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Prove √2 in easy method pls

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Prove √2 in easy method pls
  • 3 answers

Anand Yadav 2 months, 3 weeks ago

√2 is a irrational number √2b=a { a and b are the co prime } √2b=a { both side are squaring} 2b=a { a is divisible by 2 } {2 is divisible by a } Let a=√2c. { c is an integer } 2b=√2c {squaring of √2c } 2b=2c. { c is divisible by 2} { b is divisible by 2} Where a and b are common factor So contradiction is a is √2 irrational number when wrong assertion

Mehakpreet Sandhu 2 months, 3 weeks ago

Watch dear sir video on YouTube

Aditya Singh 2 months, 4 weeks ago

You write direct Latsume to √2 is a rational number Where , √2=p/q =√2p=
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