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def LS T\ ARG(L1) : L …

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def LS T\ ARG(L1) : L 2=L1 L * 3 = [0, 0, 0, 0] print (^ prime prime L2->",L2) print("L3->",L3) j = 0 L1. append(51) for i in range ( len (L1)) : if L1[i]%5==0: L * 2[j] =L2[j]^ * L2[j] L * 3[j] =L2[j]\%5 j +=1 print (^ prime prime L 1->^ prime prime ,L1) print (^ prime prime L 2->",L2) print (^ prime prime L 3->",L3) L * 1 = [10, 15, 20] LS T\ ARG(L1) print (^ prime prime L1 ^ prime prime ,L1)

Posted by Jaya Lakshmi 11 months, 4 weeks ago

CBSE > Class 12 > Computer Science

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CBSE > Class 12 > Computer Science