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Integrat this.. (3 sinx-2) cosx/5- cos …

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Integrat this.. (3 sinx-2) cosx/5- cos square x-4 sinx
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Lekha Raj 8 years, 4 months ago

(3sinx-2)cosx/5-cos^2x-4sinx Or (3sinx-2)cosx/5-(1-sin square x)-4sinx Let sinx =t This implies : cosx dx=dt Subsitute the value in the ques We get Integration ( 3t-2)/5-1+t square -4t dt ( 3t-2)/4+t square - 4t dt (3t-2)/(t-2)square dt By partial fraction 3t-2/(t-2)square=A/(t-2) +B/(t-2)square .................eq1 By comparing the coefficients We get A=3 and B=4 Substitute in eq1 And integrate it Then....... We get 3log[ t-2 ]-4/t-2 Substitute Sinx =t Answer ::::: 3log [sinx-2 ] -4/sinx-2
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