solid is 20cm and diameter of cylinder is 7cm . Find the total volume of solid . (use pie =22/7)

Posted by Navneet Kaur Sekhon 2 years, 2 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

3+3√2+√2

Posted by Og Youweee 2 years, 2 months ago

CBSE > Class 10 > Mathematics

4 answers

Piyush Sahani 2 years, 2 months ago

3+3√4

0Thank You

Navneet Kaur Sekhon 2 years, 2 months ago

3+4√2

1Thank You

Diva Shah 2 years, 2 months ago

Therefore 3(1+√3)

0Thank You

Diva Shah 2 years, 2 months ago

It's 3+3√3

0Thank You

ANSWER

Outside a circle of centres TP and tq are drawn to a circle prove that what is the right bisector of a line segment PQ

Posted by Harshith M. V 2 years, 2 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Let a and b be two positive integers such that a=p²q⁴and b=p²q³,where p and q are prime numbers. If hcf(a,b)p q and lcm (a,b)=pŕ qş,then (mtn)(rts)

Posted by Sumit Kumar 2 years, 2 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

The x-coordinate of a point P is twice it's y-coordinate . If P is equidistant from Q(2,-5) and R(-3,6) , find the co-ordinates of P .

Posted by Gaurav Narwar 2 years, 2 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

A man earns 600rs per month more than his wife. One tenth of the man's salary and one sixth of the salary amount to 1500 which is saved every month find their income

Posted by Niti Viramgama 2 years, 2 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Hlo friends plz asa koi chapters btado Jo asan ha aur paper ma ps hoja unko krka

Posted by Rakhi Negi 2 years, 2 months ago

CBSE > Class 10 > Mathematics

1 answers

Swayam Mani Gautam 2 years, 2 months ago

Polynomial

0Thank You

ANSWER

Maths laboratory activity 32 solution

Posted by Jayesh Ahire 2 years, 2 months ago

CBSE > Class 10 > Mathematics

0 answers

ANSWER

Find the cubic polynomial with the sum Sum of the product of its zeros taken to at a time and the product of its zeros at 5 - 2 and - 24 respectively

Posted by Naidile C Dharwad 2 years, 2 months ago

CBSE > Class 10 > Mathematics

1 answers

Nikita Yadav 2 years, 1 month ago

Cubic polynomial=x³-(5)x²+(-2)x-(-24) =x³-5x²-2x+24

0Thank You

ANSWER

If √3_1\√3+1

Posted by Satyam Yadav 2 years, 2 months ago

CBSE > Class 10 > Mathematics

1 answers

Diva Shah 2 years, 2 months ago

1/2+√3

0Thank You

ANSWER

Given a=3,n=8,S=192, find d

Posted by Aman Khan 2 years, 2 months ago

CBSE > Class 10 > Mathematics

5 answers

Navpreet Bal 2 years, 2 months ago

Sn=n/2[2a+(n–1)d] 192=8/2[2×3+(8–1)d] 192=4[6+7d] 192-42=6+7d 48=6+7d 48-6=7d 42=7d d=42/7 d=6

0Thank You

Pratiksha Yadav 2 years, 2 months ago

D = 6

1Thank You

Aman Khan 2 years, 2 months ago

Kaise

0Thank You

Jatin Bansal 2 years, 2 months ago

1Thank You

Nandini . 2 years, 2 months ago

D=6

3Thank You

ANSWER

Hlw friends.......Exam ki preparation kaisi chal rahi hai.. 🥰

Posted by Chinki 🦋👈🏻 2 years, 2 months ago

CBSE > Class 10 > Mathematics

5 answers

Ashish Yadav 2 years, 2 months ago

Tagri

2Thank You

Aman Khan 2 years, 2 months ago

Achhe se chal rahi h

3Thank You

Saumya Singh 2 years, 2 months ago

Baith gyi hai

3Thank You

Shubham Pathak 2 years, 2 months ago

Bas chal hi rhi hai , kash daurti !!

3Thank You

Priya Yadav 2 years, 2 months ago

Thik chal rahi hai

3Thank You

ANSWER

What is 2 + 2

Posted by Salim Siddiqui 2 years, 2 months ago

CBSE > Class 10 > Mathematics

5 answers

Jatin Bansal 2 years, 2 months ago

0Thank You

Shubham Pathak 2 years, 2 months ago

1Thank You

Om Kumar 2 years, 2 months ago

0Thank You

Nikhil Ranjan 2 years, 2 months ago

2Thank You

Salim Siddiqui 2 years, 2 months ago

0Thank You

ANSWER

(a+b)(a-b)=

Posted by Dattatrey Mangavati 2 years, 2 months ago

CBSE > Class 10 > Mathematics

5 answers

Abhishek Dubey 2 years, 2 months ago

a²-b²

2Thank You

𝕷𝖊𝖌𝖊𝖓𝖉 🏆 🍑 🎀 𝒜𝓁☯𝓃𝑒 𝑅𝒶𝓈𝒽𝒾 🎀 🍑 2 years, 2 months ago

a²-b²

2Thank You

Pratha Shrivastava 2 years, 2 months ago

a²-b²

2Thank You

Radhika Bhardwaj 2 years, 2 months ago

a²-b²

2Thank You

Dattatrey Mangavati 2 years, 2 months ago

a²-b²

2Thank You

ANSWER

If tan theeta =a/x then x/root off a square +xsqure

Posted by Noufal Kasala 2 years, 2 months ago

CBSE > Class 10 > Mathematics

1 answers

Preeti Dabral 2 years, 2 months ago

Value of $\frac{x}{\sqrt{a^2+x^2}}$

$\tan \theta=\frac{\mathrm{a}}{\mathrm{x}} Since, \begin{aligned} & \frac{x}{\sqrt{a^2+x^2}} \\ & \Rightarrow \frac{\frac{a}{\tan \theta}}{\sqrt{a^2+\left(\frac{a}{\tan \theta}\right)^2}} \\ & \Rightarrow \frac{\frac{a}{\tan \theta}}{\sqrt{a^2+\frac{a^2}{\tan ^2 \theta}}} \end{aligned}$

$\begin{aligned} & \Rightarrow \frac{\frac{a}{\tan \theta}}{a \sqrt{\frac{1+\tan ^2 \theta}{\tan ^2 \theta}}} \\ & \Rightarrow \frac{\frac{1}{\tan \theta}}{\sqrt{\frac{1+\tan ^2 \theta}{\tan ^2 \theta}}} \\ & \Rightarrow \frac{1}{\sqrt{\sec ^2 \theta}} \\ & \Rightarrow \frac{1}{\sec \theta} \end{aligned}$