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function f is defined as f(x) = {2x+2, x<2; k, x=2; 3x, x>2} find the value of k for which the function f is continuous at x=2

Posted by Krishnanjali Nigam 4 months, 4 weeks ago

CBSE > Class 12 > Mathematics

2 answers

Account Deleted 4 months, 3 weeks ago

It is continuous at x=2 Then, LHL: lim x-2–. f(x)= (2x+2)= 2*2+2=6 RHL: lim x-2+.f(x)=3x= 3*2=6 and at 'K' x=2 which is independent of any terms of X or exponential power of X . So,by comparing LHL and RHL we get solutions which is K = 6. Hence,K=6.

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Jaideep Debnath 4 months, 3 weeks ago

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