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For what value of p, the …

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For what value of p, the points (2,1),(p,-7) and (-1,3)are collinear
  • 1 answers

Naitik Nama 1 year, 2 months ago

(2,1), (p,−1) & (−1,3) are collinear  ⇒p−2−1−1​=−1−p3−(−1)​ ⇒p−2−2​=−1−p4​ ⇒2(1+p)=4(p−2)⇒2+2p=4p−8                                                 ⇒10−2p        ∴   p=5
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