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# A transformer has 500 primary turns …

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A transformer has 500 primary turns and 10 secondary turns. If the secondary has resistive load of 15 Ω, the currents in the primary and secondary

Krish Agrawal 3 months, 3 weeks ago

To calculate the currents in the primary and secondary of a transformer, you can use the transformer equation, which relates the primary and secondary voltages and currents. The equation is: (Vp / Vs) = (Np / Ns) Where: - Vp is the primary voltage. - Vs is the secondary voltage. - Np is the number of turns in the primary coil. - Ns is the number of turns in the secondary coil. In your case, you have: - Np = 500 - Ns = 10 Now, let's calculate the primary voltage (Vp) and the secondary voltage (Vs). The primary voltage (Vp) is typically the voltage applied to the primary coil. To find it, you would need more information, such as the source voltage. Assuming you have the primary voltage (Vp), you can use the equation to find the secondary voltage (Vs): (Vp / Vs) = (Np / Ns) Vs = Vp * (Ns / Np) Now, we need to calculate the currents in the primary and secondary. Use Ohm's Law: I = V / R Where: - I is the current. - V is the voltage. - R is the resistance. For the secondary: - Vs is the voltage (which you've found). - The resistive load is 15 Ω. Isolate the secondary current (Is) and calculate it: Is = Vs / Rs Is = Vs / 15 Ω For the primary current (Ip), you can use the transformer equation again: (Vp / Vs) = (Np / Ns) Ip = Is * (Ns / Np) Substitute the values you have to calculate Ip. Please note that to get precise values, you would need the primary voltage (Vp). Without that information, you won't be able to calculate the exact currents in the primary and secondary coils.

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