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# If the a=50,d=-4 and Sn =0 …

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If the a=50,d=-4 and Sn =0 then find n.

Deepali Vishnoi 2 months ago

The distance between the points (0,2/5)and (-2/5,0)is

Shuhbham Mahakud 2 months ago

Sn = n/2 [2a + (n-1)d] Substituting values :- 0 = n/2 [2(50) + (n-1)(-4)] 0 = n/2 [100 - 4n + 4] 0 = n/2 [104 - 4n] 0 = n/2 × 4 [ 26 - n ] 0 = 2n [ 26 - n ] 0 = 26 - n - 26 = - n 26 = n. This should be the answer according to me.

Its Vicky 2 months ago

Sn = n/2 [2a + (n-1)d] Substituting values :- 0 = n/2 [2(50) + (n-1)(-4)] 0 = n/2 [100 - 4n + 4] 0 = n/2 [104 - 4n] 0 = n/2 × 4 [ 26 - n ] 0 = 2n [ 26 - n ] 0 = 26 - n - 26 = - n 26 = n. This should be the answer according to me.

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