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1+sec/sec = sin^2A/1-cos

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1+sec/sec = sin^2A/1-cos
  • 1 answers

Naitik Rajput 2 months, 3 weeks ago

1+sec/sec = sin²A/1-cos 1/sec+sec/sec = 1-cos²/1-cos Cos+1=(1-cos)(1+cos)/1-cos Cos +1 =1+cos LHS = RHS
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