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find the value of x3+y3+z3-3xyz if …

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find the value of x3+y3+z3-3xyz if x2+y2+z2=83 and x+y+z=15
  • 2 answers

Gopal Paul 2 weeks, 5 days ago

x²+y²+z²=(x+y+z)²-2(xy+yz+zx) Or, 83=(15)²-2(xy+yz+zx) Or, 225-83=2(xy+yz+zx) Or, 142÷2=xy+yz+zx Or, xy +yz+zx = 71 We know, x³+y³+z³-3xyz=(x+y+z) (x²+y²+z²-xy-yz-zx) Or, x³+y³+z³-3xyz=15(83-71) =15×12 =180 Therefore, x³+y³+z³-3xyz=180

Himanshu Sharma 2 weeks, 5 days ago

find the value of x3+y3+z3-3xyz if x2+y2+z2=83 and x+y+z=15
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